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		<title>Continuity of the infimum</title>
		<link>http://williewong.wordpress.com/2011/11/01/continuity-of-the-infimum/</link>
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		<pubDate>Tue, 01 Nov 2011 14:09:24 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[classical analysis]]></category>
		<category><![CDATA[Life of a mathematician]]></category>
		<category><![CDATA[Maths]]></category>
		<category><![CDATA[Require introductory level university maths]]></category>

		<guid isPermaLink="false">http://williewong.wordpress.com/?p=784</guid>
		<description><![CDATA[Just realised (two seeks ago, but only gotten around to finish this blog posting now) that an argument used to prove a proposition in a project I am working on is wrong. After reducing the problem to its core I found that it is something quite elementary. So today&#8217;s post would be of a different [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=784&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Just realised (two seeks ago, but only gotten around to finish this blog posting now) that an argument used to prove a proposition in a project I am working on is wrong. After reducing the problem to its core I found that it is something quite elementary. So today&#8217;s post would be of a different flavour from the ones of recent past. </p>
<p><strong>Question</strong> Let <img src='http://s0.wp.com/latex.php?latex=X%2CY&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X,Y' title='X,Y' class='latex' /> be topological spaces. Let <img src='http://s0.wp.com/latex.php?latex=f%3AX%5Ctimes+Y%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f:X&#92;times Y&#92;to&#92;mathbb{R}' title='f:X&#92;times Y&#92;to&#92;mathbb{R}' class='latex' /> be a bounded, continuous function. Is the function <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3D+%5Cinf_%7By%5Cin+Y%7Df%28x%2Cy%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) = &#92;inf_{y&#92;in Y}f(x,y)' title='g(x) = &#92;inf_{y&#92;in Y}f(x,y)' class='latex' /> continuous? </p>
<p>Intuitively, one may be tempted to say &#8220;yes&#8221;. Indeed, there are plenty of examples where the answer is in the positive. The simplest one is when we can replace the infimum with the minimum:</p>
<p><strong>Example</strong> Let the space <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> be a finite set with the discrete topology. Then <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3D+%5Cmin_%7By%5Cin+Y%7D+f%28x%2Cy%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) = &#92;min_{y&#92;in Y} f(x,y)' title='g(x) = &#92;min_{y&#92;in Y} f(x,y)' class='latex' /> is continuous.<br />
<em>Proof</em> left as exercise.</p>
<p>But in fact, the answer to the question is &#8220;No&#8221;. Here&#8217;s a counterexample:</p>
<p><strong>Example</strong> Let <img src='http://s0.wp.com/latex.php?latex=X+%3D+Y+%3D+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X = Y = &#92;mathbb{R}' title='X = Y = &#92;mathbb{R}' class='latex' /> with the standard topology. Define </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+f%28x%2Cy%29+%3D+%5Cbegin%7Bcases%7D+1+%26+x+%3E+0+%5C%5C+0+%26+x+%3C+-e%5E%7By%7D+%5C%5C+1+%2B+x+e%5E%7B-y%7D+%26+x%5Cin+%5B-e%5E%7By%7D%2C0%5D++%5Cend%7Bcases%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle f(x,y) = &#92;begin{cases} 1 &amp; x &gt; 0 &#92;&#92; 0 &amp; x &lt; -e^{y} &#92;&#92; 1 + x e^{-y} &amp; x&#92;in [-e^{y},0]  &#92;end{cases}' title='&#92;displaystyle f(x,y) = &#92;begin{cases} 1 &amp; x &gt; 0 &#92;&#92; 0 &amp; x &lt; -e^{y} &#92;&#92; 1 + x e^{-y} &amp; x&#92;in [-e^{y},0]  &#92;end{cases}' class='latex' />
</p></blockquote>
<p>which is clearly continuous. But the infimum function <img src='http://s0.wp.com/latex.php?latex=g%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x)' title='g(x)' class='latex' /> is roughly the Heaviside function: <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3D+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) = 1' title='g(x) = 1' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=x+%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x &#92;geq 0' title='x &#92;geq 0' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) = 0' title='g(x) = 0' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=x+%3C+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x &lt; 0' title='x &lt; 0' class='latex' />. </p>
<p>So what is it about the first example that makes the argument work? What is the different between the minimum and the infimum? A naive guess maybe that in the finite case, we are taking a minimum, and therefore the infimum is attained. This guess is not unreasonable: there are a lot of arguments in analysis where when the infimum can be assumed to be attained, the problem becomes a lot easier (when we are then allowed to deal with a minimizer instead of a minimizing sequence). But sadly that is not (entirely) the case here: for every <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x_0' title='x_0' class='latex' />, we can certainly find a <img src='http://s0.wp.com/latex.php?latex=y_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y_0' title='y_0' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=f%28x_0%2Cy_0%29+%3D+g%28x_0%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f(x_0,y_0) = g(x_0)' title='f(x_0,y_0) = g(x_0)' class='latex' />. So attaining the infimum point-wise is not enough. </p>
<p>What we need, here, is <strong>compactness</strong>. In fact, we have the following </p>
<p><strong>Theorem</strong> If <img src='http://s0.wp.com/latex.php?latex=X%2CY&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X,Y' title='X,Y' class='latex' /> are topological spaces and <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> is compact. Then for any continuous <img src='http://s0.wp.com/latex.php?latex=f%3AX%5Ctimes+Y%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f:X&#92;times Y&#92;to&#92;mathbb{R}' title='f:X&#92;times Y&#92;to&#92;mathbb{R}' class='latex' />, the function <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3A%3D+%5Cinf_%7By%5Cin+Y%7D+f%28x%2Cy%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) := &#92;inf_{y&#92;in Y} f(x,y)' title='g(x) := &#92;inf_{y&#92;in Y} f(x,y)' class='latex' /> is well-defined and continuous.</p>
<p><em>Proof</em> usually proceeds in three parts. That <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3E+-%5Cinfty&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) &gt; -&#92;infty' title='g(x) &gt; -&#92;infty' class='latex' /> follows from the fact that for any fixed <img src='http://s0.wp.com/latex.php?latex=x%5Cin+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x&#92;in X' title='x&#92;in X' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=f%28x%2C%5Ccdot%29%3AY%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f(x,&#92;cdot):Y&#92;to&#92;mathbb{R}' title='f(x,&#92;cdot):Y&#92;to&#92;mathbb{R}' class='latex' /> is a continuous function defined on a compact space, and hence is bounded (in fact the infimum is attained). Then using that the sets <img src='http://s0.wp.com/latex.php?latex=%28-%5Cinfty%2Ca%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(-&#92;infty,a)' title='(-&#92;infty,a)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%28b%2C%5Cinfty%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(b,&#92;infty)' title='(b,&#92;infty)' class='latex' /> form a subbase for the topology of <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbb{R}' title='&#92;mathbb{R}' class='latex' />, it suffices to check that <img src='http://s0.wp.com/latex.php?latex=g%5E%7B-1%7D%28%28-%5Cinfty%2Ca%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g^{-1}((-&#92;infty,a))' title='g^{-1}((-&#92;infty,a))' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=g%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g^{-1}((b,&#92;infty))' title='g^{-1}((b,&#92;infty))' class='latex' /> are open. </p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=%5Cpi_X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi_X' title='&#92;pi_X' class='latex' /> be the canonical projection <img src='http://s0.wp.com/latex.php?latex=%5Cpi_X%3AX%5Ctimes+Y%5Cto+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi_X:X&#92;times Y&#92;to X' title='&#92;pi_X:X&#92;times Y&#92;to X' class='latex' />, which we recall is continuous and open. It is easy to see that <img src='http://s0.wp.com/latex.php?latex=g%5E%7B-1%7D%28%28-%5Cinfty%2Ca%29%29+%3D+%5Cpi_X+%5Ccirc+f%5E%7B-1%7D%28%28-%5Cinfty%2Ca%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g^{-1}((-&#92;infty,a)) = &#92;pi_X &#92;circ f^{-1}((-&#92;infty,a))' title='g^{-1}((-&#92;infty,a)) = &#92;pi_X &#92;circ f^{-1}((-&#92;infty,a))' class='latex' />. So continuity of <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f' title='f' class='latex' /> implies that this set is open. (Note that this part does not depend on compactness of <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' />. In fact, a minor modification of this proof shows that for any family of upper semicontinuous functions <img src='http://s0.wp.com/latex.php?latex=%5C%7Bf_c%5C%7D_C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{f_c&#92;}_C' title='&#92;{f_c&#92;}_C' class='latex' />, the pointwise infimum <img src='http://s0.wp.com/latex.php?latex=%5Cinf_%7Bc%5Cin+C%7D+f_c&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;inf_{c&#92;in C} f_c' title='&#92;inf_{c&#92;in C} f_c' class='latex' /> is also upper semicontinuous, a fact that is very useful in convex analysis. And indeed, the counterexample function given above is upper semicontinuous.)</p>
<p>It is in this last part, showing that <img src='http://s0.wp.com/latex.php?latex=g%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g^{-1}((b,&#92;infty))' title='g^{-1}((b,&#92;infty))' class='latex' /> is open, that compactness is crucially used. Observe that <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3E+b+%5Cimplies+f%28x%2Cy%29+%3E+b%7E+%5Cforall+y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) &gt; b &#92;implies f(x,y) &gt; b~ &#92;forall y' title='g(x) &gt; b &#92;implies f(x,y) &gt; b~ &#92;forall y' class='latex' />. In other words <img src='http://s0.wp.com/latex.php?latex=g%28x%29+%3E+b+%5Cimplies+%5Cforall+y%2C+%28x%2Cy%29+%5Cin+f%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(x) &gt; b &#92;implies &#92;forall y, (x,y) &#92;in f^{-1}((b,&#92;infty))' title='g(x) &gt; b &#92;implies &#92;forall y, (x,y) &#92;in f^{-1}((b,&#92;infty))' class='latex' /> an open set. This in particular implies that <img src='http://s0.wp.com/latex.php?latex=%5Cforall+x%5Cin+g%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29+%5Cforall+y%5Cin+Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;forall x&#92;in g^{-1}((b,&#92;infty)) &#92;forall y&#92;in Y' title='&#92;forall x&#92;in g^{-1}((b,&#92;infty)) &#92;forall y&#92;in Y' class='latex' /> there exists a &#8220;box&#8221; neighborhood <img src='http://s0.wp.com/latex.php?latex=U_%7B%28x%2Cy%29%7D%5Ctimes+V_%7B%28x%2Cy%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='U_{(x,y)}&#92;times V_{(x,y)}' title='U_{(x,y)}&#92;times V_{(x,y)}' class='latex' /> contained in <img src='http://s0.wp.com/latex.php?latex=f%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f^{-1}((b,&#92;infty))' title='f^{-1}((b,&#92;infty))' class='latex' />. Now using compactness of <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' />, a finite subset <img src='http://s0.wp.com/latex.php?latex=%5C%7B%28x%2Cy_i%29%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{(x,y_i)&#92;}' title='&#92;{(x,y_i)&#92;}' class='latex' /> of all these boxes cover <img src='http://s0.wp.com/latex.php?latex=%5C%7Bx%5C%7D%5Ctimes+Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{x&#92;}&#92;times Y' title='&#92;{x&#92;}&#92;times Y' class='latex' />. And in particular we have</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5C%7Bx%5C%7D%5Ctimes+Y+%5Csubset+%5Cleft%28%5Ccap_%7Bi+%3D+1%7D%5Ek+U_%7B%28x%2Cy_i%29%7D%5Cright%29%5Ctimes+Y+%5Csubset+f%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;{x&#92;}&#92;times Y &#92;subset &#92;left(&#92;cap_{i = 1}^k U_{(x,y_i)}&#92;right)&#92;times Y &#92;subset f^{-1}((b,&#92;infty))' title='&#92;displaystyle &#92;{x&#92;}&#92;times Y &#92;subset &#92;left(&#92;cap_{i = 1}^k U_{(x,y_i)}&#92;right)&#92;times Y &#92;subset f^{-1}((b,&#92;infty))' class='latex' />
</p></blockquote>
<p>and hence <img src='http://s0.wp.com/latex.php?latex=g%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29+%3D+%5Ccup_%7Bx%5Cin+g%5E%7B-1%7D%28%28b%2C%5Cinfty%29%29%7D+%5Ccap_%7Bi+%3D+1%7D%5E%7Bk%28x%29%7D+U_%7Bx%2Cy_i%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g^{-1}((b,&#92;infty)) = &#92;cup_{x&#92;in g^{-1}((b,&#92;infty))} &#92;cap_{i = 1}^{k(x)} U_{x,y_i}' title='g^{-1}((b,&#92;infty)) = &#92;cup_{x&#92;in g^{-1}((b,&#92;infty))} &#92;cap_{i = 1}^{k(x)} U_{x,y_i}' class='latex' /> is open. Q.E.D.</p>
<p>One question we may ask is how <em>sharp</em> is the requirement that <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> is compact. As with most things in topology, counterexamples abound. </p>
<p><strong>Example</strong> Let <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> be any uncountably infinite set equipped with the <a href="http://en.wikipedia.org/wiki/Cocountable_topology">co-countable topology</a>. That is, the collection of open subsets are precisely the empty set and all subsets whose complement is countable. The two interesting properties of this topology are (a) <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> is not compact and (b) <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> is <a href="http://en.wikipedia.org/wiki/Hyperconnected_space">hyperconnected</a>. (a) is easy to see: let <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C' title='C' class='latex' /> be some countably infinite subset of <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' />. For each <img src='http://s0.wp.com/latex.php?latex=c%5Cin+C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='c&#92;in C' title='c&#92;in C' class='latex' /> let <img src='http://s0.wp.com/latex.php?latex=U_c+%3D+%5C%7Bc%5C%7D%5Ccup+%28Y%5Csetminus+C%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='U_c = &#92;{c&#92;}&#92;cup (Y&#92;setminus C)' title='U_c = &#92;{c&#92;}&#92;cup (Y&#92;setminus C)' class='latex' />. This forms an open cover with not finite sub-cover.  Hyperconnected spaces are, roughly speaking, spaces in which all open nonempty sets are &#8220;large&#8221;, in the sense that they mutually overlap a lot. In particular, a continuous map from a hyperconnected space to a Hausdorff space must be constant. In our case we can see this directly: suppose <img src='http://s0.wp.com/latex.php?latex=h%3AY%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='h:Y&#92;to &#92;mathbb{R}' title='h:Y&#92;to &#92;mathbb{R}' class='latex' /> is a continuous map. Fix <img src='http://s0.wp.com/latex.php?latex=y_1%2Cy_2%5Cin+Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y_1,y_2&#92;in Y' title='y_1,y_2&#92;in Y' class='latex' />. Let <img src='http://s0.wp.com/latex.php?latex=N_%7B1%2C2%7D%5Csubset+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='N_{1,2}&#92;subset &#92;mathbb{R}' title='N_{1,2}&#92;subset &#92;mathbb{R}' class='latex' /> be open neighborhoods of <img src='http://s0.wp.com/latex.php?latex=f%28y_%7B1%2C2%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f(y_{1,2})' title='f(y_{1,2})' class='latex' />. Since <img src='http://s0.wp.com/latex.php?latex=h&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='h' title='h' class='latex' /> is continuous, <img src='http://s0.wp.com/latex.php?latex=h%5E%7B-1%7D%28N_1%29%5Ccap+h%5E%7B-1%7D%28N_2%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='h^{-1}(N_1)&#92;cap h^{-1}(N_2)' title='h^{-1}(N_1)&#92;cap h^{-1}(N_2)' class='latex' /> is open and non-empty (by the co-countable assumption). Therefore <img src='http://s0.wp.com/latex.php?latex=N_1%5Ccap+N_2%5Cneq+%5Cemptyset&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='N_1&#92;cap N_2&#92;neq &#92;emptyset' title='N_1&#92;cap N_2&#92;neq &#92;emptyset' class='latex' /> for any pairs of neighborhoods. Since <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbb{R}' title='&#92;mathbb{R}' class='latex' /> is Hausdorff, this forces <img src='http://s0.wp.com/latex.php?latex=h&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='h' title='h' class='latex' /> to be the constant map. This implies that for any topological space <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' />, a continuous function <img src='http://s0.wp.com/latex.php?latex=f%3AX%5Ctimes+Y%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f:X&#92;times Y&#92;to&#92;mathbb{R}' title='f:X&#92;times Y&#92;to&#92;mathbb{R}' class='latex' /> is constant along <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' />, and hence for any <img src='http://s0.wp.com/latex.php?latex=y_0%5Cin+Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y_0&#92;in Y' title='y_0&#92;in Y' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cinf_%7By%5Cin+Y%7D+f%28x%2Cy%29+%3D%3A+g%28x%29+%3D+f%28x%2Cy_0%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;inf_{y&#92;in Y} f(x,y) =: g(x) = f(x,y_0)' title='&#92;inf_{y&#92;in Y} f(x,y) =: g(x) = f(x,y_0)' class='latex' /> is continuous. </p>
<p>One can try to introduce various regularity/separation assumptions on the spaces <img src='http://s0.wp.com/latex.php?latex=X%2CY&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X,Y' title='X,Y' class='latex' /> to see at what level compactness becomes a crucial requirement. As an analyst, however, I really only care about topological manifolds. In which case the second counterexample up top can be readily used. We can slightly weaken the assumptions and still prove the following partial converse in essentially the same way.</p>
<p><strong>Theorem</strong> Let <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> be Tychonoff, connected, and first countable, such that <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> contains a non-trivial open subset whose closure is not the entire space; and let <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> be paracompact, Lindelof. Then if <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> is noncompact, there exists a continuous function <img src='http://s0.wp.com/latex.php?latex=f%3AX%5Ctimes+Y%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f:X&#92;times Y&#92;to&#92;mathbb{R}' title='f:X&#92;times Y&#92;to&#92;mathbb{R}' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Cinf_%7By%5Cin+Y%7Df%3AX%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;inf_{y&#92;in Y}f:X&#92;to &#92;mathbb{R}' title='&#92;inf_{y&#92;in Y}f:X&#92;to &#92;mathbb{R}' class='latex' /> is not continuous. </p>
<p><strong>Remark</strong> Connected (nontrivial) topological manifolds automatically satisfy the conditions on <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' /> except for non-compactness. The conditions given are not necessary for the theorem to hold; but they more or less capture the topological properties used in the construction of the second counterexample above. </p>
<p><strong>Remark</strong> If <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> is such that every open set&#8217;s closure is the entire space, we must have that it is hyperconnected (let <img src='http://s0.wp.com/latex.php?latex=C%5Csubset+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C&#92;subset X' title='C&#92;subset X' class='latex' /> be a closed set. Suppose <img src='http://s0.wp.com/latex.php?latex=D%5Csubset+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='D&#92;subset X' title='D&#92;subset X' class='latex' /> is another closed set such that <img src='http://s0.wp.com/latex.php?latex=C%5Ccup+D+%3D+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C&#92;cup D = X' title='C&#92;cup D = X' class='latex' />. Then <img src='http://s0.wp.com/latex.php?latex=C%5Csubset+D%5Ec&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C&#92;subset D^c' title='C&#92;subset D^c' class='latex' /> and vice versa, but <img src='http://s0.wp.com/latex.php?latex=D%5Ec&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='D^c' title='D^c' class='latex' /> is open, so <img src='http://s0.wp.com/latex.php?latex=C+%3D+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C = X' title='C = X' class='latex' />. Hence <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> cannot be written as the union of two proper closed subsets). And if it is Tychonoff, then <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> is either the empty-set or the one-point set. </p>
<p><strong>Lemma</strong> For a paracompact Lindelof space that is noncompact, there exists a countably infinite open cover <img src='http://s0.wp.com/latex.php?latex=%5C%7BU_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{U_k&#92;}' title='&#92;{U_k&#92;}' class='latex' /> and a sequence of points <img src='http://s0.wp.com/latex.php?latex=y_k+%5Cin+U_k&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y_k &#92;in U_k' title='y_k &#92;in U_k' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5C%7By_k%5C%7D%5Ccap+U_j+%3D+%5Cemptyset&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{y_k&#92;}&#92;cap U_j = &#92;emptyset' title='&#92;{y_k&#92;}&#92;cap U_j = &#92;emptyset' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=j%5Cneq+k&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j&#92;neq k' title='j&#92;neq k' class='latex' />. </p>
<p><em>Proof</em>: By noncompactness, there exists an open cover that is infinite. By Lindelof, this open cover can be assumed to be countable, which we enumerate by <img src='http://s0.wp.com/latex.php?latex=%5C%7BV_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{V_k&#92;}' title='&#92;{V_k&#92;}' class='latex' /> and assume WLOG that <img src='http://s0.wp.com/latex.php?latex=%5Cforall+k%2C+V_k+%5Csetminus+%5Ccup_%7Bj+%3D1%7D%5E%7Bk-1%7D+V_j+%5Cneq+%5Cemptyset&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;forall k, V_k &#92;setminus &#92;cup_{j =1}^{k-1} V_j &#92;neq &#92;emptyset' title='&#92;forall k, V_k &#92;setminus &#92;cup_{j =1}^{k-1} V_j &#92;neq &#92;emptyset' class='latex' />. Define <img src='http://s0.wp.com/latex.php?latex=%5C%7BU_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{U_k&#92;}' title='&#92;{U_k&#92;}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5C%7By_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{y_k&#92;}' title='&#92;{y_k&#92;}' class='latex' /> inductively by: <img src='http://s0.wp.com/latex.php?latex=U_k+%3D+V_k+%5Csetminus+%5Ccup_%7Bj+%3D+1%7D%5E%7Bk-1%7D+%5C%7B+y_j%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='U_k = V_k &#92;setminus &#92;cup_{j = 1}^{k-1} &#92;{ y_j&#92;}' title='U_k = V_k &#92;setminus &#92;cup_{j = 1}^{k-1} &#92;{ y_j&#92;}' class='latex' /> and choose <img src='http://s0.wp.com/latex.php?latex=y_k+%5Cin+U_k+%5Csetminus+%5Ccup_%7Bj%3D1%7D%5E%7Bk-1%7DU_j&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y_k &#92;in U_k &#92;setminus &#92;cup_{j=1}^{k-1}U_j' title='y_k &#92;in U_k &#92;setminus &#92;cup_{j=1}^{k-1}U_j' class='latex' />. </p>
<p><em>Proof of theorem</em>: We first construct a sequence of continuous functions on <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' />. Let <img src='http://s0.wp.com/latex.php?latex=G%5Csubset+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='G&#92;subset X' title='G&#92;subset X' class='latex' /> be a non-empty open set such that its closure-complement <img src='http://s0.wp.com/latex.php?latex=H+%3D+%28%5Cbar%7BG%7D%29%5Ec&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='H = (&#92;bar{G})^c' title='H = (&#92;bar{G})^c' class='latex' /> is a non-empty open set (<img src='http://s0.wp.com/latex.php?latex=G&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='G' title='G' class='latex' /> exists by assumption). By connectedness <img src='http://s0.wp.com/latex.php?latex=%5Cbar%7BG%7D%5Ccap+%5Cbar%7BH%7D+%5Cneq+%5Cemptyset&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;bar{G}&#92;cap &#92;bar{H} &#92;neq &#92;emptyset' title='&#92;bar{G}&#92;cap &#92;bar{H} &#92;neq &#92;emptyset' class='latex' />, so we can pick <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x_0' title='x_0' class='latex' /> in the intersection. Let <img src='http://s0.wp.com/latex.php?latex=%5C%7Bx_j%5C%7D%5Csubset+H&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{x_j&#92;}&#92;subset H' title='&#92;{x_j&#92;}&#92;subset H' class='latex' /> be a sequence of points converging to <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x_0' title='x_0' class='latex' />, which exists by first countability. Using Tychonoff, we can get a sequence of continuous functions <img src='http://s0.wp.com/latex.php?latex=f_j&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_j' title='f_j' class='latex' />on <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=f_j%7C_%7B%5Cbar%7BG%7D%7D+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_j|_{&#92;bar{G}} = 0' title='f_j|_{&#92;bar{G}} = 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=f_j%28x_j%29+%3D+-1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_j(x_j) = -1' title='f_j(x_j) = -1' class='latex' />. </p>
<p>On <img src='http://s0.wp.com/latex.php?latex=Y&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Y' title='Y' class='latex' />, choose an open cover <img src='http://s0.wp.com/latex.php?latex=%5C%7BU_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{U_k&#92;}' title='&#92;{U_k&#92;}' class='latex' /> and  points <img src='http://s0.wp.com/latex.php?latex=%5C%7By_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{y_k&#92;}' title='&#92;{y_k&#92;}' class='latex' /> per the previous Lemma. By paracompactness we have a partition of unity <img src='http://s0.wp.com/latex.php?latex=%5C%7B%5Cpsi_k%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;{&#92;psi_k&#92;}' title='&#92;{&#92;psi_k&#92;}' class='latex' /> subordinate to <img src='http://s0.wp.com/latex.php?latex=U_k&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='U_k' title='U_k' class='latex' />, and by the conclusion of the Lemma we have that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi_k%28y_k%29+%3D+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi_k(y_k) = 1' title='&#92;psi_k(y_k) = 1' class='latex' />. Now we define the function</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+f%28x%2Cy%29+%3D+%5Csum_%7Bk%7D+f_k%28x%29%5Cpsi_k%28y%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle f(x,y) = &#92;sum_{k} f_k(x)&#92;psi_k(y)' title='&#92;displaystyle f(x,y) = &#92;sum_{k} f_k(x)&#92;psi_k(y)' class='latex' />
</p></blockquote>
<p>which is continuous, and such that <img src='http://s0.wp.com/latex.php?latex=f%7C_%7B%5Cbar%7BG%7D%5Ctimes+Y%7D+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f|_{&#92;bar{G}&#92;times Y} = 0' title='f|_{&#92;bar{G}&#92;times Y} = 0' class='latex' />. But by construction <img src='http://s0.wp.com/latex.php?latex=%5Cinf_%7By%5Cin+Y%7Df%28x%2Cy%29+%5Cleq+f%28x_k%2Cy_k%29+%3D+f_k%28x_k%29+%3D+-1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;inf_{y&#92;in Y}f(x,y) &#92;leq f(x_k,y_k) = f_k(x_k) = -1' title='&#92;inf_{y&#92;in Y}f(x,y) &#92;leq f(x_k,y_k) = f_k(x_k) = -1' class='latex' />, which combined with the fact that <img src='http://s0.wp.com/latex.php?latex=x_k+%5Cto+x_0+%5Cin+%5Cbar%7BG%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x_k &#92;to x_0 &#92;in &#92;bar{G}' title='x_k &#92;to x_0 &#92;in &#92;bar{G}' class='latex' /> shows the desired result. q.e.d. </p>
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			<media:title type="html">Willie</media:title>
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		<title>Gauge invariance, geometrically</title>
		<link>http://williewong.wordpress.com/2011/09/30/gauge-invariance-geometrically/</link>
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		<pubDate>Fri, 30 Sep 2011 15:34:43 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[differential/pseudo-Riemannian geometry]]></category>
		<category><![CDATA[general relativity]]></category>
		<category><![CDATA[Maths]]></category>
		<category><![CDATA[partial differential equations]]></category>
		<category><![CDATA[Requires upper level university maths]]></category>

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		<description><![CDATA[A somewhat convoluted chain of events led me to think about the geometric description of partial differential equations. And a question I asked myself this morning was Question What is the meaning of gauge invariance in the jet-bundle treatment of partial differential equations? The answer, actually, is quite simple. Review of geometric formulation PDE We [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=773&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A somewhat convoluted chain of events led me to think about the <em>geometric</em> description of partial differential equations. And a question I asked myself this morning was</p>
<blockquote><p><strong>Question</strong><br />
What is the meaning of gauge invariance in the jet-bundle treatment of partial differential equations?
</p></blockquote>
<p>The answer, actually, is quite simple. </p>
<p><strong>Review of geometric formulation PDE</strong><br />
We consider here abstract PDEs formulated geometrically. All objects considered will be smooth. For more about the formal framework presented here, a good reference is H. Goldschmidt, &#8220;Integrability criteria for systems of nonlinear partial differential equations&#8221;, JDG (1967) 1:269&#8211;307. </p>
<p>A quick review: the background manifold <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> is assumed (here we take a slightly more restrictive point of view) to be a connected smooth manifold. The configuration space <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}' title='&#92;mathcal{C}' class='latex' /> is defined to be a fibred manifold <img src='http://s0.wp.com/latex.php?latex=p%3A%5Cmathcal%7BC%7D%5Cto+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p:&#92;mathcal{C}&#92;to X' title='p:&#92;mathcal{C}&#92;to X' class='latex' />. By <img src='http://s0.wp.com/latex.php?latex=J%5Er%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^r&#92;mathcal{C}' title='J^r&#92;mathcal{C}' class='latex' /> we refer to the fibred manifold of <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' />-jets of <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}' title='&#92;mathcal{C}' class='latex' />, whose projection <img src='http://s0.wp.com/latex.php?latex=p%5Er+%3D+%5Cpi%5Er_0+%5Ccirc+p&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p^r = &#92;pi^r_0 &#92;circ p' title='p^r = &#92;pi^r_0 &#92;circ p' class='latex' /> where for <img src='http://s0.wp.com/latex.php?latex=r+%3E+s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r &gt; s' title='r &gt; s' class='latex' /> we use <img src='http://s0.wp.com/latex.php?latex=%5Cpi%5Er_s%3A+J%5Er%5Cmathcal%7BC%7D%5Cto+J%5Es%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi^r_s: J^r&#92;mathcal{C}&#92;to J^s&#92;mathcal{C}' title='&#92;pi^r_s: J^r&#92;mathcal{C}&#92;to J^s&#92;mathcal{C}' class='latex' /> for the canonical projection. </p>
<p>A <em>field</em> is a (smooth) section <img src='http://s0.wp.com/latex.php?latex=%5Cphi+%5Csubset+%5CGamma+%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi &#92;subset &#92;Gamma &#92;mathcal{C}' title='&#92;phi &#92;subset &#92;Gamma &#92;mathcal{C}' class='latex' />. A simple example that capture most of the usual cases: if we are studying mappings between manifolds <img src='http://s0.wp.com/latex.php?latex=%5Cphi%3A+X%5Cto+N&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi: X&#92;to N' title='&#92;phi: X&#92;to N' class='latex' />, then we take <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D+%3D+N%5Ctimes+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C} = N&#92;times X' title='&#92;mathcal{C} = N&#92;times X' class='latex' /> the trivial fibre bundle. The <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='s' title='s' class='latex' />-jet operator naturally sends <img src='http://s0.wp.com/latex.php?latex=j%5Es%3A+%5CGamma%5Cmathcal%7BC%7D+%5Cni+%5Cphi+%5Cmapsto+j%5Es%5Cphi+%5Cin+%5CGamma+J%5Er%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j^s: &#92;Gamma&#92;mathcal{C} &#92;ni &#92;phi &#92;mapsto j^s&#92;phi &#92;in &#92;Gamma J^r&#92;mathcal{C}' title='j^s: &#92;Gamma&#92;mathcal{C} &#92;ni &#92;phi &#92;mapsto j^s&#92;phi &#92;in &#92;Gamma J^r&#92;mathcal{C}' class='latex' />. </p>
<p>A partial differential equation of order <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> is defined to be a fibred submanifold <img src='http://s0.wp.com/latex.php?latex=J%5Er%5Cmathcal%7BC%7D+%5Csupset+R%5Er+%5Cto+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^r&#92;mathcal{C} &#92;supset R^r &#92;to X' title='J^r&#92;mathcal{C} &#92;supset R^r &#92;to X' class='latex' />. A field is said to solve the PDE if <img src='http://s0.wp.com/latex.php?latex=j%5Er%5Cphi+%5Csubset+R%5Er&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j^r&#92;phi &#92;subset R^r' title='j^r&#92;phi &#92;subset R^r' class='latex' />. </p>
<p>In the usual case of systems of PDEs on Euclidean space, <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' /> is taken to be <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D%5Ed&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbb{R}^d' title='&#92;mathbb{R}^d' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D+%3D+%5Cmathbb%7BR%7D%5En%5Ctimes+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C} = &#92;mathbb{R}^n&#92;times X' title='&#92;mathcal{C} = &#92;mathbb{R}^n&#92;times X' class='latex' /> the trivial vector bundle. A system of <img src='http://s0.wp.com/latex.php?latex=m&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='m' title='m' class='latex' /> PDEs of order <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> is usually taken to be <img src='http://s0.wp.com/latex.php?latex=F%28x%2C%5Cphi%2C+%5Cpartial%5Cphi%2C+%5Cpartial%5E2%5Cphi%2C+%5Cldots%2C+%5Cpartial%5Er%5Cphi%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F(x,&#92;phi, &#92;partial&#92;phi, &#92;partial^2&#92;phi, &#92;ldots, &#92;partial^r&#92;phi) = 0' title='F(x,&#92;phi, &#92;partial&#92;phi, &#92;partial^2&#92;phi, &#92;ldots, &#92;partial^r&#92;phi) = 0' class='latex' /> where</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+F%3A+X%5Ctimes+%5Cmathbb%7BR%7D%5En+%5Ctimes+%5Cmathbb%7BR%7D%5E%7Bdn%7D+%5Ctimes+%5Cmathbb%7BR%7D%5E%7B%5Cfrac%7B1%7D%7B2%7Dd%28d%2B1%29n%7D+%5Ctimes+%5Ccdots+%5Ctimes+%5Cmathbb%7BR%7D%5E%7B%7Bd%2Br-1+%5Cchoose+r%7D+n%7D+%5Cto+%5Cmathbb%7BR%7D%5Em&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle F: X&#92;times &#92;mathbb{R}^n &#92;times &#92;mathbb{R}^{dn} &#92;times &#92;mathbb{R}^{&#92;frac{1}{2}d(d+1)n} &#92;times &#92;cdots &#92;times &#92;mathbb{R}^{{d+r-1 &#92;choose r} n} &#92;to &#92;mathbb{R}^m' title='&#92;displaystyle F: X&#92;times &#92;mathbb{R}^n &#92;times &#92;mathbb{R}^{dn} &#92;times &#92;mathbb{R}^{&#92;frac{1}{2}d(d+1)n} &#92;times &#92;cdots &#92;times &#92;mathbb{R}^{{d+r-1 &#92;choose r} n} &#92;to &#92;mathbb{R}^m' class='latex' />
</p></blockquote>
<p>is some function. We note that the domain of <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> can be identified in this case with <img src='http://s0.wp.com/latex.php?latex=J%5Er%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^r&#92;mathcal{C}' title='J^r&#92;mathcal{C}' class='latex' />, We can then extend <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BF%7D%3A+J%5Er%5Cmathcal%7BC%7D+%5Cni+c+%5Cmapsto+%28F%28c%29%2Cp%5Er%28c%29%29+%5Cin+%5Cmathbb%7BR%7D%5Em%5Ctimes+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{F}: J^r&#92;mathcal{C} &#92;ni c &#92;mapsto (F(c),p^r(c)) &#92;in &#92;mathbb{R}^m&#92;times X' title='&#92;tilde{F}: J^r&#92;mathcal{C} &#92;ni c &#92;mapsto (F(c),p^r(c)) &#92;in &#92;mathbb{R}^m&#92;times X' class='latex' /> a fibre bundle morphism. </p>
<p>If we assume that <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BF%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{F}' title='&#92;tilde{F}' class='latex' /> has constant rank, then <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BF%7D%5E%7B-1%7D%280%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{F}^{-1}(0)' title='&#92;tilde{F}^{-1}(0)' class='latex' /> is a fibred submanifold of <img src='http://s0.wp.com/latex.php?latex=J%5Er%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^r&#92;mathcal{C}' title='J^r&#92;mathcal{C}' class='latex' />, and this is our differential equation. </p>
<p><strong>Gauge invariance</strong><br />
In this frame work, the gauge invariance of a partial differential equation relative to certain symmetry groups can be captured by requiring <img src='http://s0.wp.com/latex.php?latex=R%5Er&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='R^r' title='R^r' class='latex' /> be an invariant submanifold. </p>
<p>More precisely, we take</p>
<blockquote><p><strong>Definition</strong><br />
A <em>symmetry/gauge group</em> <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BG%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{G}' title='&#92;mathcal{G}' class='latex' /> is a subgroup of <img src='http://s0.wp.com/latex.php?latex=%5Cmathrm%7BDiff%7D%28%5Cmathcal%7BC%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathrm{Diff}(&#92;mathcal{C})' title='&#92;mathrm{Diff}(&#92;mathcal{C})' class='latex' />, with the property that for any <img src='http://s0.wp.com/latex.php?latex=g%5Cin%5Cmathcal%7BG%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g&#92;in&#92;mathcal{G}' title='g&#92;in&#92;mathcal{G}' class='latex' />, there exists a <img src='http://s0.wp.com/latex.php?latex=g%27%5Cin+%5Cmathrm%7BDiff%7D%28X%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g&#039;&#92;in &#92;mathrm{Diff}(X)' title='g&#039;&#92;in &#92;mathrm{Diff}(X)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=p%5Ccirc+g+%3D+g%27+%5Ccirc+p&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p&#92;circ g = g&#039; &#92;circ p' title='p&#92;circ g = g&#039; &#92;circ p' class='latex' />.
</p></blockquote>
<p>It is important we are looking at the diffeomorphism group for <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}' title='&#92;mathcal{C}' class='latex' />, not <img src='http://s0.wp.com/latex.php?latex=J%5Er%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^r&#92;mathcal{C}' title='J^r&#92;mathcal{C}' class='latex' />. In general diffeomorphisms of <img src='http://s0.wp.com/latex.php?latex=J%5Er%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^r&#92;mathcal{C}' title='J^r&#92;mathcal{C}' class='latex' /> will not preserve holonomy for sections of the form <img src='http://s0.wp.com/latex.php?latex=j%5Er%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j^r&#92;phi' title='j^r&#92;phi' class='latex' />, a condition that is essential for solving PDEs. The condition that the symmetry operation &#8220;commutes with projections&#8221; is to ensure that <img src='http://s0.wp.com/latex.php?latex=g%3A%5CGamma%5Cmathcal%7BC%7D%5Cto%5CGamma%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g:&#92;Gamma&#92;mathcal{C}&#92;to&#92;Gamma&#92;mathcal{C}' title='g:&#92;Gamma&#92;mathcal{C}&#92;to&#92;Gamma&#92;mathcal{C}' class='latex' />, which in particular guarantees that <img src='http://s0.wp.com/latex.php?latex=g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g' title='g' class='latex' /> extends to a diffeomorphism of <img src='http://s0.wp.com/latex.php?latex=J%5ErC&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='J^rC' title='J^rC' class='latex' /> with itself that commutes with projections. </p>
<p>From this point of view, a (system of) partial differential equation(s) <img src='http://s0.wp.com/latex.php?latex=R%5Er&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='R^r' title='R^r' class='latex' /> is said to be <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BG%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{G}' title='&#92;mathcal{G}' class='latex' />-invariant if for every <img src='http://s0.wp.com/latex.php?latex=g%5Cin%5Cmathcal%7BG%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g&#92;in&#92;mathcal{G}' title='g&#92;in&#92;mathcal{G}' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=g%28R%5Er%29+%5Csubset+R%5Er&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(R^r) &#92;subset R^r' title='g(R^r) &#92;subset R^r' class='latex' />.  </p>
<p>We give two examples showing that this description agrees with the classical notions. </p>
<p><em>Gauge theory</em>. In classical gauged theories, the configuration space <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}' title='&#92;mathcal{C}' class='latex' /> is a fibre bundle with structure group <img src='http://s0.wp.com/latex.php?latex=G&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='G' title='G' class='latex' /> which acts on the fibres. A section of <img src='http://s0.wp.com/latex.php?latex=G%5Ctimes+X+%5Cto+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='G&#92;times X &#92;to X' title='G&#92;times X &#92;to X' class='latex' /> induces a diffeomorphism of <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}' title='&#92;mathcal{C}' class='latex' /> by fibre-wise action. In fact, the gauge symmetry is a fibre bundle morphism (fixes the base points).</p>
<p><em>General relativity</em>. In general relativity, the configuration space is the space of Lorentzian metrics. So the background manifold is the space-time <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X' title='X' class='latex' />. And the configuration space is the open submanifold of <img src='http://s0.wp.com/latex.php?latex=S%5E2T%5E%2AX&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='S^2T^*X' title='S^2T^*X' class='latex' /> given by non-degenerate symmetric bilinear forms with signature (-+++). A diffeomorphism <img src='http://s0.wp.com/latex.php?latex=%5CPsi%3AX%5Cto+X&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Psi:X&#92;to X' title='&#92;Psi:X&#92;to X' class='latex' /> induces <img src='http://s0.wp.com/latex.php?latex=T%5E%2A%5CPsi+%3D+%28%5CPsi%5E%7B-1%7D%29%5E%2A%3A+T%5E%2AX+%5Cto+T%5E%2AX&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='T^*&#92;Psi = (&#92;Psi^{-1})^*: T^*X &#92;to T^*X' title='T^*&#92;Psi = (&#92;Psi^{-1})^*: T^*X &#92;to T^*X' class='latex' /> and hence a configuration space diffeomorphism that commutes with projection. It is in this sense that Einstein&#8217;s equations are diffeomorphism invariant. </p>
<p>Notice of course, this formulation does not contain the &#8220;physical&#8221; distinction between global and local gauge transformations. For example, for a linear PDE (so <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}' title='&#92;mathcal{C}' class='latex' /> is a vector bundle and <img src='http://s0.wp.com/latex.php?latex=R%5Er&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='R^r' title='R^r' class='latex' /> is closed under linear operations), the trivial &#8220;global scaling&#8221; of a solution is considered in this frame work a gauge symmetry, though it is generally ignored in physics. </p>
<br />Filed under: <a href='http://williewong.wordpress.com/category/maths/differentialpseudo-riemannian-geometry/'>differential/pseudo-Riemannian geometry</a>, <a href='http://williewong.wordpress.com/category/maths/general-relativity/'>general relativity</a>, <a href='http://williewong.wordpress.com/category/maths/'>Maths</a>, <a href='http://williewong.wordpress.com/category/maths/partial-differential-equations/'>partial differential equations</a>, <a href='http://williewong.wordpress.com/category/requires-upper-level-university-maths/'>Requires upper level university maths</a>  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/williewong.wordpress.com/773/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/williewong.wordpress.com/773/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/williewong.wordpress.com/773/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/williewong.wordpress.com/773/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/williewong.wordpress.com/773/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/williewong.wordpress.com/773/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/williewong.wordpress.com/773/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/williewong.wordpress.com/773/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=773&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
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		<slash:comments>3</slash:comments>
	
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			<media:title type="html">Willie</media:title>
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		<title>Moving SVN servers</title>
		<link>http://williewong.wordpress.com/2011/09/28/moving-svn-servers/</link>
		<comments>http://williewong.wordpress.com/2011/09/28/moving-svn-servers/#comments</comments>
		<pubDate>Wed, 28 Sep 2011 10:57:23 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[Life of a mathematician]]></category>

		<guid isPermaLink="false">http://williewong.wordpress.com/?p=770</guid>
		<description><![CDATA[This is mostly to document the process for my own benefit, so the information is easier to find the next time I need to do it. This is also a follow-up to this previous post of mine. Suppose the repository on the old server is called &#8220;WorkSVN&#8221; as in my previous post. First we need [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=770&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>This is mostly to document the process for my own benefit, so the information is easier to find the next time I need to do it. This is also a follow-up to <a href="http://williewong.wordpress.com/2010/02/03/managing-papers-with-subversion/">this previous post of mine</a>. </p>
<p>Suppose the repository on the old server is called &#8220;WorkSVN&#8221; as in my previous post. First we need to dump the contents from the old server by</p>
<blockquote><p>
svnadmin dump /home/XXYY/WorkSVN &gt; WorkSVN.dmp
</p></blockquote>
<p>We then copy the file over to the new server. On the new server issue</p>
<blockquote><p>
svnadmin create ~/WorkSVN
</p></blockquote>
<p>as before, and followed by</p>
<blockquote><p>
svnadmin load ~/WorkSVN&lt; WorkSVN.dmp
</p></blockquote>
<p>to load the database dump. </p>
<p>Then create the working copy as usual</p>
<blockquote><p>
svn co file:///home/XXYY/WorkSVN/PaperDrafts ~/PaperDrafts
</p></blockquote>
<p>For the client computers, update the server path via</p>
<blockquote><p>
svn switch &#8211;relocate OLDURL NEWURL
</p></blockquote>
<p>You can find the oldurl by reading &#8220;svn info&#8221; of the working copy. </p>
<br />Filed under: <a href='http://williewong.wordpress.com/category/life-of-a-mathematician/'>Life of a mathematician</a>  <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/williewong.wordpress.com/770/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/williewong.wordpress.com/770/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gofacebook/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/facebook/williewong.wordpress.com/770/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gotwitter/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/twitter/williewong.wordpress.com/770/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/williewong.wordpress.com/770/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/williewong.wordpress.com/770/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/williewong.wordpress.com/770/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/williewong.wordpress.com/770/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=770&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></content:encoded>
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			<media:title type="html">Willie</media:title>
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		<title>Extensions of (co)vector fields to tangent bundles</title>
		<link>http://williewong.wordpress.com/2011/08/30/extensions-of-covector-fields-to-tangent-bundles/</link>
		<comments>http://williewong.wordpress.com/2011/08/30/extensions-of-covector-fields-to-tangent-bundles/#comments</comments>
		<pubDate>Tue, 30 Aug 2011 16:44:06 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[differential/pseudo-Riemannian geometry]]></category>
		<category><![CDATA[Maths]]></category>
		<category><![CDATA[Requires upper level university maths]]></category>

		<guid isPermaLink="false">http://williewong.wordpress.com/?p=761</guid>
		<description><![CDATA[I am reading Sasaki&#8217;s original paper on the construction of the Sasaki metric (a canonical Riemannian metric on the tangent bundle of a Riemannian manifold), and the following took me way too long to understand. So I&#8217;ll write it down in case I forgot in the future. In section two of the paper, Sasaki consider [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=761&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>I am reading Sasaki&#8217;s <a href="http://projecteuclid.org/euclid.tmj/1178244668">original paper</a> on the construction of the Sasaki metric (a canonical Riemannian metric on the tangent bundle of a Riemannian manifold), and the following took me way too long to understand. So I&#8217;ll write it down in case I forgot in the future. </p>
<p>In section two of the paper, Sasaki consider &#8220;extended transformations and extended tensors&#8221;. Basically he wanted to give a way to &#8220;lift&#8221; tensor fields from a manifold to tensor fields of the same rank on its tangent bundle. And he did so in the language of coordinate changes, which geometrical content is a bit hard to parse. I&#8217;ll discuss his construction in a bit. But first I&#8217;ll talk about something different. </p>
<p><strong>The <em>trivial</em> lifts</strong><br />
Let <img src='http://s0.wp.com/latex.php?latex=M%2C+N&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M, N' title='M, N' class='latex' /> be smooth manifolds, and let <img src='http://s0.wp.com/latex.php?latex=f%3AM%5Cto+N&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f:M&#92;to N' title='f:M&#92;to N' class='latex' /> a submersion. Then we can trivially lift covariant objects on <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='N' title='N' class='latex' /> to equivalent objects on <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> by the <em>pull-back</em> operation. To define the pull-back, we start with a covariant tensor field <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta+%5Cin+%5CGamma+T%5E0_kN&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta &#92;in &#92;Gamma T^0_kN' title='&#92;vartheta &#92;in &#92;Gamma T^0_kN' class='latex' />, and set <img src='http://s0.wp.com/latex.php?latex=f%5E%2A%5Cvartheta+%5Cin+%5CGamma+T%5E0_kM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f^*&#92;vartheta &#92;in &#92;Gamma T^0_kM' title='f^*&#92;vartheta &#92;in &#92;Gamma T^0_kM' class='latex' /> by the formula:</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+f%5E%2A%5Cvartheta%28X_1%2C%5Cldots%2CX_k%29+%3D+%5Cvartheta%28df%5Ccirc+X_1%2C+%5Cldots%2C+df%5Ccirc+X_k%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle f^*&#92;vartheta(X_1,&#92;ldots,X_k) = &#92;vartheta(df&#92;circ X_1, &#92;ldots, df&#92;circ X_k)' title='&#92;displaystyle f^*&#92;vartheta(X_1,&#92;ldots,X_k) = &#92;vartheta(df&#92;circ X_1, &#92;ldots, df&#92;circ X_k)' class='latex' />
</p></blockquote>
<p>where the <img src='http://s0.wp.com/latex.php?latex=X_1%2C+%5Cldots%2C+X_k+%5Cin+T_pM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='X_1, &#92;ldots, X_k &#92;in T_pM' title='X_1, &#92;ldots, X_k &#92;in T_pM' class='latex' />, and we use that <img src='http://s0.wp.com/latex.php?latex=df%28p%29%3A+T_pM+%5Cto+T_%7Bf%28p%29%7DN&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='df(p): T_pM &#92;to T_{f(p)}N' title='df(p): T_pM &#92;to T_{f(p)}N' class='latex' />. Observe that for a function <img src='http://s0.wp.com/latex.php?latex=g%3A+N+%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g: N &#92;to &#92;mathbb{R}' title='g: N &#92;to &#92;mathbb{R}' class='latex' />, the pull-back is simply <img src='http://s0.wp.com/latex.php?latex=f%5E%2Ag+%3D+g%5Ccirc+f+%3AM%5Cto+N%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f^*g = g&#92;circ f :M&#92;to N&#92;to&#92;mathbb{R}' title='f^*g = g&#92;circ f :M&#92;to N&#92;to&#92;mathbb{R}' class='latex' />. </p>
<p>On the other hand, for <em>contravariant</em> tensor fields, the pull-back is not uniquely defined: using that <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f' title='f' class='latex' /> is a submersion, we have that <img src='http://s0.wp.com/latex.php?latex=TM+%2F+%5Cker%28df%29+%3D+TN&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM / &#92;ker(df) = TN' title='TM / &#92;ker(df) = TN' class='latex' />, so while, given a vector field <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='N' title='N' class='latex' />, we can always find a vector field <img src='http://s0.wp.com/latex.php?latex=w&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='w' title='w' class='latex' /> on <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=df%28w%29+%3D+v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='df(w) = v' title='df(w) = v' class='latex' />, the vector field <img src='http://s0.wp.com/latex.php?latex=w&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='w' title='w' class='latex' /> is only unique up to an addition of a vector field that lies in the kernel of <img src='http://s0.wp.com/latex.php?latex=df&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='df' title='df' class='latex' />. If, however, that <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> is Riemannian, then we can take the orthogonal decomposition of <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' /> into the kernel and its complement, thereby getting a well-defined lift of the vector field (in other words, by exploiting the identification between the tangent and cotangent spaces). </p>
<p>Remarkably, the extensions defined by Sasaki is not this one. </p>
<p>(Let me just add a remark here: given two manifolds, once one obtain a well defined way of lifting vectors, covectors, and functions from one to the other, such that they are compatible (<img src='http://s0.wp.com/latex.php?latex=%5Cvartheta%5E%2A%28v%5E%2A%29+%3D+%5B%5Cvartheta%28v%29%5D%5E%2A&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta^*(v^*) = [&#92;vartheta(v)]^*' title='&#92;vartheta^*(v^*) = [&#92;vartheta(v)]^*' class='latex' />), one can extend this mapping to arbitrary tensor fields.)</p>
<p><strong>The extensions defined by Sasaki</strong><br />
As seen above, if we just rely on the canonical submersion <img src='http://s0.wp.com/latex.php?latex=%5Cpi%3ATM%5Cto+M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi:TM&#92;to M' title='&#92;pi:TM&#92;to M' class='latex' />, we cannot generally extend vector fields. Sasaki&#8217;s construction, however, strongly exploits the fact that <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' /> is the tangent bundle of <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' />. </p>
<p>We start by looking at the vector field extension defined by equation (2.6) of the linked paper. We first observe that a vector field <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> on a manifold <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> is a section of the tangent bundle. That is, <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> is a map <img src='http://s0.wp.com/latex.php?latex=M%5Cto+TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M&#92;to TM' title='M&#92;to TM' class='latex' /> such that the composition with the canonical projection <img src='http://s0.wp.com/latex.php?latex=%5Cpi%5Ccirc+v%3AM%5Cto+M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi&#92;circ v:M&#92;to M' title='&#92;pi&#92;circ v:M&#92;to M' class='latex' /> is the identity map. This implies, using the chain rule, that the map <img src='http://s0.wp.com/latex.php?latex=d%28%5Cpi%5Ccirc+v%29%3D+d%5Cpi+%5Ccirc+dv%3A+TM%5Cto+TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d(&#92;pi&#92;circ v)= d&#92;pi &#92;circ dv: TM&#92;to TM' title='d(&#92;pi&#92;circ v)= d&#92;pi &#92;circ dv: TM&#92;to TM' class='latex' /> is also the identity map. Now, <img src='http://s0.wp.com/latex.php?latex=d%5Cpi%3A+T%28TM%29+%5Cto+TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d&#92;pi: T(TM) &#92;to TM' title='d&#92;pi: T(TM) &#92;to TM' class='latex' /> is the projection induced by the projection map <img src='http://s0.wp.com/latex.php?latex=%5Cpi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi' title='&#92;pi' class='latex' />, which is different from the canonical projection <img src='http://s0.wp.com/latex.php?latex=%5Cpi_2%3A+T%28TM%29+%5Cto+TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi_2: T(TM) &#92;to TM' title='&#92;pi_2: T(TM) &#92;to TM' class='latex' /> from the tangent bundle of a manifold to the manifold itself. However, a Proposition of Kobayashi (see &#8220;Theory of Connections&#8221; (1957), Proposition 1.4), shows that there exists an automorphism <img src='http://s0.wp.com/latex.php?latex=%5Calpha%3AT%28TM%29+%5Cto+T%28TM%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha:T(TM) &#92;to T(TM)' title='&#92;alpha:T(TM) &#92;to T(TM)' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=d%5Cpi+%5Ccirc+%5Calpha+%3D+%5Cpi_2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d&#92;pi &#92;circ &#92;alpha = &#92;pi_2' title='d&#92;pi &#92;circ &#92;alpha = &#92;pi_2' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpi_2%5Ccirc%5Calpha+%3D+d%5Cpi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi_2&#92;circ&#92;alpha = d&#92;pi' title='&#92;pi_2&#92;circ&#92;alpha = d&#92;pi' class='latex' />. So <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> as a differential mapping induces a map <img src='http://s0.wp.com/latex.php?latex=%5Calpha%5Ccirc+dv%3A+TM+%5Cto+T%28TM%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha&#92;circ dv: TM &#92;to T(TM)' title='&#92;alpha&#92;circ dv: TM &#92;to T(TM)' class='latex' />, which is a map from the tangent bundle <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' /> to the double tangent bundle <img src='http://s0.wp.com/latex.php?latex=T%28TM%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='T(TM)' title='T(TM)' class='latex' />, which when composed with the canonical projection <img src='http://s0.wp.com/latex.php?latex=%5Cpi_2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pi_2' title='&#92;pi_2' class='latex' /> is the identity. In other words, <img src='http://s0.wp.com/latex.php?latex=%5Calpha%5Ccirc+dv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha&#92;circ dv' title='&#92;alpha&#92;circ dv' class='latex' /> is a vector field on <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' />. </p>
<p>Next we look at the definition (2.7) for one-forms. Give <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta' title='&#92;vartheta' class='latex' /> a one-form on <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' />, it induces naturally a scalar function on <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' />: for <img src='http://s0.wp.com/latex.php?latex=p%5Cin+M%2C+v%5Cin+T_pM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p&#92;in M, v&#92;in T_pM' title='p&#92;in M, v&#92;in T_pM' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta%3A+TM%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta: TM&#92;to &#92;mathbb{R}' title='&#92;vartheta: TM&#92;to &#92;mathbb{R}' class='latex' /> taking value <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta%28p%29%5Ccdot+v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta(p)&#92;cdot v' title='&#92;vartheta(p)&#92;cdot v' class='latex' />. Hence its differential <img src='http://s0.wp.com/latex.php?latex=d%5Cvartheta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d&#92;vartheta' title='d&#92;vartheta' class='latex' /> is a one-form over <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' />. </p>
<p>Now, what about scalar functions? Let <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta' title='&#92;vartheta' class='latex' /> be a one-form and <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> be a vector field on <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' />, we consider the pairing of their extensions to <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' />. It is not too hard to check that the corresponding scalar field to <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta%28v%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta(v)' title='&#92;vartheta(v)' class='latex' />, when evaluated at <img src='http://s0.wp.com/latex.php?latex=%28p%2Cw%29%5Cin+TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(p,w)&#92;in TM' title='(p,w)&#92;in TM' class='latex' />, is in fact <img src='http://s0.wp.com/latex.php?latex=d%28%5Cvartheta%28v%29%29%7C_%7Bp%2Cw%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d(&#92;vartheta(v))|_{p,w}' title='d(&#92;vartheta(v))|_{p,w}' class='latex' />, the derivative of the scalar function <img src='http://s0.wp.com/latex.php?latex=%5Cvartheta%28v%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;vartheta(v)' title='&#92;vartheta(v)' class='latex' /> in the direction of <img src='http://s0.wp.com/latex.php?latex=w&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='w' title='w' class='latex' /> at point <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p' title='p' class='latex' />. In general, the compatible lift of scalar fields <img src='http://s0.wp.com/latex.php?latex=g%3AM%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g:M&#92;to &#92;mathbb{R}' title='g:M&#92;to &#92;mathbb{R}' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' /> is the function <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7Bg%7D%28p%2Cv%29+%3D+dg%28p%29%5Bv%5D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{g}(p,v) = dg(p)[v]' title='&#92;tilde{g}(p,v) = dg(p)[v]' class='latex' />. </p>
<p>Using this we can extend the construction to arbitrary tensor fields, and a simple computation yields that this construction is in fact identical, for rank-2 tensors, to the expressions given in (2.8), (2.9), and (2.10) in the paper. </p>
<p><strong>The second extension</strong><br />
The above extension is not the only map sending vectors on <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> to vectors on <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' />. In the statement of Lemmas 3 there is also another construction. Given a vector field <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' />, it induces a one parameter family of diffeomorphisms on <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' /> via that maps <img src='http://s0.wp.com/latex.php?latex=%5Cpsi_t%28p%2Cw%29+%3D+%28p%2C+w%2Bvt%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi_t(p,w) = (p, w+vt)' title='&#92;psi_t(p,w) = (p, w+vt)' class='latex' />. Its differential <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D%5Cpsi_t%7C_%7Bt%3D0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{d}{dt}&#92;psi_t|_{t=0}' title='&#92;frac{d}{dt}&#92;psi_t|_{t=0}' class='latex' /> is a vector field over <img src='http://s0.wp.com/latex.php?latex=TM&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='TM' title='TM' class='latex' />. </p>
<p>The construction in the statement of Lemma 4 is the trivial one mentioned at the start of this post. </p>
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			<media:title type="html">Willie</media:title>
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		<title>Decay of waves IIIb: tails for homogeneous linear equation on curved background</title>
		<link>http://williewong.wordpress.com/2011/06/09/decay-of-waves-iiib-tails-for-homogeneous-linear-equation-on-curved-background/</link>
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		<pubDate>Thu, 09 Jun 2011 13:03:44 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[differential/pseudo-Riemannian geometry]]></category>
		<category><![CDATA[general relativity]]></category>
		<category><![CDATA[Maths]]></category>
		<category><![CDATA[partial differential equations]]></category>
		<category><![CDATA[Requires upper level university maths]]></category>
		<category><![CDATA[wave and Schroedinger equations]]></category>

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		<description><![CDATA[Now we will actually show that the specific decay properties of the linear wave equation on Minkowski space&#8211;in particular the strong Huygens&#8217; principle&#8211;is very strongly tied to the global geometry of that space-time. In particular, we&#8217;ll build, by hand, an example of a space-time where geometry itself induces back-scattering, and even linear, homogeneous waves will [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=707&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Now we will actually show that the specific decay properties of the linear wave equation on Minkowski space&#8211;in particular the strong Huygens&#8217; principle&#8211;is very strongly tied to the global geometry of that space-time. In particular, we&#8217;ll build, by hand, an example of a space-time where geometry itself induces back-scattering, and even linear, homogeneous waves will exhibit a tail. </p>
<p>For convenience, the space-time we construct will be spherically symmetric, and we will only consider spherically symmetric solutions of the wave equation on it. We will also focus on the 1+3 dimensional case. <span id="more-707"></span></p>
<p><strong>Spherically symmetric space-times and their wave equations</strong></p>
<p>In a 1+3 dimensional spherically symmetric space-time, associated to each point (unless the point is on the symmetry axis; that is, a fixed point under the symmetry action) is a two-dimensional sphere, the orbit of the point under the symmetry. Much like the way we define spherical coordinates for 3-dimensional Euclidean space, we can define an analogous system of coordinates for such manifolds. (For more detailed and more involved discussion of this, see <a href="http://journals.cambridge.org/article_S030500410400790X">Szenthe</a>, <em>On the global geometry of spherically symmetric space-times</em>, Math. Proc. Cam. Phil. Soc. (2004) 137:741&#8211;754.) </p>
<p>The spherical symmetry in particular implies that, away from the symmetry axis, our space-time take the form of a warped product <img src='http://s0.wp.com/latex.php?latex=M%5Csetminus+%5CGamma+%3D+Q+%5Crtimes_r+%5Cmathbb%7BS%7D%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M&#92;setminus &#92;Gamma = Q &#92;rtimes_r &#92;mathbb{S}^2' title='M&#92;setminus &#92;Gamma = Q &#92;rtimes_r &#92;mathbb{S}^2' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> is the space-time, <img src='http://s0.wp.com/latex.php?latex=%5CGamma&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Gamma' title='&#92;Gamma' class='latex' /> is the axis, <img src='http://s0.wp.com/latex.php?latex=Q&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Q' title='Q' class='latex' /> is the two-dimensional quotient manifold, <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BS%7D%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbb{S}^2' title='&#92;mathbb{S}^2' class='latex' /> is given the standard metric on the unit sphere, and the warping function <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> is the <em>area-radius</em> of the symmetry spheres. (That is, <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> is defined to be the square root of <img src='http://s0.wp.com/latex.php?latex=%284%5Cpi%29%5E%7B-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(4&#92;pi)^{-1}' title='(4&#92;pi)^{-1}' class='latex' /> times the surface area of the orbit of the spherical symmetry.) So we can build a coordinate system on <img src='http://s0.wp.com/latex.php?latex=M%5Csetminus%5CGamma&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M&#92;setminus&#92;Gamma' title='M&#92;setminus&#92;Gamma' class='latex' /> by taking an arbitrary coordinate system on the 1+1 dimensional Lorentzian manifold <img src='http://s0.wp.com/latex.php?latex=Q&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Q' title='Q' class='latex' /> and joining to it some coordinate system on the standard sphere. </p>
<p>Now, any 1+1 Lorentzian manifold admits a (in fact a large number of) <em>double null</em> coordinate system. That is, we can always find a pair of functions <img src='http://s0.wp.com/latex.php?latex=u%2Cv%3AQ%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u,v:Q&#92;to &#92;mathbb{R}' title='u,v:Q&#92;to &#92;mathbb{R}' class='latex' /> so that they are linearly independent functions, with <img src='http://s0.wp.com/latex.php?latex=%5Clangle+du%2C+du%5Crangle+%3D+%5Clangle+dv%2Cdv%5Crangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;langle du, du&#92;rangle = &#92;langle dv,dv&#92;rangle' title='&#92;langle du, du&#92;rangle = &#92;langle dv,dv&#92;rangle' class='latex' /> under the induced Lorentzian metric on <img src='http://s0.wp.com/latex.php?latex=Q&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Q' title='Q' class='latex' /> (this follows from the fact that at each point <img src='http://s0.wp.com/latex.php?latex=q%5Cin+Q&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='q&#92;in Q' title='q&#92;in Q' class='latex' />, the tangent space <img src='http://s0.wp.com/latex.php?latex=T_qQ&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='T_qQ' title='T_qQ' class='latex' /> admits two such preferred directions, and that Frobenius theorem is trivial in two dimensions). Under an assumption of time-orientability, we can find some function <img src='http://s0.wp.com/latex.php?latex=%5COmega%3AQ%5Cto+%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega:Q&#92;to &#92;mathbb{R}' title='&#92;Omega:Q&#92;to &#92;mathbb{R}' class='latex' /> such that the metric on <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' /> can be expressed as </p>
<blockquote><p><strong>Equation 27</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+ds%5E2+%3D+-%5COmega%5E2%28u%2Cv%29+du%5Ctilde%7B%5Cotimes%7Ddv+%2B+r%5E2%28u%2Cv%29+d%5Comega%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle ds^2 = -&#92;Omega^2(u,v) du&#92;tilde{&#92;otimes}dv + r^2(u,v) d&#92;omega^2' title='&#92;displaystyle ds^2 = -&#92;Omega^2(u,v) du&#92;tilde{&#92;otimes}dv + r^2(u,v) d&#92;omega^2' class='latex' />
</p></blockquote>
<p>where <img src='http://s0.wp.com/latex.php?latex=d%5Comega%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d&#92;omega^2' title='d&#92;omega^2' class='latex' /> is the standard metric on the sphere. </p>
<p>Let us now consider a spherically symmetric solution to the wave equation on such a space-time. </p>
<blockquote><p><strong>Equation 28</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5CBox+%5Cphi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Box &#92;phi = 0' title='&#92;Box &#92;phi = 0' class='latex' />
</p></blockquote>
<p>Expanding the d&#8217;Alembertian operator as the Laplace-Beltrami operator for the Lorentzian manifold <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='M' title='M' class='latex' />, we get that</p>
<blockquote><p><strong>Equation 29</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5CBox+%3D+-%5Cfrac%7B1%7D%7B2r%5E2%5COmega%5E2%7D%28%5Cpartial_u+r%5E2%5Cpartial_v+%2B+%5Cpartial_v+r%5E2+%5Cpartial_u%29+%2B+%5Cfrac%7B1%7D%7Br%5E2%7D+%5Ctriangle_%7B%5Cmathbb%7BS%7D%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;Box = -&#92;frac{1}{2r^2&#92;Omega^2}(&#92;partial_u r^2&#92;partial_v + &#92;partial_v r^2 &#92;partial_u) + &#92;frac{1}{r^2} &#92;triangle_{&#92;mathbb{S}^2}' title='&#92;displaystyle &#92;Box = -&#92;frac{1}{2r^2&#92;Omega^2}(&#92;partial_u r^2&#92;partial_v + &#92;partial_v r^2 &#92;partial_u) + &#92;frac{1}{r^2} &#92;triangle_{&#92;mathbb{S}^2}' class='latex' />
</p></blockquote>
<p>which in particular implies that the function <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%3A%3D+r+%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi := r &#92;phi' title='&#92;psi := r &#92;phi' class='latex' /> will solve the following equation</p>
<blockquote><p><strong>Equation 30</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B%5COmega%5E2%7D+%5Cpartial%5E2_%7Bu%2Cv%7D%5Cpsi+%3D+%5Cfrac%7B%5Cpartial%5E2_%7Bu%2Cv%7Dr%7D%7Br%5COmega%5E2%7D%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{&#92;Omega^2} &#92;partial^2_{u,v}&#92;psi = &#92;frac{&#92;partial^2_{u,v}r}{r&#92;Omega^2}&#92;psi' title='&#92;displaystyle &#92;frac{1}{&#92;Omega^2} &#92;partial^2_{u,v}&#92;psi = &#92;frac{&#92;partial^2_{u,v}r}{r&#92;Omega^2}&#92;psi' class='latex' />
</p></blockquote>
<p>So in particular <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> will solve a 1+1 dimensional wave equation <em>with source term</em> on manifold <img src='http://s0.wp.com/latex.php?latex=Q&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='Q' title='Q' class='latex' /> (which we can partially complete by adding the axis <img src='http://s0.wp.com/latex.php?latex=%5CGamma&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Gamma' title='&#92;Gamma' class='latex' /> and imposing the Dirichlet boundary condition there). This will be the starting point of our construction (recall the support propagation properties of the wave equation from <a href="http://williewong.wordpress.com/2011/05/14/decay-of-waves-iib-minkowski-space-with-right-hand-side/">Part IIb of this series</a>). </p>
<p><strong>A &#8220;radiating&#8221; space-time</strong><br />
Consider the following partial Penrose diagram<br />
<div id="attachment_728" class="wp-caption alignnone" style="width: 341px"><a href="http://williewong.files.wordpress.com/2011/06/illustration5.png"><img src="http://williewong.files.wordpress.com/2011/06/illustration5.png" alt="" title="Illustration5" width="331" height="331" class="size-full wp-image-728" /></a><p class="wp-caption-text">Figure 5</p></div><br />
where we assume that a background double-null coordinate system <img src='http://s0.wp.com/latex.php?latex=%28u%2Cv%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(u,v)' title='(u,v)' class='latex' /> is fixed, and so for a solution whose initial data is strictly supported inside the draw region, its <em>future</em> evolution will not depend on how we (smoothly) complete the space-time. </p>
<p>To prescribe the geometry we do so by describing the functions <img src='http://s0.wp.com/latex.php?latex=%5COmega%2Cr&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega,r' title='&#92;Omega,r' class='latex' /> as functions of the coordinates; we will build the space-time such that in the <em>yellow regions</em> of Figure 5 the space-time is Minkowskian, and that we have a perturbation in the <em>red region</em>. The red region we will assume to be bounded by <img src='http://s0.wp.com/latex.php?latex=v%5Cin+%280%2C%5Cinfty%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v&#92;in (0,&#92;infty)' title='v&#92;in (0,&#92;infty)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=u%5Cin+%280%2Cu_0%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u&#92;in (0,u_0)' title='u&#92;in (0,u_0)' class='latex' />. This we will take to be a poor-man&#8217;s version of a radiating space-time, where the red region represents some sort of out-going gravitational disturbance. Of course, here we prescribe the metric freely, rather than try to solve for it using some sort of the dynamical model, so the actual form of the metric is somewhat aphysical. Nevertheless this should give some indication of why it is not feasible to expect too good a decay of the solutions of linear wave equations on arbitrary space-times. </p>
<p>On the yellow region near future time-like infinity, we will insert in the Minkowski space solution in the usual parametrization. That is, we assume that there exists some <img src='http://s0.wp.com/latex.php?latex=R_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='R_0' title='R_0' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=r+%3D+%5Cfrac%7B1%7D%7B2%7D%28v+-+u%29+%2B+R_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r = &#92;frac{1}{2}(v - u) + R_0' title='r = &#92;frac{1}{2}(v - u) + R_0' class='latex' />, and that the function <img src='http://s0.wp.com/latex.php?latex=%5COmega+%3D+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega = 1' title='&#92;Omega = 1' class='latex' /> identically. </p>
<p>In the red region, we choose the function <img src='http://s0.wp.com/latex.php?latex=r+%3D+%5Cfrac%7B1%7D%7B2%7D%28v-u%29+%2B+R&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r = &#92;frac{1}{2}(v-u) + R' title='r = &#92;frac{1}{2}(v-u) + R' class='latex' /> so that it joins smoothly to the first yellow region where <img src='http://s0.wp.com/latex.php?latex=u+%3E+u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u &gt; u_0' title='u &gt; u_0' class='latex' />. To be more precise, <img src='http://s0.wp.com/latex.php?latex=R&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='R' title='R' class='latex' /> will be taken to be equal to satisfy <img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5E2_%7Bu%2Cv%7DR+%3D+%5Cfrac%7B%5Cmu%28u%29%7D%7Bv-u+%2B+2R_0%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial^2_{u,v}R = &#92;frac{&#92;mu(u)}{v-u + 2R_0}' title='&#92;partial^2_{u,v}R = &#92;frac{&#92;mu(u)}{v-u + 2R_0}' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%5Cmu%5Cin+C%5E%5Cinfty_c%28%280%2Cu_0%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu&#92;in C^&#92;infty_c((0,u_0))' title='&#92;mu&#92;in C^&#92;infty_c((0,u_0))' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cmu%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu&#92;geq 0' title='&#92;mu&#92;geq 0' class='latex' />.  By prescribing initial conditions on the bottom left boundary of the figure, we can assume that in the region <img src='http://s0.wp.com/latex.php?latex=u+%3C+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u &lt; 0' title='u &lt; 0' class='latex' /> we have <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u+R+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u R = 0' title='&#92;partial_u R = 0' class='latex' />. On the other hand, we necessarily have that there <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v+R+%3D+-+%5Cint_0%5E%7Bu_0%7D%5Cfrac%7B%5Cmu%28u%29%7D%7Bv-u+%2B+2R_0%7D+du+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v R = - &#92;int_0^{u_0}&#92;frac{&#92;mu(u)}{v-u + 2R_0} du ' title='&#92;partial_v R = - &#92;int_0^{u_0}&#92;frac{&#92;mu(u)}{v-u + 2R_0} du ' class='latex' /> is a function of <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> alone. By assuming that <img src='http://s0.wp.com/latex.php?latex=%5Cmu%2C+u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu, u_0' title='&#92;mu, u_0' class='latex' /> are sufficiently small, we can guarantee that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v+r+%3E+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v r &gt; 0' title='&#92;partial_v r &gt; 0' class='latex' /> in the region, and so we can define a change of variables <img src='http://s0.wp.com/latex.php?latex=v%5Cto+v%27&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v&#92;to v&#039;' title='v&#92;to v&#039;' class='latex' /> so that in the <img src='http://s0.wp.com/latex.php?latex=%28u%2Cv%27%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(u,v&#039;)' title='(u,v&#039;)' class='latex' /> coordinate system, we have that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u+r+%3D+-+%5Cpartial_%7Bv%27%7Dr+%3D+-1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u r = - &#92;partial_{v&#039;}r = -1' title='&#92;partial_u r = - &#92;partial_{v&#039;}r = -1' class='latex' />. We can then set <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> in the region <img src='http://s0.wp.com/latex.php?latex=u+%3C+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u &lt; 0' title='u &lt; 0' class='latex' /> so that <img src='http://s0.wp.com/latex.php?latex=%5COmega%5E2+du%5Ctilde%7B%5Cotimes%7Ddv+%3D+du%5Ctilde%7B%5Cotimes%7Ddv%27&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega^2 du&#92;tilde{&#92;otimes}dv = du&#92;tilde{&#92;otimes}dv&#039;' title='&#92;Omega^2 du&#92;tilde{&#92;otimes}dv = du&#92;tilde{&#92;otimes}dv&#039;' class='latex' />, thereby enforcing that the region is also Minkowskian. Lastly we take an arbitrary positive, smooth choice of <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' /> in the red region to join the values we have now prescribed for the two yellow regions. </p>
<p><strong>Tail for homogeneous linear wave equation</strong></p>
<p>On this space-time we just constructed, let us consider an initial data for the wave equation such that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> is an incoming wave-packet. That is, we can assume that for <img src='http://s0.wp.com/latex.php?latex=0+%3E+u+%3E+u_1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='0 &gt; u &gt; u_1' title='0 &gt; u &gt; u_1' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u+%5Cpsi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u &#92;psi = 0' title='&#92;partial_u &#92;psi = 0' class='latex' />, and that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi &#92;geq 0' title='&#92;psi &#92;geq 0' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Cpsi%7C_%7Bv+%5Cleq+0%7D+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi|_{v &#92;leq 0} = 0' title='&#92;psi|_{v &#92;leq 0} = 0' class='latex' />. Such solutions are fairly generic in the space of compactly supported Cauchy data. Then using the fact that <img src='http://s0.wp.com/latex.php?latex=%5Cmu%28u%29+%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu(u) &#92;geq 0' title='&#92;mu(u) &#92;geq 0' class='latex' />, we can integrate Equation 30 to obtain, inductively, that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi &#92;geq 0' title='&#92;psi &#92;geq 0' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=-R_0+%3E+u_0+%3E+u+%3E+u_1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-R_0 &gt; u_0 &gt; u &gt; u_1' title='-R_0 &gt; u_0 &gt; u &gt; u_1' class='latex' />. Furthermore, integrating the expression for <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u%5Cpartial_v+R&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u&#92;partial_v R' title='&#92;partial_u&#92;partial_v R' class='latex' />, we have that <img src='http://s0.wp.com/latex.php?latex=%7CR%7C+%3D+%5C%7C%5Cmu%5C%7C_%5Cinfty+O%28%5Cln+v%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|R| = &#92;|&#92;mu&#92;|_&#92;infty O(&#92;ln v)' title='|R| = &#92;|&#92;mu&#92;|_&#92;infty O(&#92;ln v)' class='latex' /> in the red region, which implies, for <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' /> sufficiently small, that <img src='http://s0.wp.com/latex.php?latex=r+%5Csim+v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r &#92;sim v' title='r &#92;sim v' class='latex' /> in the red region. </p>
<p>Therefore the coefficient on the right hand side of Equation 30 decays like <img src='http://s0.wp.com/latex.php?latex=v%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v^{-2}' title='v^{-2}' class='latex' />, so is in particular integrable in the red region. So for small enough <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' />, we can iterate the fundamental solution representation for the 1+1 dimensional wave equation to get a convergent series representation of the solution <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' />, with all terms non-negative. The first term of the iteration guarantees that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> is bounded below inside <img src='http://s0.wp.com/latex.php?latex=u_0+%5Cgeq+u+%5Cgeq+%5Cepsilon+%3E+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_0 &#92;geq u &#92;geq &#92;epsilon &gt; 0' title='u_0 &#92;geq u &#92;geq &#92;epsilon &gt; 0' class='latex' /> for any fixed <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;epsilon' title='&#92;epsilon' class='latex' />. Which then implies that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v+%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v &#92;psi' title='&#92;partial_v &#92;psi' class='latex' /> is bounded below by <img src='http://s0.wp.com/latex.php?latex=v%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v^{-2}' title='v^{-2}' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> is sufficiently large along <img src='http://s0.wp.com/latex.php?latex=u+%3D+u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u = u_0' title='u = u_0' class='latex' />. </p>
<p>Propagating forward into the yellow region, we have that in the yellow region you have <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v+%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v &#92;psi' title='&#92;partial_v &#92;psi' class='latex' /> decaying like <img src='http://s0.wp.com/latex.php?latex=v%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v^{-2}' title='v^{-2}' class='latex' />. We can transfer this to an estimate on <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />: in the yellow region <img src='http://s0.wp.com/latex.php?latex=u+%3E+u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u &gt; u_0' title='u &gt; u_0' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cpsi%28u%2Cv%29+%3D+%5Cint_%7Bu-2R_0%7D%5Ev+%5Cpartial_v+%5Cpsi%28u%2Cs%29+ds&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi(u,v) = &#92;int_{u-2R_0}^v &#92;partial_v &#92;psi(u,s) ds' title='&#92;psi(u,v) = &#92;int_{u-2R_0}^v &#92;partial_v &#92;psi(u,s) ds' class='latex' /> using that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> vanishes on the center axis. But <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v&#92;psi' title='&#92;partial_v&#92;psi' class='latex' /> is conserved along <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u' title='u' class='latex' />, so we actually have that <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bv-u%2B2R_0%7D%7B%28u-2R_0%29v%7D+%5Clesssim+%5Cpsi%28u%2Cv%29+%3C+%5Cint_%7Bu-2R_0%7D%5E%5Cinfty+%5Cpartial_v%5Cpsi%28u_0%2Cs%29ds+%5Clesssim+u%5E%7B-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{v-u+2R_0}{(u-2R_0)v} &#92;lesssim &#92;psi(u,v) &lt; &#92;int_{u-2R_0}^&#92;infty &#92;partial_v&#92;psi(u_0,s)ds &#92;lesssim u^{-1}' title='&#92;frac{v-u+2R_0}{(u-2R_0)v} &#92;lesssim &#92;psi(u,v) &lt; &#92;int_{u-2R_0}^&#92;infty &#92;partial_v&#92;psi(u_0,s)ds &#92;lesssim u^{-1}' class='latex' />. Dividing through by <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> we get a <strong>lower bound</strong> that, within the eventual Minkowski region, the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> to the original linear, homogeneous wave equation exhibits a <img src='http://s0.wp.com/latex.php?latex=t%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t^{-2}' title='t^{-2}' class='latex' /> tail. </p>
<p><strong>A more physical decay rate</strong></p>
<p><em>[Thanks to Mihalis for reminding me of this!]</em> One sees from the argument above that the tail decay rate is intimately tied to the rate of decay of <img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5E2_%7Bu%2Cv%7D+r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial^2_{u,v} r' title='&#92;partial^2_{u,v} r' class='latex' /> in the wave region. And indeed, we can run through the exact same argument as above with the rates</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial%5E2_%7Bu%2Cv%7DR+%3D+%5Cfrac%7B%5Cmu%28u%29%7D%7B%28v-u+%2B+2R_0%29%5Ep%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;partial^2_{u,v}R = &#92;frac{&#92;mu(u)}{(v-u + 2R_0)^p}' title='&#92;displaystyle &#92;partial^2_{u,v}R = &#92;frac{&#92;mu(u)}{(v-u + 2R_0)^p}' class='latex' />
</p></blockquote>
<p>for any power <img src='http://s0.wp.com/latex.php?latex=p+%5Cgeq+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p &#92;geq 1' title='p &#92;geq 1' class='latex' />. This will lead to the appearance of a corresponding tail of size </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cphi+%5Csim+t%5E%7B-p-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;phi &#92;sim t^{-p-1}' title='&#92;displaystyle &#92;phi &#92;sim t^{-p-1}' class='latex' />.
</p></blockquote>
<p>The above construction shows that in arbitrary Lorentzian manifolds, one can not do better than a <img src='http://s0.wp.com/latex.php?latex=t%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t^{-2}' title='t^{-2}' class='latex' /> decay. But in the context of general relativity, this heuristic leads to <img src='http://s0.wp.com/latex.php?latex=t%5E%7B-3%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t^{-3}' title='t^{-3}' class='latex' /> being the more physical decay rate. This has to do with the fact that for physical space-times appearing in relativity theory, we expect the space-time to have a well-defined Bondi mass (which is the limit of the <a href="http://williewong.wordpress.com/2010/02/06/the-kodama-vector-field-and-the-gravitational-red-shift/">Hawking mass</a> at null infinity. Formally we can read off the Bondi mass from the <img src='http://s0.wp.com/latex.php?latex=r%5E%7B-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r^{-1}' title='r^{-1}' class='latex' /> term in the asymptotic expansion of <img src='http://s0.wp.com/latex.php?latex=g%28%5Cnabla+r%2C%5Cnabla+r%29+%3D+%5COmega%5E%7B-2%7D+%5Cpartial_u+r+%5Cpartial_v+r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(&#92;nabla r,&#92;nabla r) = &#92;Omega^{-2} &#92;partial_u r &#92;partial_v r' title='g(&#92;nabla r,&#92;nabla r) = &#92;Omega^{-2} &#92;partial_u r &#92;partial_v r' class='latex' />. For the choice of <img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5E2_%7Bu%2Cv%7D+r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial^2_{u,v} r' title='&#92;partial^2_{u,v} r' class='latex' /> given above, with <img src='http://s0.wp.com/latex.php?latex=2+%3E+p&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='2 &gt; p' title='2 &gt; p' class='latex' /> the Bondi mass blows up at infinity (the asymptotic expansion is not well defined). For <img src='http://s0.wp.com/latex.php?latex=p+%3E+2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p &gt; 2' title='p &gt; 2' class='latex' />, the Bondi mass is zero. So heuristically we expect the case <img src='http://s0.wp.com/latex.php?latex=p+%3D+2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='p = 2' title='p = 2' class='latex' /> to correspond to the physically interesting case where gravitation has non-trivial long range effects. And for this rate we have a cubic decay law expected (as consistent with the so-called &#8220;Price&#8217;s Law&#8221; in general relativity). </p>
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		<title>Decay of waves IIIa: nonlinear tails in Minkowski space redux</title>
		<link>http://williewong.wordpress.com/2011/05/16/decay-of-waves-iiia-nonlinear-tails-in-minkowski-space-redux/</link>
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		<pubDate>Mon, 16 May 2011 11:27:46 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[Maths]]></category>
		<category><![CDATA[partial differential equations]]></category>
		<category><![CDATA[Requires upper level university maths]]></category>
		<category><![CDATA[wave and Schroedinger equations]]></category>

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		<description><![CDATA[Before we move on to the geometric case, I want to flesh out the nonlinear case mentioned in the end of the last post a bit more. Recall that it was shown for generic nonlinear (actually semilinear; for quasilinear and worse equations we cannot use Duhamel&#8217;s principle) wave equations, if we put in compact support [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=700&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Before we move on to the geometric case, I want to flesh out the nonlinear case mentioned in the end of the last post a bit more. Recall that it was shown for generic nonlinear (actually semilinear; for quasilinear and worse equations we cannot use Duhamel&#8217;s principle) wave equations, if we put in compact support for the initial data, we expect the first iterate to exhibit a tail. One may ask whether it is possible that, in fact, this is an artifact of the successive approximation scheme; that in fact somehow it always transpires that a conspiracy happens, and all the higher order iterates cancel out the tail coming from the first iterate. This is rather unlikely, owing to the fact that the convergence to <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%5Cinfty&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_&#92;infty' title='&#92;phi_&#92;infty' class='latex' /> is dominated by a geometric series. But to just make double sure, here we give a nonlinear system of wave equations such that the successive approximation scheme converges after finitely many steps (in fact, after the first iterate), and so we can also explicitly compute the rate of decay for the nonlinear tail. While the decay rate is not claimed to be generic (though it is), the existence of one such example with a fixed decay rate shows that for a statement quantifying over all nonlinear wave equations, it would be impossible to demonstrate better decay rate than the one exhibited.<span id="more-700"></span></p>
<p>In this particular case we will consider the following system of wave equations on 1+3 dimensional Minkowski space, with the assumption of spherical symmetry in force. </p>
<blockquote><p><strong>Equation 21</strong><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cphi+%2B+%5Ctriangle+%5Cphi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;phi + &#92;triangle &#92;phi = 0' title='-&#92;partial_t^2 &#92;phi + &#92;triangle &#92;phi = 0' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cpsi+%2B+%5Ctriangle+%5Cpsi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;psi + &#92;triangle &#92;psi = 0' title='-&#92;partial_t^2 &#92;psi + &#92;triangle &#92;psi = 0' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Czeta+%2B+%5Ctriangle+%5Czeta+%3D+%28%5Cpartial_t%5Cphi+%2B+%5Cpartial_r%5Cphi%29%5Ccdot%28%5Cpartial_t%5Cpsi+-+%5Cpartial_r%5Cpsi%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;zeta + &#92;triangle &#92;zeta = (&#92;partial_t&#92;phi + &#92;partial_r&#92;phi)&#92;cdot(&#92;partial_t&#92;psi - &#92;partial_r&#92;psi)' title='-&#92;partial_t^2 &#92;zeta + &#92;triangle &#92;zeta = (&#92;partial_t&#92;phi + &#92;partial_r&#92;phi)&#92;cdot(&#92;partial_t&#92;psi - &#92;partial_r&#92;psi)' class='latex' />
</p></blockquote>
<p>The system as a whole, as an equation on the vector <img src='http://s0.wp.com/latex.php?latex=%28%5Cphi%2C%5Cpsi%2C%5Czeta%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(&#92;phi,&#92;psi,&#92;zeta)' title='(&#92;phi,&#92;psi,&#92;zeta)' class='latex' /> is nonlinear, since the right hand side depends nonlinearly on the vector itself. However, we recognize that taken individually the components of the vector decouple, and each component solves a (possibly inhomogeneous) wave equation with no nonlinearities. (So we cheat a little bit. But this is how we can make the successive approximation scheme converge after finitely many steps.) </p>
<p>Recall that under the spherical symmetry change of coordinates, writing again <img src='http://s0.wp.com/latex.php?latex=u+%3D+%5Cfrac12%28t-r%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u = &#92;frac12(t-r)' title='u = &#92;frac12(t-r)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=v%3D%5Cfrac12%28t%2Br%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v=&#92;frac12(t+r)' title='v=&#92;frac12(t+r)' class='latex' />, we can rewrite the equations as</p>
<blockquote><p><strong>Equation 21&#8242;</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u%5Cpartial_v%28r%5Cphi%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u&#92;partial_v(r&#92;phi) = 0' title='&#92;partial_u&#92;partial_v(r&#92;phi) = 0' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u%5Cpartial_v%28r%5Cpsi%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u&#92;partial_v(r&#92;psi) = 0' title='&#92;partial_u&#92;partial_v(r&#92;psi) = 0' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u%5Cpartial_v%28r%5Czeta%29+%3D+-%28v-u%29+%5Cpartial_v%5Cphi+%5Ccdot+%5Cpartial_u+%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u&#92;partial_v(r&#92;zeta) = -(v-u) &#92;partial_v&#92;phi &#92;cdot &#92;partial_u &#92;psi' title='&#92;partial_u&#92;partial_v(r&#92;zeta) = -(v-u) &#92;partial_v&#92;phi &#92;cdot &#92;partial_u &#92;psi' class='latex' />
</p></blockquote>
<p>Why this particular form on nonlinearities? It is known that generic nonlinearities, quadratic in <img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial&#92;phi' title='&#92;partial&#92;phi' class='latex' />, lead to formation of singularities in finite time, with the number of spatial dimensions is less than or equal to three. In dimension 1, we can explicitly illustrate this: consider the wave equation <img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_u%5Cpartial_v+%5Cvarphi+%3D+%28%5Cpartial_v%5Cvarphi%29%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_u&#92;partial_v &#92;varphi = (&#92;partial_v&#92;varphi)^2' title='-&#92;partial_u&#92;partial_v &#92;varphi = (&#92;partial_v&#92;varphi)^2' class='latex' />. Then along the curves of constant <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' />, the quantity <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v+%5Cvarphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v &#92;varphi' title='&#92;partial_v &#92;varphi' class='latex' /> verifies an equation of the form <img src='http://s0.wp.com/latex.php?latex=y%27+%3D+-y%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y&#039; = -y^2' title='y&#039; = -y^2' class='latex' />, whose solution is <img src='http://s0.wp.com/latex.php?latex=y+%3D+%5Cfrac%7B1%7D%7Bx%2Bc%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='y = &#92;frac{1}{x+c}' title='y = &#92;frac{1}{x+c}' class='latex' />. So if <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v%5Cvarphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v&#92;varphi' title='&#92;partial_v&#92;varphi' class='latex' /> is negative at any point when <img src='http://s0.wp.com/latex.php?latex=t+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t = 0' title='t = 0' class='latex' />, the solution will develop a singularity in finite time. </p>
<p>In low spatial dimensions, the rates of dispersion are slower (the energy density is expected to drop as the inverse of the area of the wave front, which in <img src='http://s0.wp.com/latex.php?latex=d&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d' title='d' class='latex' /> dimensions grows like <img src='http://s0.wp.com/latex.php?latex=t%5E%7Bd-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t^{d-1}' title='t^{d-1}' class='latex' />), and compared to the positive feedback coming from a generic quadratic derivative nonlinearity, may not be enough to radiate away the self-interaction sufficiently fast.  This motivated my thesis advisor, Sergiu Klainerman, to study, when he was doing his own PhD, the conditions sufficient to guarantee the quadratic nonlinearities are not too strong. This lead to the recognition that the so-called <em>null structures</em> play an important role in the study of wave equations in low spatial dimensions. To cut the story short, the form chosen for the nonlinearity above renders it a null form, so it should be better behaved (decay faster) than the most general quadratic type nonlinearities. By choosing this example, my goal is to illustrate the fact that even in the <em>good</em> scenarios, one expect to have some fairly strong nonlinear tail effects. (A detailed discussion of this topic would take us too far from the focus of this post. Perhaps I&#8217;ll write about it in a part IV to this series.) (That we need a <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and a <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> is also related. If we only have the function <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and choose the nonlinearity for <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' /> to be <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v%5Cphi%5Cpartial_u%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v&#92;phi&#92;partial_u&#92;phi' title='&#92;partial_v&#92;phi&#92;partial_u&#92;phi' class='latex' />, we see that the null form cancellation is <em>too</em> strong, and we won&#8217;t be able to see the effect at the level of the first iterate.)</p>
<p>Anyway, back to the example.  </p>
<div id="attachment_693" class="wp-caption alignnone" style="width: 264px"><a href="http://williewong.files.wordpress.com/2011/05/illustration4.png"><img src="http://williewong.files.wordpress.com/2011/05/illustration4.png" alt="" title="Illustration4" width="254" height="352" class="size-full wp-image-693" /></a><p class="wp-caption-text">Figure 4 (again)</p></div>
<p>The key observation is captured already in Figure 4 (which we recall again here above): when the red dot is &#8220;sufficiently far in the future&#8221;, the crosshatched region only intersects the &#8220;outgoing legs&#8221; of the cyan region (using the fact the incoming wave, after bouncing off the center axis, becomes outgoing also). In other words, where the crosshatched region and the cyan region intersects, the wave is purely outgoing. </p>
<p>Now suppose the cyan region is a representation of the support of <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' />, and we are trying to evaluate <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' /> at the red dot (the part coming from initial data can be neglected due to linearity). To do so we integrate <img src='http://s0.wp.com/latex.php?latex=-%28v-u%29%5Cpartial_v%5Cphi%5Cpartial_u%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-(v-u)&#92;partial_v&#92;phi&#92;partial_u&#92;psi' title='-(v-u)&#92;partial_v&#92;phi&#92;partial_u&#92;psi' class='latex' /> in the intersection of the crosshatched and cyan regions. Now in that region, Equation 21&#8242; implies that <img src='http://s0.wp.com/latex.php?latex=r%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r&#92;phi' title='r&#92;phi' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=r%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r&#92;psi' title='r&#92;psi' class='latex' /> are outgoing waves, that is there <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v' title='&#92;partial_v' class='latex' /> derivatives vanish. Furthermore the wave equation also means their <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u' title='&#92;partial_u' class='latex' /> derivatives are constant along lines of constant <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u' title='u' class='latex' />. </p>
<blockquote><p><strong>Equation 22</strong><br />
<img src='http://s0.wp.com/latex.php?latex=0+%3D+%5Cpartial_v+%28r%5Cphi%29+%3D+%5Cphi+%2B+r%5Cpartial_v%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='0 = &#92;partial_v (r&#92;phi) = &#92;phi + r&#92;partial_v&#92;phi' title='0 = &#92;partial_v (r&#92;phi) = &#92;phi + r&#92;partial_v&#92;phi' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=c%28u%29+%3D+%5Cpartial_u%28r%5Cpsi%29+%3D+-%5Cpsi+%2B+r%5Cpartial_u%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='c(u) = &#92;partial_u(r&#92;psi) = -&#92;psi + r&#92;partial_u&#92;psi' title='c(u) = &#92;partial_u(r&#92;psi) = -&#92;psi + r&#92;partial_u&#92;psi' class='latex' />
</p></blockquote>
<p>Using the constancy of <img src='http://s0.wp.com/latex.php?latex=r%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r&#92;phi' title='r&#92;phi' class='latex' /> along constant <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u' title='u' class='latex' /> lines, we have that <img src='http://s0.wp.com/latex.php?latex=%5Cphi+%3D+c_%5Cphi%28u%29%2Fr&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi = c_&#92;phi(u)/r' title='&#92;phi = c_&#92;phi(u)/r' class='latex' />, and similarly <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%3D+c_%5Cpsi%28u%29%2Fr&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi = c_&#92;psi(u)/r' title='&#92;psi = c_&#92;psi(u)/r' class='latex' />. So we get that</p>
<blockquote><p><strong>Equation 23</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+r%5Cpartial_v%5Cphi+%3D+-+%5Cfrac%7Bc_%5Cphi%28u%29%7D%7Br%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle r&#92;partial_v&#92;phi = - &#92;frac{c_&#92;phi(u)}{r}' title='&#92;displaystyle r&#92;partial_v&#92;phi = - &#92;frac{c_&#92;phi(u)}{r}' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_u%5Cpsi+%3D+%5Cfrac%7Bc%28u%29%7D%7Br%7D+%2B+%5Cfrac%7Bc_%5Cpsi%28u%29%7D%7Br%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;partial_u&#92;psi = &#92;frac{c(u)}{r} + &#92;frac{c_&#92;psi(u)}{r^2}' title='&#92;displaystyle &#92;partial_u&#92;psi = &#92;frac{c(u)}{r} + &#92;frac{c_&#92;psi(u)}{r^2}' class='latex' />
</p></blockquote>
<p>Now, the area integrated over is determined both by the cyan and crosshatched regions. The cyan region coming from <img src='http://s0.wp.com/latex.php?latex=%5Cphi%2C%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi,&#92;psi' title='&#92;phi,&#92;psi' class='latex' /> determins the <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u' title='u' class='latex' /> limits of the integration, while the crosshatched region determines the <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> limits. We will just assume that the <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u' title='u' class='latex' /> limits are some fixed values <img src='http://s0.wp.com/latex.php?latex=u_l&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_l' title='u_l' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=u_r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_r' title='u_r' class='latex' />, which is completely determined by the compact support of the initial data. The <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' /> limits, however, depends on where we will evaluate <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' />. If we choose to evaluate <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' /> at point <img src='http://s0.wp.com/latex.php?latex=%28u_0%2Cv_0%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(u_0,v_0)' title='(u_0,v_0)' class='latex' />, we see that by the requirement <img src='http://s0.wp.com/latex.php?latex=v_0+-+u_0+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v_0 - u_0 = 0' title='v_0 - u_0 = 0' class='latex' /> on the central axis, the lower bound of the region is precisely <img src='http://s0.wp.com/latex.php?latex=v+%3D+u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v = u_0' title='v = u_0' class='latex' />, and the upperbound <img src='http://s0.wp.com/latex.php?latex=v+%3D+v_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v = v_0' title='v = v_0' class='latex' />. Therefore we have that, for the red dot sufficiently far in the future where the picture in Figure 4 is a good representation, </p>
<blockquote><p><strong>Equation 24</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28v_0+-+u_0%29%5Czeta%28u_0%2Cv_0%29+%3D+%5Cint_%7Bu_0%7D%5E%7Bv_0%7D%5Cint_%7Bu_r%7D%5E%7Bu_l%7D+%5Cfrac%7Bc_%5Cphi%28u%29%7D%7Br%7D%5Cleft%28+%5Cfrac%7Bc%28u%29%7D%7Br%7D+%2B+%5Cfrac%7Bc_%5Cpsi%28u%29%7D%7Br%5E2%7D%5Cright%29%7Edu%7Edv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle (v_0 - u_0)&#92;zeta(u_0,v_0) = &#92;int_{u_0}^{v_0}&#92;int_{u_r}^{u_l} &#92;frac{c_&#92;phi(u)}{r}&#92;left( &#92;frac{c(u)}{r} + &#92;frac{c_&#92;psi(u)}{r^2}&#92;right)~du~dv' title='&#92;displaystyle (v_0 - u_0)&#92;zeta(u_0,v_0) = &#92;int_{u_0}^{v_0}&#92;int_{u_r}^{u_l} &#92;frac{c_&#92;phi(u)}{r}&#92;left( &#92;frac{c(u)}{r} + &#92;frac{c_&#92;psi(u)}{r^2}&#92;right)~du~dv' class='latex' />
</p></blockquote>
<p>Now, sufficiently far into the future, <img src='http://s0.wp.com/latex.php?latex=u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_0' title='u_0' class='latex' /> is sufficiently large, and hence <img src='http://s0.wp.com/latex.php?latex=r+%3D+v+-+u+%5Cgeq+u_0+-+u_l&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r = v - u &#92;geq u_0 - u_l' title='r = v - u &#92;geq u_0 - u_l' class='latex' /> is very large. This means that we can throw away the second term in the parentheses as negligible. For generic <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> (note that if <img src='http://s0.wp.com/latex.php?latex=%5Cphi+%3D+%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi = &#92;psi' title='&#92;phi = &#92;psi' class='latex' /> there is actually a cancellation so that the contribution from the nonlinearity vanishes), we can find a lowerbound once <img src='http://s0.wp.com/latex.php?latex=u_0%2C+v_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_0, v_0' title='u_0, v_0' class='latex' /> become large enough (the upper bound is trivial)</p>
<blockquote><p><strong>Equation 25</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+C_%7B%5Cphi%2C%5Cpsi%7D+%5Cint_%7Bu_0%7D%5E%7Bv_0%7Dv%5E%7B-2%7D+dv++%5Cgeq+%5Cleft%7C+%5Cint_%7Bu_0%7D%5E%7Bv_0%7D%5Cint_%7Bu_r%7D%5E%7Bu_l%7D+%5Cfrac%7Bc_%5Cphi%28u%29c%28u%29%7D%7Br%5E2%7D%7Edu%7Edv+%5Cright%7C+%5Cgeq+C_%7B%5Cphi%2C%5Cpsi%7D%5E%7B-1%7D+%5Cint_%7Bu_0%7D%5E%7Bv_0%7D+v%5E%7B-2%7D+dv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle C_{&#92;phi,&#92;psi} &#92;int_{u_0}^{v_0}v^{-2} dv  &#92;geq &#92;left| &#92;int_{u_0}^{v_0}&#92;int_{u_r}^{u_l} &#92;frac{c_&#92;phi(u)c(u)}{r^2}~du~dv &#92;right| &#92;geq C_{&#92;phi,&#92;psi}^{-1} &#92;int_{u_0}^{v_0} v^{-2} dv' title='&#92;displaystyle C_{&#92;phi,&#92;psi} &#92;int_{u_0}^{v_0}v^{-2} dv  &#92;geq &#92;left| &#92;int_{u_0}^{v_0}&#92;int_{u_r}^{u_l} &#92;frac{c_&#92;phi(u)c(u)}{r^2}~du~dv &#92;right| &#92;geq C_{&#92;phi,&#92;psi}^{-1} &#92;int_{u_0}^{v_0} v^{-2} dv' class='latex' />
</p></blockquote>
<p>And in Equation 25 we capture the behaviour of the nonlinear tail. For any fixed <img src='http://s0.wp.com/latex.php?latex=r_0+%3D+v_0+-+u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r_0 = v_0 - u_0' title='r_0 = v_0 - u_0' class='latex' />, the integral <img src='http://s0.wp.com/latex.php?latex=%5Cint_%7Bu_0%7D%5E%7Bv_0%7D+v%5E%7B-2%7D+dv+%5Csim+%28v_0+-+u_0%29%28v_0+%2B+u_0%29%5E%7B-2%7D+%3D+r_0+t_0%5E%7B-2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;int_{u_0}^{v_0} v^{-2} dv &#92;sim (v_0 - u_0)(v_0 + u_0)^{-2} = r_0 t_0^{-2}' title='&#92;int_{u_0}^{v_0} v^{-2} dv &#92;sim (v_0 - u_0)(v_0 + u_0)^{-2} = r_0 t_0^{-2}' class='latex' />. So we have that</p>
<blockquote><p><strong>Equation 26a</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Czeta%28t%2Cr_0%29+%5Csim+%5Cfrac%7B1%7D%7Bt%5E2%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;zeta(t,r_0) &#92;sim &#92;frac{1}{t^2}' title='&#92;displaystyle &#92;zeta(t,r_0) &#92;sim &#92;frac{1}{t^2}' class='latex' /> for fixed <img src='http://s0.wp.com/latex.php?latex=r_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r_0' title='r_0' class='latex' />
</p></blockquote>
<p>giving us the &#8220;interior decay&#8221; rate. On the otherhand, if we were to take the limit toward <img src='http://s0.wp.com/latex.php?latex=v_0%5Cnearrow+%2B%5Cinfty&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v_0&#92;nearrow +&#92;infty' title='v_0&#92;nearrow +&#92;infty' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_0' title='u_0' class='latex' /> fixed, we have that the total integral is controlled by <img src='http://s0.wp.com/latex.php?latex=u_0%5E%7B-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_0^{-1}' title='u_0^{-1}' class='latex' />, and so we have the &#8220;radiative decay&#8221; rate coming purely from the <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> weight:</p>
<blockquote><p><strong>Equation 26b</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Czeta%28v%2Cu_0%29+%5Csim+%5Cfrac%7B1%7D%7Bv%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;zeta(v,u_0) &#92;sim &#92;frac{1}{v}' title='&#92;displaystyle &#92;zeta(v,u_0) &#92;sim &#92;frac{1}{v}' class='latex' /> for any sufficiently large fixed <img src='http://s0.wp.com/latex.php?latex=u_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u_0' title='u_0' class='latex' />.
</p></blockquote>
<p>In both Equations 26a and 26b, the &#8220;eventually vanishing&#8221; phenomena observed in the linear case for data with compact support are destroyed. </p>
<p>Lastly, just note that Equations 26a,b can be glued together with boundedness on bounded regions to get the global estimate</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Czeta%28v%2Cu%29+%5Csim+%5Cfrac%7B1%7D%7B%281%2B%7Cu%7C%29%281%2B%7Cv%7C%29%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;zeta(v,u) &#92;sim &#92;frac{1}{(1+|u|)(1+|v|)}' title='&#92;displaystyle &#92;zeta(v,u) &#92;sim &#92;frac{1}{(1+|u|)(1+|v|)}' class='latex' />
</p></blockquote>
<p>which captures a more generic (in the sense of stability under nonlinear perturbations) behaviour of spherically symmetric waves on 1+3 dimensional Minkowski space. </p>
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			<media:title type="html">Willie</media:title>
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		<title>Decay of waves IIb: Minkowski space, with right-hand side</title>
		<link>http://williewong.wordpress.com/2011/05/14/decay-of-waves-iib-minkowski-space-with-right-hand-side/</link>
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		<pubDate>Sat, 14 May 2011 13:50:55 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[Maths]]></category>
		<category><![CDATA[partial differential equations]]></category>
		<category><![CDATA[Requires upper level university maths]]></category>
		<category><![CDATA[wave and Schroedinger equations]]></category>

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		<description><![CDATA[In the first half of this second part of the series, we considered solutions to the linear, homogeneous wave equation on flat Minkowski space, and showed that for compactly supported initial data, we have strong Huygens&#8217; principle. We further made references to the fact that this behaviour is expected to be unstable. In this post, [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=671&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>In the first half of this second part of the series, we considered solutions to the linear, homogeneous wave equation on flat Minkowski space, and showed that for compactly supported initial data, we have <em>strong Huygens&#8217; principle</em>. We further made references to the fact that this behaviour is expected to be unstable. In this post, we will further illustrate this instability by looking at Equation 1 first with a fixed source <img src='http://s0.wp.com/latex.php?latex=F+%3D+F%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F = F(t,x)' title='F = F(t,x)' class='latex' />, and then with a nonlinearity <img src='http://s0.wp.com/latex.php?latex=F+%3D+F%28t%2Cx%2C+%5Cphi%2C+%5Cpartial%5Cphi%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F = F(t,x, &#92;phi, &#92;partial&#92;phi)' title='F = F(t,x, &#92;phi, &#92;partial&#92;phi)' class='latex' />. </p>
<p><strong>Duhamel&#8217;s Principle</strong></p>
<p>To study how one can incorporate inhomogeneous terms into a linear equation, and to get a qualitative grasp of how the source term contributes to the solution, we need to discuss <a href="http://en.wikipedia.org/wiki/Duhamel's_principle">the abstract method known as Duhamel&#8217;s Principle</a>. We start by illustrating this for a very simple ordinary differential equation. </p>
<p>Consider the ODE satisfied by a scalar function <img src='http://s0.wp.com/latex.php?latex=%5Calpha&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha' title='&#92;alpha' class='latex' />:</p>
<blockquote><p><strong>Equation 13</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D%5Calpha%28s%29+%3D+k%28s%29%5Calpha%28s%29+%2B+%5Cbeta%28s%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds}&#92;alpha(s) = k(s)&#92;alpha(s) + &#92;beta(s)' title='&#92;displaystyle &#92;frac{d}{ds}&#92;alpha(s) = k(s)&#92;alpha(s) + &#92;beta(s)' class='latex' />
</p></blockquote>
<p>when <img src='http://s0.wp.com/latex.php?latex=%5Cbeta%5Cequiv+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;beta&#92;equiv 0' title='&#92;beta&#92;equiv 0' class='latex' />, we can easily solve the equation with integration factors</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha%28s%29+%3D+%5Calpha%280%29+e%5E%7B%5Cint_0%5Es+k%28t%29+dt%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;alpha(s) = &#92;alpha(0) e^{&#92;int_0^s k(t) dt}' title='&#92;displaystyle &#92;alpha(s) = &#92;alpha(0) e^{&#92;int_0^s k(t) dt}' class='latex' />
</p></blockquote>
<p>Using this as a sort of an ansatz, we can solve the inhomogeneous equation as follows. For convenience we denote by <img src='http://s0.wp.com/latex.php?latex=K%28s%29+%3D+%5Cint_0%5Es+k%28t%29+dt&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='K(s) = &#92;int_0^s k(t) dt' title='K(s) = &#92;int_0^s k(t) dt' class='latex' /> the anti-derivative of <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='k' title='k' class='latex' />. Then multiplying Equation 13 through by <img src='http://s0.wp.com/latex.php?latex=%5Cexp+-K%28s%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp -K(s)' title='&#92;exp -K(s)' class='latex' />, we have that</p>
<blockquote><p><strong>Equation 14</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bds%7D+%5Cleft%28+e%5E%7B-K%28s%29%7D%5Calpha%28s%29%5Cright%29+%3D+e%5E%7B-K%28s%29%7D%5Cbeta%28s%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{ds} &#92;left( e^{-K(s)}&#92;alpha(s)&#92;right) = e^{-K(s)}&#92;beta(s)' title='&#92;displaystyle &#92;frac{d}{ds} &#92;left( e^{-K(s)}&#92;alpha(s)&#92;right) = e^{-K(s)}&#92;beta(s)' class='latex' />
</p></blockquote>
<p>which we solve by integrating</p>
<blockquote><p><strong>Equation 15</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha%28s%29+%3D+e%5E%7BK%28s%29%7D%5Calpha%280%29+%2B+e%5E%7BK%28s%29%7D+%5Cint_0%5Es+e%5E%7B-K%28t%29%7D%5Cbeta%28t%29+dt&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;alpha(s) = e^{K(s)}&#92;alpha(0) + e^{K(s)} &#92;int_0^s e^{-K(t)}&#92;beta(t) dt' title='&#92;displaystyle &#92;alpha(s) = e^{K(s)}&#92;alpha(0) + e^{K(s)} &#92;int_0^s e^{-K(t)}&#92;beta(t) dt' class='latex' />
</p></blockquote>
<p>If we write <img src='http://s0.wp.com/latex.php?latex=K%28s%3Bt%29+%3D+%5Cint_t%5Es+k%28u%29+du&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='K(s;t) = &#92;int_t^s k(u) du' title='K(s;t) = &#92;int_t^s k(u) du' class='latex' />, then we can rewrite Equation 15 as given by an integral operator</p>
<blockquote><p><strong>Equation 15&#8242;</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha%28s%29+%3D+e%5E%7BK%28s%29%7D%5Calpha%280%29+%2B+%5Cint_0%5Es+e%5E%7BK%28s%3Bt%29%7D%5Cbeta%28t%29+dt&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;alpha(s) = e^{K(s)}&#92;alpha(0) + &#92;int_0^s e^{K(s;t)}&#92;beta(t) dt' title='&#92;displaystyle &#92;alpha(s) = e^{K(s)}&#92;alpha(0) + &#92;int_0^s e^{K(s;t)}&#92;beta(t) dt' class='latex' />
</p></blockquote>
<p><span id="more-671"></span></p>
<p>So what does Equations 15 and 15&#8242; mean? The term <img src='http://s0.wp.com/latex.php?latex=%5Cexp+K%28s%3Bt%29+%5Cbeta%28t%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp K(s;t) &#92;beta(t)' title='&#92;exp K(s;t) &#92;beta(t)' class='latex' /> by itself would indicate a solution to the homogeneous version of ODE 13, evaluated at time <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='s' title='s' class='latex' />, with initial data prescribed at time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t' title='t' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=%5Cbeta%28t%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;beta(t)' title='&#92;beta(t)' class='latex' />. So in other words, the total solution of the ODE 13 at time <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='s' title='s' class='latex' /> corresponds to the &#8220;free evolution&#8221; of the initial data prescribed at time <img src='http://s0.wp.com/latex.php?latex=t+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t = 0' title='t = 0' class='latex' />, plus an infinitesimal part for each time instant between <img src='http://s0.wp.com/latex.php?latex=0+%3C+t+%3C+s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='0 &lt; t &lt; s' title='0 &lt; t &lt; s' class='latex' /> corresponding to the &quot;free evolution&quot; of initial data <img src='http://s0.wp.com/latex.php?latex=%5Cbeta%28t%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;beta(t)' title='&#92;beta(t)' class='latex' /> from time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t' title='t' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='s' title='s' class='latex' />. </p>
<p>Qualitatively, what is going on is that at every time instant, the &quot;source term&quot; gives a small kick to the solution. Because of the linearity of the corresponding homogeneous problem, each small kick evolves independently of the free evolution, and also independently of other small kicks coming from other instants in time. At the end to evaluate the solution at time <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='s' title='s' class='latex' />, all one needs to do is to add up the contribution from the sum total of these small kicks, and add to it the free evolution of the homogeneous problem given by the initial data. </p>
<p>Now, recall how many statements about scalar ODEs can be transferred to vector valued ODEs: we can treat <img src='http://s0.wp.com/latex.php?latex=%5Calpha%2C+%5Cbeta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha, &#92;beta' title='&#92;alpha, &#92;beta' class='latex' /> to be vector valued in Equation 13, with <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='k' title='k' class='latex' /> to be matrix valued. The defining <img src='http://s0.wp.com/latex.php?latex=%5Cexp+K&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp K' title='&#92;exp K' class='latex' /> the usual way for matrices, we get that Equations 15 and 15&#039; equally well apply in this context. </p>
<p>Similarly, with a bit more care, we can generalise this to infinite dimensional systems. </p>
<p>For the wave equation, observe that we can write it as a first order ODE on some Hilbert space: let <img src='http://s0.wp.com/latex.php?latex=%5Calpha+%3D+%28%5Cphi%2C+%5Cpartial_t+%5Cphi%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha = (&#92;phi, &#92;partial_t &#92;phi)' title='&#92;alpha = (&#92;phi, &#92;partial_t &#92;phi)' class='latex' />, then the wave equation can be written as</p>
<blockquote><p><strong>Equation 16</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7Bd%7D%7Bdt%7D+%5Cbegin%7Bpmatrix%7D%5Cphi%28t%29+%5C%5C+%5Cpartial_t%5Cphi%28t%29+%5Cend%7Bpmatrix%7D+%3D+%5Cbegin%7Bpmatrix%7D+0+%26+1%5C%5C+%5Ctriangle+%26+0%5Cend%7Bpmatrix%7D%5Cbegin%7Bpmatrix%7D+%5Cphi%28t%29+%5C%5C+%5Cpartial_t%5Cphi%28t%29%5Cend%7Bpmatrix%7D+%2B+%5Cbegin%7Bpmatrix%7D+0+%5C%5C+F%28t%29%5Cend%7Bpmatrix%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{d}{dt} &#92;begin{pmatrix}&#92;phi(t) &#92;&#92; &#92;partial_t&#92;phi(t) &#92;end{pmatrix} = &#92;begin{pmatrix} 0 &amp; 1&#92;&#92; &#92;triangle &amp; 0&#92;end{pmatrix}&#92;begin{pmatrix} &#92;phi(t) &#92;&#92; &#92;partial_t&#92;phi(t)&#92;end{pmatrix} + &#92;begin{pmatrix} 0 &#92;&#92; F(t)&#92;end{pmatrix}' title='&#92;displaystyle &#92;frac{d}{dt} &#92;begin{pmatrix}&#92;phi(t) &#92;&#92; &#92;partial_t&#92;phi(t) &#92;end{pmatrix} = &#92;begin{pmatrix} 0 &amp; 1&#92;&#92; &#92;triangle &amp; 0&#92;end{pmatrix}&#92;begin{pmatrix} &#92;phi(t) &#92;&#92; &#92;partial_t&#92;phi(t)&#92;end{pmatrix} + &#92;begin{pmatrix} 0 &#92;&#92; F(t)&#92;end{pmatrix}' class='latex' />
</p></blockquote>
<p>so at least on a formal level (which can in fact be made rigorous) we can obtain the solution for the inhomogeneous wave equation by considering the solutions for the homogeneous version. </p>
<p>To recapitulate, and to introduce some terminologies, equations like Equation 13 above, where <img src='http://s0.wp.com/latex.php?latex=%5Calpha%2C+%5Cbeta&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;alpha, &#92;beta' title='&#92;alpha, &#92;beta' class='latex' /> are &#8220;time dependent&#8221; functions that are scalar-, vector-, or Hilbert-space-valued, and where <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='k' title='k' class='latex' /> is a &#8220;time dependent&#8221; family of scalar-multipliers, linear transformations, or linear operators (in the three cases mentioned) are <em>first order evolution equations</em>. The corresponding object <img src='http://s0.wp.com/latex.php?latex=%5Cexp+K%28s%3Bt%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp K(s;t)' title='&#92;exp K(s;t)' class='latex' /> (which is now is a two-parameter, depending on initial and final times, family of multipliers, linear transformations, or linear operators) goes under the names of <em>free propagator</em>, <em>Green&#8217;s function</em>, or <em>fundamental solution</em>, as it denotes the (linear) change for solutions of the homogeneous problem between initial time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t' title='t' class='latex' /> and final time <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='s' title='s' class='latex' />. </p>
<p>As an aside: Interesting to note is that each evolution equation corresponds to a <a href="http://en.wikipedia.org/wiki/Category_theory">category</a>. The <em>objects</em> are sets representing the time-dependent spaces of data. The <em>morphisms</em> are precisely <img src='http://s0.wp.com/latex.php?latex=%5Cexp+K&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp K' title='&#92;exp K' class='latex' /> that maps between the different times. Well-posedness of the initial value problem relative to one element <img src='http://s0.wp.com/latex.php?latex=o&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='o' title='o' class='latex' /> in the class of objects is then the statement that <img src='http://s0.wp.com/latex.php?latex=o&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='o' title='o' class='latex' /> is an <a href="http://en.wikipedia.org/wiki/Initial_and_terminal_objects">initial object</a> (existence) and that for any two objects <img src='http://s0.wp.com/latex.php?latex=a%2Cb&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='a,b' title='a,b' class='latex' /> the class of morphisms <img src='http://s0.wp.com/latex.php?latex=hom%28a%2Cb%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='hom(a,b)' title='hom(a,b)' class='latex' /> consists of at most one arrow (uniqueness). Time reversibility will then be the statement our category is in fact a <a href="http://en.wikipedia.org/wiki/Groupoid">groupoid</a>, and hence that <img src='http://s0.wp.com/latex.php?latex=o&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='o' title='o' class='latex' /> is also a terminal object. Linearity amounts to requiring the objects be vector spaces and the arrows be vector space homomorphisms. Time translation symmetry would be the existence of a functor collapsing our category to a <a href="http://en.wikipedia.org/wiki/Monoid">monoid</a>. (At least, if I am not mistaken&#8230;.)</p>
<p><strong>Example: 1D wave equation</strong></p>
<p>Let us illustrate this by considering the wave equation in 1 spatial dimension. (Which, again, using the reflection trick described in the last post, gives us a solution to the case with Dirichlet boundary conditions, and also then to the spherically symmetric wave equation in 3 spatial dimensions.) We first try to write down the free propagator in terms of the first-order formalism above. Recall Equation 7 for the solution to the homogeneous problem with initial data <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' /></p>
<blockquote><p><strong>Equation 17a</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cphi%28t%2Cx%29+%3D+%5Cfrac12+%5Cleft%28f%28x-t%29+%2B+f%28x%2Bt%29+%2B+%5Cint_%7Bx-t%7D%5E%7Bx%2Bt%7D+g%28y%29+dy+%5Cright%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;phi(t,x) = &#92;frac12 &#92;left(f(x-t) + f(x+t) + &#92;int_{x-t}^{x+t} g(y) dy &#92;right)' title='&#92;displaystyle &#92;phi(t,x) = &#92;frac12 &#92;left(f(x-t) + f(x+t) + &#92;int_{x-t}^{x+t} g(y) dy &#92;right)' class='latex' />
</p></blockquote>
<p>Now observe that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_t&#92;phi' title='&#92;partial_t&#92;phi' class='latex' /> also solves a homogeneous wave equation by linearity, and using that for a solution <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t%5E2%5Cphi+%3D+%5Ctriangle+%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_t^2&#92;phi = &#92;triangle &#92;phi' title='&#92;partial_t^2&#92;phi = &#92;triangle &#92;phi' class='latex' />, we have that the initial data for <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_t &#92;phi' title='&#92;partial_t &#92;phi' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=%28g%2Cf%27%27%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(g,f&#039;&#039;)' title='(g,f&#039;&#039;)' class='latex' />. Hence we also have the expression </p>
<blockquote><p><strong>Equation 17b</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t%5Cphi%28t%2Cx%29+%3D+%5Cfrac12+%5Cleft%28+g%28x-t%29+%2B+g%28x%2Bt%29+%2B+%5Cint_%7Bx-t%7D%5E%7Bx%2Bt%7D+f%27%27%28y%29+dy%5Cright%29+%3D+%5Cfrac12+%5Cleft%28+g%28x-t%29+%2B+g%28x%2Bt%29+%2B+f%27%28x%2Bt%29+-+f%27%28x-t%29%5Cright%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;partial_t&#92;phi(t,x) = &#92;frac12 &#92;left( g(x-t) + g(x+t) + &#92;int_{x-t}^{x+t} f&#039;&#039;(y) dy&#92;right) = &#92;frac12 &#92;left( g(x-t) + g(x+t) + f&#039;(x+t) - f&#039;(x-t)&#92;right)' title='&#92;displaystyle &#92;partial_t&#92;phi(t,x) = &#92;frac12 &#92;left( g(x-t) + g(x+t) + &#92;int_{x-t}^{x+t} f&#039;&#039;(y) dy&#92;right) = &#92;frac12 &#92;left( g(x-t) + g(x+t) + f&#039;(x+t) - f&#039;(x-t)&#92;right)' class='latex' />
</p></blockquote>
<p>The time translation symmetry tells us that the propagator <img src='http://s0.wp.com/latex.php?latex=%5Cexp+K%28s%3Bt%29+%3D+%5Cexp+K%28s-t%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp K(s;t) = &#92;exp K(s-t)' title='&#92;exp K(s;t) = &#92;exp K(s-t)' class='latex' />. And Equations 17a,b tell us what the map <img src='http://s0.wp.com/latex.php?latex=%5Cexp+K%28s%3Bs%27%29%3A+%5Cleft%28%5Cphi%28s%27%29%2C%5Cpartial_t%5Cphi%28s%27%29%5Cright%29%5Cmapsto+%5Cleft%28%5Cphi%28s%29%2C%5Cpartial_t%5Cphi%28s%29%5Cright%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;exp K(s;s&#039;): &#92;left(&#92;phi(s&#039;),&#92;partial_t&#92;phi(s&#039;)&#92;right)&#92;mapsto &#92;left(&#92;phi(s),&#92;partial_t&#92;phi(s)&#92;right)' title='&#92;exp K(s;s&#039;): &#92;left(&#92;phi(s&#039;),&#92;partial_t&#92;phi(s&#039;)&#92;right)&#92;mapsto &#92;left(&#92;phi(s),&#92;partial_t&#92;phi(s)&#92;right)' class='latex' /> looks like. Now, going back up to Equation 16, we see that the vector representation of <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> only contributes to the second slot. So we have</p>
<blockquote><p><strong>Equation 18</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%28%5Cexp+K%28s-t%29+F%28t%29%5Cright%29%28x%29+%3D+%5Cfrac12+%5Cint_%7Bx-s%2Bt%7D%5E%7Bx%2Bs-t%7D+F%28t%2Cy%29+dy&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left(&#92;exp K(s-t) F(t)&#92;right)(x) = &#92;frac12 &#92;int_{x-s+t}^{x+s-t} F(t,y) dy' title='&#92;displaystyle &#92;left(&#92;exp K(s-t) F(t)&#92;right)(x) = &#92;frac12 &#92;int_{x-s+t}^{x+s-t} F(t,y) dy' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_s+%5Cleft%28%5Cexp+K%28s-t%29F%28t%29%5Cright%29%28x%29+%3D+%5Cfrac12+%5Cleft%28+F%28x-s%2Bt%29+%2B+F%28x%2Bs-t%29+%5Cright%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;partial_s &#92;left(&#92;exp K(s-t)F(t)&#92;right)(x) = &#92;frac12 &#92;left( F(x-s+t) + F(x+s-t) &#92;right)' title='&#92;displaystyle &#92;partial_s &#92;left(&#92;exp K(s-t)F(t)&#92;right)(x) = &#92;frac12 &#92;left( F(x-s+t) + F(x+s-t) &#92;right)' class='latex' />
</p></blockquote>
<p>and thus, the source part of the full solution to the inhomogeneous problem, would be</p>
<blockquote><p><strong>Equation 19</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cphi_%7Binhomo%7D%28s%2Cx%29+%3D+%5Cint_0%5Es+%5Cexp+K%28s-t%29+F%28t%29+dt+%3D+%5Cfrac12+%5Cint_%7B0%7D%5Es+%5Cint_%7Bx%2Bt-s%7D%5E%7Bx-t%2Bs%7D+F%28t%2Cy%29+dy+dt&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;phi_{inhomo}(s,x) = &#92;int_0^s &#92;exp K(s-t) F(t) dt = &#92;frac12 &#92;int_{0}^s &#92;int_{x+t-s}^{x-t+s} F(t,y) dy dt' title='&#92;displaystyle &#92;phi_{inhomo}(s,x) = &#92;int_0^s &#92;exp K(s-t) F(t) dt = &#92;frac12 &#92;int_{0}^s &#92;int_{x+t-s}^{x-t+s} F(t,y) dy dt' class='latex' />
</p></blockquote>
<p>which perhaps is easier seen with a picture. </p>
<div id="attachment_682" class="wp-caption alignnone" style="width: 485px"><a href="http://williewong.files.wordpress.com/2011/05/illustration2.png"><img src="http://williewong.files.wordpress.com/2011/05/illustration2.png" alt="" title="Illustration2" width="475" height="336" class="size-full wp-image-682" /></a><p class="wp-caption-text">Figure 2</p></div>
<p>In Figure 2, we assume that we want to consider the initial value problem for Equation 16 (of equivalently, the inhomogeneous wave equation) in spatial dimension 1. Let us assume that the initial data is prescribed on the <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> axis, and the initial data is identically zero. (In other words, we just want to consider purely the contribution coming from the source term, by setting the first term on the right hand side of Equation 15&#8242; to be 0. In the picture, the green region represents the support of the source function <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' />. Suppose we want to evaluate the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> at the red dot, then Equation 19 tells us that <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is given by <em>the total integral</em> of <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> in the blue, crosshatched region, which is bounded below by the initial time slice, and above by the <em>null</em> lines emanating from the red dot. </p>
<p>(In general, given a space-time point <img src='http://s0.wp.com/latex.php?latex=%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(t,x)' title='(t,x)' class='latex' /> where now space can be arbitrary number of dimensions, we will write the two sets <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D%5E%7B%5Cpm%7D%28t%2Cx%29%3A%3D+%5C%7B+%28s%2Cy%29+%3A+s+-+t+%3D+%5Cpm+%5Cleft%7C+y+-+x%5Cright%7C%5C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}^{&#92;pm}(t,x):= &#92;{ (s,y) : s - t = &#92;pm &#92;left| y - x&#92;right|&#92;}' title='&#92;mathcal{C}^{&#92;pm}(t,x):= &#92;{ (s,y) : s - t = &#92;pm &#92;left| y - x&#92;right|&#92;}' class='latex' /> which represents the future and past light rays emanating from our point. We see that they form two cones, intersection only at the vertex, in space-time. We will also denote the sets <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BI%7D%5E%7B%5Cpm%7D%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{I}^{&#92;pm}(t,x)' title='&#92;mathcal{I}^{&#92;pm}(t,x)' class='latex' /> to be respectively the future of <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D%5E%2B&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}^+' title='&#92;mathcal{C}^+' class='latex' /> and past of <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BC%7D%5E-&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{C}^-' title='&#92;mathcal{C}^-' class='latex' />.)</p>
<p>Another thing to read off from the picture, and from Equations 18 and 19, is that the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> will not &#8220;settle down to a constant value&#8221; until the support set of the inhomogeneity <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> is completely contained in <img src='http://s0.wp.com/latex.php?latex=%5Cmathcal%7BI%7D%5E%2B%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathcal{I}^+(t,x)' title='&#92;mathcal{I}^+(t,x)' class='latex' />. So in particular, if the support set for <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> has infinite spatial (or temporal) extent, then the solution will see &#8220;tail behaviour&#8221;. This supports the interpretation, using Duhamel&#8217;s Principle, of the right-hand side of the wave equation as a &#8220;source term&#8221;. </p>
<p><strong>A quick detour to Penrose diagram</strong></p>
<p>To better illustrate the <em>global behaviour</em> of wave equations, we will use the so-called (Carter-)Penrose diagrams for space-time. To study late time behaviour, we will need to think about points infinitely far into the future. And so we want a convenient way to represent the space-time and its infinite extent on a finite piece of paper. This requires some creative rescaling of space-time coordinates. Now, there are many ways to map the infinite to the finte. For example, consider the tangent function. It is a one-to-one mapping between the open interval <img src='http://s0.wp.com/latex.php?latex=%28-%5Cpi%2C%5Cpi%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(-&#92;pi,&#92;pi)' title='(-&#92;pi,&#92;pi)' class='latex' /> and the entire real line. The Penrose diagram is a particular type of mapping. Now, if you look at any mapping from <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mathbb{R}^2' title='&#92;mathbb{R}^2' class='latex' />, representing the 1+1 dimensional space-time, to a finite region, it would be necessary that some of the straight-lines be mapped to lines that are no longer straight. (If all straight lines are preserved, the mapping must be affine by the fundamental theorem of projective geometry.) So the question is what, if any, curves we want to keep &#8220;straight&#8221;. As we have already seen, what is most important in the study of wave equations is the null lines <img src='http://s0.wp.com/latex.php?latex=x%5Cpm+t+%3D+const&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x&#92;pm t = const' title='x&#92;pm t = const' class='latex' />; they, being characteristics of the partial differential equation, encode most of the phenomenon that we want to study. The Penrose diagram is a way of representing the 1+1 dimensional Minkowski space-time as a set with finite extent, such that the null lines (which are also the level sets of the <img src='http://s0.wp.com/latex.php?latex=u%2Cv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u,v' title='u,v' class='latex' /> coordinate functions) are preserved. </p>
<div id="attachment_688" class="wp-caption alignnone" style="width: 359px"><a href="http://williewong.files.wordpress.com/2011/05/illustration3.png"><img src="http://williewong.files.wordpress.com/2011/05/illustration3.png" alt="" title="Illustration3" width="349" height="469" class="size-full wp-image-688" /></a><p class="wp-caption-text">Figure 3</p></div>
<p>Figure 3 shows some examples of Penrose diagrams. (a) is the Penrose diagram for the 1+1 dimensional Minkowski space, the boundaries of the diamond are precisely where the coordinate functions <img src='http://s0.wp.com/latex.php?latex=u%2Cv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u,v' title='u,v' class='latex' /> attain <img src='http://s0.wp.com/latex.php?latex=%5Cpm+%5Cinfty&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;pm &#92;infty' title='&#92;pm &#92;infty' class='latex' /> values; we include the diagonal lines to indicate the level sets of <img src='http://s0.wp.com/latex.php?latex=u%2Cv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u,v' title='u,v' class='latex' />. (b) is the Penrose diagram for the <img src='http://s0.wp.com/latex.php?latex=r+%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r &#92;geq 0' title='r &#92;geq 0' class='latex' /> Minkowski half space; this also corresponds to the Penrose diagram for the 1+3 dimensional Minkowski space after we quotient out by the spherical symmetry. Notice that the central axis <img src='http://s0.wp.com/latex.php?latex=r+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r = 0' title='r = 0' class='latex' /> is drawn slightly curved to illustrate the fact that non-null straight lines don&#8217;t necessarily map to straight lines in the compactified diagram. In (a) and (b) we see that the open circles and the dashed lines represent &#8220;idealized boundaries&#8221;, points that are not in fact in the space-time; in (b) the solid line for the central axis indicates the fact that boundary is in fact a physical region of the space-time. (c) is a representation of Figure 2 in compactified form; observe that the bottom boundary of the blue triangle is drawn slightly curved also. (d) shows the &#8220;domain of influence&#8221; of a source. In the picture the cyan ball indicates the space-time support set of the inhomogeneity. Under the assumption of either Dirichlet boundary condition (if we consider this as a 1+1 problem on the Minkowski half space) or symmetric reduction from a 1+3 dimensional problem, the pink region is the region in space-time where <em>a priori</em>, the contribution from the inhomogeneity to the solution of the wave equation can be non-zero. The larger the space-time extent of the inhomogeneity, the larger the domain of influence. </p>
<p><strong>Nonlinear tails: an example</strong></p>
<p>Be start by giving the motivation for the construction. Consider the following Penrose diagram, in which we study the future evolution of some wave equation in 1+1 dimensional space with Dirichlet boundary (which could be the symmetry reduction of a spherically symmetric wave equation in 1+3 dimensional Minkowski space).</p>
<div id="attachment_693" class="wp-caption alignnone" style="width: 264px"><a href="http://williewong.files.wordpress.com/2011/05/illustration4.png"><img src="http://williewong.files.wordpress.com/2011/05/illustration4.png" alt="" title="Illustration4" width="254" height="352" class="size-full wp-image-693" /></a><p class="wp-caption-text">Figure 4</p></div>
<p>The initial data is prescribed to be only non-vanishing on the blue line. So if we were to solve the purely linear homogeneous problem, using what we discussed in the previous post in the series, we see that the initial data splits into an incoming part, which approaches the central axis, bounces off, and then radiates to infinity; and an outgoing part which immediately radiates outward. And as we described before, following any future directed time like curve (which can be represented by a curve converging to the top open circle, the &#8220;future timelike infinity&#8221;) we will eventually escape the region influenced by this data. </p>
<p>Equivalently, we can consider the value of the solution at a point in the space time (here the red dot). Using the representation given by Duhamel&#8217;s principle, we see that for the inhomogeneous wave equation with possible source term, the solution can only be non-vanishing at the red dot if the initial data and any inhomogeneities have space-time support that intersects the crosshatched region. So for our linear homogeneous problem, where the initial data (blue curve) does not intersect the crosshatched set determined by strong Huygens&#8217; principle, at the red dot the solution would vanish. </p>
<p>Now suppose that instead of an outside source, we impose a nonlinear self-interaction on the right hand side. That is, the source term is assumed to be generated from non-linear effects of the wave itself. To be slightly more precise, assume our equation takes the form</p>
<blockquote><p><strong>Equation 20</strong><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cphi%28t%2Cx%29+%2B+%5Ctriangle%5Cphi%28t%2Cx%29+%3D+F%5Ccirc%5Cphi%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;phi(t,x) + &#92;triangle&#92;phi(t,x) = F&#92;circ&#92;phi(t,x)' title='-&#92;partial_t^2 &#92;phi(t,x) + &#92;triangle&#92;phi(t,x) = F&#92;circ&#92;phi(t,x)' class='latex' />
</p></blockquote>
<p>where <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> is now only a function of the value of the displacement <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />, with <img src='http://s0.wp.com/latex.php?latex=F%280%29+%3D+F%27%280%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F(0) = F&#039;(0) = 0' title='F(0) = F&#039;(0) = 0' class='latex' /> (these conditions ensure that the interaction is non-linear, and that waves won&#8217;t be spontaneously generated from 0 initial data; in other words, 0 is still a solution to the equation). </p>
<p>Now, because the interaction is nonlinear, if <img src='http://s0.wp.com/latex.php?latex=%5Cphi+%3D+O%28%5Cepsilon%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi = O(&#92;epsilon)' title='&#92;phi = O(&#92;epsilon)' class='latex' /> is small, we can expect, by Taylor expanding <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' />, that the source term contribution would be <img src='http://s0.wp.com/latex.php?latex=F%28%5Cphi%29+%3D+O%28%5Cepsilon%5E2%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F(&#92;phi) = O(&#92;epsilon^2)' title='F(&#92;phi) = O(&#92;epsilon^2)' class='latex' />, which is even smaller. Thus intuitively we expect to be able to solve the equation using <em>successive approximation</em>, namely: we start with the given initial data <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' />, we solve the <em>homogeneous wave equation</em> for it, and call the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_0' title='&#92;phi_0' class='latex' />. Then we run through the following iterative procedure:</p>
<ol>
<li>We are fed the solution from the previous iterate, <img src='http://s0.wp.com/latex.php?latex=%5Cphi_n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_n' title='&#92;phi_n' class='latex' />.
<li>We solve the inhomogeneous wave equation with prescribed source: <img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cphi_%7Bn%2B1%7D+%2B+%5Ctriangle+%5Cphi_%7Bn%2B1%7D+%3D+F%5Ccirc+%5Cphi_n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;phi_{n+1} + &#92;triangle &#92;phi_{n+1} = F&#92;circ &#92;phi_n' title='-&#92;partial_t^2 &#92;phi_{n+1} + &#92;triangle &#92;phi_{n+1} = F&#92;circ &#92;phi_n' class='latex' /> subject to the initial data <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' />. Notice that on the right hand side, the source is given by <img src='http://s0.wp.com/latex.php?latex=%5Cphi_n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_n' title='&#92;phi_n' class='latex' />, with on the left hand side, we are solving for <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_{n+1}' title='&#92;phi_{n+1}' class='latex' />. So we can directly obtain an integral expression using Duhamel&#8217;s principle.
<li>Feed <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_{n+1}' title='&#92;phi_{n+1}' class='latex' /> into this algorithm and repeat.
</ol>
<p>If this approximation scheme converges, then we will have that <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%7B%5Cinfty%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_{&#92;infty}' title='&#92;phi_{&#92;infty}' class='latex' />, the limiting function, will solve the nonlinear equation. (See Appendix for a bit more details.)</p>
<p>Let us consider for now the first iterate, which is enough to give a heuristic demonstration of why nonlinear tails are generic, and that the complete vanishing of waves within finite time that is possible in the linear system is very unstable. </p>
<p>Going back to Figure 4, suppose the initial data is precisely supported on the blue line. Then the 0th iterate, <img src='http://s0.wp.com/latex.php?latex=%5Cphi_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_0' title='&#92;phi_0' class='latex' />, just solves the linear homogeneous wave equation, and so its support set is represented by the cyan region, and the red dot lies outside of it. But now let us consider the first iterate. It solves the wave equation with source term <img src='http://s0.wp.com/latex.php?latex=F%5Ccirc+%5Cphi_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F&#92;circ &#92;phi_0' title='F&#92;circ &#92;phi_0' class='latex' />! So in particular, while it is true that the crosshatched region does not intersection the initial data (so there is no contribution to <img src='http://s0.wp.com/latex.php?latex=%5Cphi_1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_1' title='&#92;phi_1' class='latex' /> at the red dot coming from the prescribed initial value <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' />), the region <em>does</em> intersect the cyan set, on which our inhomogeneity does not identically vanish. And if the homogeneity is assumed to take only non-negative values (for example <img src='http://s0.wp.com/latex.php?latex=F%28%5Cphi%29+%3D+%7C%5Cphi%7C%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F(&#92;phi) = |&#92;phi|^2' title='F(&#92;phi) = |&#92;phi|^2' class='latex' />), then it is necessary that <img src='http://s0.wp.com/latex.php?latex=%5Cphi_1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_1' title='&#92;phi_1' class='latex' /> is nonvanishing at the red dot. Since the position of the red dot is more or less arbitrary, we see that at the level of the first iterate, we already expect some nonlinear tails.</p>
<p><strong>Appendix: successive approximation and local existence of solutions for nonlinear problems</strong></p>
<p>Observe that using Duhamel&#8217;s principle we have a very precise control of the rate of convergence. Consider the difference <img src='http://s0.wp.com/latex.php?latex=%5Cpsi_%7Bn%2B1%7D+%3D+%5Cphi_%7Bn%2B1%7D+-+%5Cphi_n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi_{n+1} = &#92;phi_{n+1} - &#92;phi_n' title='&#92;psi_{n+1} = &#92;phi_{n+1} - &#92;phi_n' class='latex' />. It solves the wave equation</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2%5Cpsi_%7Bn%2B1%7D+%2B+%5Ctriangle+%5Cpsi_%7Bn%2B1%7D+%3D+F%5Ccirc+%5Cphi_n+-+F%5Ccirc+%5Cphi_%7Bn-1%7D+%3D+F+%5Ccirc+%28%5Cphi_%7Bn-1%7D+%2B+%5Cpsi_n%29+-+F%5Ccirc+%5Cphi_%7Bn-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2&#92;psi_{n+1} + &#92;triangle &#92;psi_{n+1} = F&#92;circ &#92;phi_n - F&#92;circ &#92;phi_{n-1} = F &#92;circ (&#92;phi_{n-1} + &#92;psi_n) - F&#92;circ &#92;phi_{n-1}' title='-&#92;partial_t^2&#92;psi_{n+1} + &#92;triangle &#92;psi_{n+1} = F&#92;circ &#92;phi_n - F&#92;circ &#92;phi_{n-1} = F &#92;circ (&#92;phi_{n-1} + &#92;psi_n) - F&#92;circ &#92;phi_{n-1}' class='latex' />
</p></blockquote>
<p>with 0 initial condition. The right hand side we again use Taylor expansion (assuming that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi_n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi_n' title='&#92;psi_n' class='latex' /> is small), to replace by </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=F+%5Ccirc+%28%5Cphi_%7Bn-1%7D+%2B+%5Cpsi_n%29+-+F%5Ccirc+%5Cphi_%7Bn-1%7D+%3D+F%27%5Ccirc+%5Cphi_%7Bn-1%7D+%5Ccdot+%5Cpsi_n&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F &#92;circ (&#92;phi_{n-1} + &#92;psi_n) - F&#92;circ &#92;phi_{n-1} = F&#039;&#92;circ &#92;phi_{n-1} &#92;cdot &#92;psi_n' title='F &#92;circ (&#92;phi_{n-1} + &#92;psi_n) - F&#92;circ &#92;phi_{n-1} = F&#039;&#92;circ &#92;phi_{n-1} &#92;cdot &#92;psi_n' class='latex' />
</p></blockquote>
<p>But since <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%7Bn-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_{n-1}' title='&#92;phi_{n-1}' class='latex' /> is also small, we can approximate <img src='http://s0.wp.com/latex.php?latex=F%27%5Ccirc+%5Cphi_%7Bn-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F&#039;&#92;circ &#92;phi_{n-1}' title='F&#039;&#92;circ &#92;phi_{n-1}' class='latex' /> by <img src='http://s0.wp.com/latex.php?latex=F%27%280%29+%2B+O%28%5Cphi_%7Bn-1%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F&#039;(0) + O(&#92;phi_{n-1})' title='F&#039;(0) + O(&#92;phi_{n-1})' class='latex' />. So by the assumption that <img src='http://s0.wp.com/latex.php?latex=F%27%280%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F&#039;(0) = 0' title='F&#039;(0) = 0' class='latex' />, we see that the source term is small. In particular, applying Duhamel&#8217;s principle again, using that the integral used to factor in the inhomogeneity is taken over a finite space-time region, we have that </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Csup_%7Bt%5Cin+%5B0%2CT%5D%7D%5Csup_%7Bx%7D%7C%5Cpsi_%7Bn%2B1%7D%28t%2Cx%29%7C+%5Cleq+C_T+O%28%5Cphi_%7Bn-1%7D%29+%5Csup_%7Bt%5Cin%5B0%2CT%5D%7D%5Csup_%7Bx%7D+%7C%5Cpsi_n%28t%2Cx%29%7C+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;sup_{t&#92;in [0,T]}&#92;sup_{x}|&#92;psi_{n+1}(t,x)| &#92;leq C_T O(&#92;phi_{n-1}) &#92;sup_{t&#92;in[0,T]}&#92;sup_{x} |&#92;psi_n(t,x)| ' title='&#92;sup_{t&#92;in [0,T]}&#92;sup_{x}|&#92;psi_{n+1}(t,x)| &#92;leq C_T O(&#92;phi_{n-1}) &#92;sup_{t&#92;in[0,T]}&#92;sup_{x} |&#92;psi_n(t,x)| ' class='latex' />
</p></blockquote>
<p>where the constant <img src='http://s0.wp.com/latex.php?latex=C_T&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C_T' title='C_T' class='latex' /> depends only on the maximum time <img src='http://s0.wp.com/latex.php?latex=T&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='T' title='T' class='latex' />. Using that <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%7Bn-1%7D+%3D+%5Cphi_0+%2B+%5Csum_%7Bj+%3D+1%7D%5E%7Bn-1%7D+%5Cpsi_j&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_{n-1} = &#92;phi_0 + &#92;sum_{j = 1}^{n-1} &#92;psi_j' title='&#92;phi_{n-1} = &#92;phi_0 + &#92;sum_{j = 1}^{n-1} &#92;psi_j' class='latex' />, we see that <img src='http://s0.wp.com/latex.php?latex=%5Cphi_%5Cinfty+%3D+%5Cphi_0+%2B+%5Csum+%5Cpsi_j&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi_&#92;infty = &#92;phi_0 + &#92;sum &#92;psi_j' title='&#92;phi_&#92;infty = &#92;phi_0 + &#92;sum &#92;psi_j' class='latex' /> is in fact controlled by a geometric series, and the series converges if <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' /> is bounded by an <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;epsilon' title='&#92;epsilon' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=C_T%5Cepsilon&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C_T&#92;epsilon' title='C_T&#92;epsilon' class='latex' /> is less than, say, 1/100. </p>
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			<media:title type="html">Willie</media:title>
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		<title>Decay of waves IIa: Minkowski background, homogeneous case</title>
		<link>http://williewong.wordpress.com/2011/05/12/decay-of-waves-iia-minkowski-background-homogeneous-case/</link>
		<comments>http://williewong.wordpress.com/2011/05/12/decay-of-waves-iia-minkowski-background-homogeneous-case/#comments</comments>
		<pubDate>Thu, 12 May 2011 18:53:57 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[Maths]]></category>
		<category><![CDATA[partial differential equations]]></category>
		<category><![CDATA[Requires upper level university maths]]></category>
		<category><![CDATA[wave and Schroedinger equations]]></category>

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		<description><![CDATA[Now let us get into the mathematics. The wave equations that we will consider take the form Equation 1 where is a real valued function defined on (1+n)-dimensional Minkowski space that describes our solution, and represents a &#8220;source&#8221; term. When vanishes identically, we say that we are looking at the linear, homogeneous wave equation. When [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=648&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Now let us get into the mathematics. The wave equations that we will consider take the form </p>
<blockquote><p><strong>Equation 1</strong><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cphi+%2B+%5Ctriangle+%5Cphi+%3D+F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;phi + &#92;triangle &#92;phi = F' title='-&#92;partial_t^2 &#92;phi + &#92;triangle &#92;phi = F' class='latex' />
</p></blockquote>
<p>where <img src='http://s0.wp.com/latex.php?latex=%5Cphi%3A%5Cmathbb%7BR%7D%5E%7B1%2Bn%7D%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi:&#92;mathbb{R}^{1+n}&#92;to&#92;mathbb{R}' title='&#92;phi:&#92;mathbb{R}^{1+n}&#92;to&#92;mathbb{R}' class='latex' /> is a real valued function defined on (1+n)-dimensional Minkowski space that describes our solution, and <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> represents a &#8220;source&#8221; term. When <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> vanishes identically, we say that we are looking at the linear, homogeneous wave equation. When <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> is itself a function of <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and its first derivatives, we say that the equation is a semilinear wave equation. </p>
<p>We first start with the homogeneous, linear case. </p>
<p><strong>Homogeneous wave equation in one spatial dimension</strong></p>
<p>One interesting aspect of the wave equation is that it only possesses the second, multidimensional, dispersive mechanism <a href="http://williewong.wordpress.com/2011/05/05/decay-of-waves-i-introduction/">as described in my previous post</a>. In physical parlance, the &#8220;phase velocity&#8221; and the &#8220;group velocity&#8221; of the wave equation are the same. And therefore, a solution of the wave equation, quite unlike a solution of the Schroedinger equation, will not exhibit decay when there is only one spatial dimension (mathematically this is one significant difference between <em>relativistic</em> and <em>quantum</em> mechanics). In this section we make a computation to demonstrate this, a fact that would also be useful later on when we look at higher (in particular, three) dimensions. </p>
<p>Use <img src='http://s0.wp.com/latex.php?latex=x%5Cin%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x&#92;in&#92;mathbb{R}' title='x&#92;in&#92;mathbb{R}' class='latex' />  for the variable representing spatial position. The wave equation can be written as</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cphi+%2B+%5Cpartial_x%5E2%5Cphi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;phi + &#92;partial_x^2&#92;phi = 0' title='-&#92;partial_t^2 &#92;phi + &#92;partial_x^2&#92;phi = 0' class='latex' />
</p></blockquote>
<p>Now we perform a change of variables: let <img src='http://s0.wp.com/latex.php?latex=u+%3D+%5Cfrac%7B1%7D%7B2%7D%28t-x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u = &#92;frac{1}{2}(t-x)' title='u = &#92;frac{1}{2}(t-x)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=v+%3D+%5Cfrac%7B1%7D%7B2%7D%28t%2Bx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v = &#92;frac{1}{2}(t+x)' title='v = &#92;frac{1}{2}(t+x)' class='latex' /> be the <em>canonical null variables</em>. The change of variable formula replaces </p>
<blockquote><p><strong>Equation 2</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_t+%5Cto+%5Cfrac%7B%5Cpartial+u%7D%7B%5Cpartial+t%7D+%5Cpartial_u+%2B+%5Cfrac%7B%5Cpartial+v%7D%7B%5Cpartial+t%7D+%5Cpartial+v+%3D+%5Cfrac%7B1%7D%7B2%7D%5Cpartial_u+%2B+%5Cfrac%7B1%7D%7B2%7D%5Cpartial_v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;partial_t &#92;to &#92;frac{&#92;partial u}{&#92;partial t} &#92;partial_u + &#92;frac{&#92;partial v}{&#92;partial t} &#92;partial v = &#92;frac{1}{2}&#92;partial_u + &#92;frac{1}{2}&#92;partial_v' title='&#92;displaystyle &#92;partial_t &#92;to &#92;frac{&#92;partial u}{&#92;partial t} &#92;partial_u + &#92;frac{&#92;partial v}{&#92;partial t} &#92;partial v = &#92;frac{1}{2}&#92;partial_u + &#92;frac{1}{2}&#92;partial_v' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cpartial_x+%5Cto+%5Cfrac%7B%5Cpartial+u%7D%7B%5Cpartial+x%7D+%5Cpartial_u+%2B+%5Cfrac%7B%5Cpartial+v%7D%7B%5Cpartial+x%7D+%5Cpartial+v+%3D+-%5Cfrac%7B1%7D%7B2%7D%5Cpartial_u+%2B+%5Cfrac%7B1%7D%7B2%7D%5Cpartial_v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;partial_x &#92;to &#92;frac{&#92;partial u}{&#92;partial x} &#92;partial_u + &#92;frac{&#92;partial v}{&#92;partial x} &#92;partial v = -&#92;frac{1}{2}&#92;partial_u + &#92;frac{1}{2}&#92;partial_v' title='&#92;displaystyle &#92;partial_x &#92;to &#92;frac{&#92;partial u}{&#92;partial x} &#92;partial_u + &#92;frac{&#92;partial v}{&#92;partial x} &#92;partial v = -&#92;frac{1}{2}&#92;partial_u + &#92;frac{1}{2}&#92;partial_v' class='latex' />
</p></blockquote>
<p>and we get that in the <img src='http://s0.wp.com/latex.php?latex=%28u%2Cv%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(u,v)' title='(u,v)' class='latex' /> coordinate system, </p>
<blockquote><p><strong>Equation 3</strong><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_u+%5Cpartial_v+%5Cphi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_u &#92;partial_v &#92;phi = 0' title='-&#92;partial_u &#92;partial_v &#92;phi = 0' class='latex' />
</p></blockquote>
<p><span id="more-648"></span></p>
<p>Equation 3 implies that the derivatives of <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> solve transport/ordinary differential equations. More precisely, it says that <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v&#92;phi' title='&#92;partial_v&#92;phi' class='latex' /> is independent of <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u' title='u' class='latex' />, and using the commutation of second derivatives, <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u&#92;phi' title='&#92;partial_u&#92;phi' class='latex' /> is independent of <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' />. Hence on each instant in time <img src='http://s0.wp.com/latex.php?latex=u%2Bv+%3D+%5Ctau&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='u+v = &#92;tau' title='u+v = &#92;tau' class='latex' />, the maximum value of <img src='http://s0.wp.com/latex.php?latex=%7C%5Cpartial_v%5Cphi%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|&#92;partial_v&#92;phi|' title='|&#92;partial_v&#92;phi|' class='latex' /> and the maximum value of <img src='http://s0.wp.com/latex.php?latex=%7C%5Cpartial_u%5Cphi%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|&#92;partial_u&#92;phi|' title='|&#92;partial_u&#92;phi|' class='latex' /> are independent of <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />. Which is the first indication that we do not have amplitude decay. </p>
<p>To be more explicit, we can derive an explicit representation of the solution to the initial value problem. Assume that at time <img src='http://s0.wp.com/latex.php?latex=t+%3D+0+%3D+u%2Bv&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t = 0 = u+v' title='t = 0 = u+v' class='latex' />, we have that <img src='http://s0.wp.com/latex.php?latex=%5Cphi%280%2Cx%29+%3D+f%28x%29%2C+%5Cpartial_t%5Cphi%280%2Cx%29+%3D+g%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(0,x) = f(x), &#92;partial_t&#92;phi(0,x) = g(x)' title='&#92;phi(0,x) = f(x), &#92;partial_t&#92;phi(0,x) = g(x)' class='latex' />. We can decompose <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' /> into <em>forward</em> and <em>backward</em> traveling waves </p>
<blockquote><p><strong>Equation 4</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29+%3D+%28f_%2B%2Cg_%2B%29+%2B+%28f_-%2C+g_-%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g) = (f_+,g_+) + (f_-, g_-)' title='(f,g) = (f_+,g_+) + (f_-, g_-)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_xf_%2B+%2B+g_%2B+%3D+0+%3D+-%5Cpartial_x+f_-+%2B+g_-&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_xf_+ + g_+ = 0 = -&#92;partial_x f_- + g_-' title='&#92;partial_xf_+ + g_+ = 0 = -&#92;partial_x f_- + g_-' class='latex' />
</p></blockquote>
<p>The second conditions guarantee that the corresponding solution decomposition (by linearity of the Equation 1) <img src='http://s0.wp.com/latex.php?latex=%5Cphi+%3D+%5Cphi_%2B+%2B+%5Cphi_-&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi = &#92;phi_+ + &#92;phi_-' title='&#92;phi = &#92;phi_+ + &#92;phi_-' class='latex' /> satisfies <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_v+%5Cphi_%2B+%3D+0+%3D+%5Cpartial_u+%5Cphi_-&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_v &#92;phi_+ = 0 = &#92;partial_u &#92;phi_-' title='&#92;partial_v &#92;phi_+ = 0 = &#92;partial_u &#92;phi_-' class='latex' />. So we can write</p>
<blockquote><p><strong>Equation 5</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cphi%28t%2Cx%29+%3D+%5Cphi_%2B%28t%2Cx%29+%2B+%5Cphi_-%28t%2Cx%29+%3D+%5Cphi_%2B%280%2Cx-t%29+%2B+%5Cphi_-%280%2Cx%2Bt%29+%3D+f_%2B%28x-t%29+%2B+f_-%28x%2Bt%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(t,x) = &#92;phi_+(t,x) + &#92;phi_-(t,x) = &#92;phi_+(0,x-t) + &#92;phi_-(0,x+t) = f_+(x-t) + f_-(x+t)' title='&#92;phi(t,x) = &#92;phi_+(t,x) + &#92;phi_-(t,x) = &#92;phi_+(0,x-t) + &#92;phi_-(0,x+t) = f_+(x-t) + f_-(x+t)' class='latex' />
</p></blockquote>
<p>Solving for the algebraic conditions in Equation 4, we have <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_x+f_%7B%5Cpm%7D+%5Cmp+g_%7B%5Cpm%7D+%3D+%5Cpartial_x+f+%5Cmp+g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_x f_{&#92;pm} &#92;mp g_{&#92;pm} = &#92;partial_x f &#92;mp g' title='&#92;partial_x f_{&#92;pm} &#92;mp g_{&#92;pm} = &#92;partial_x f &#92;mp g' class='latex' /> which implies</p>
<blockquote><p><strong>Equation 6</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+f_%7B%5Cpm%7D%28x%29+%3D+%5Cfrac%7B1%7D%7B2%7D%5Cleft%28f%28x%29++%5Cmp+%5Cint_%7B0%7D%5Ex+g%28y%29+dy+%5Cright%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle f_{&#92;pm}(x) = &#92;frac{1}{2}&#92;left(f(x)  &#92;mp &#92;int_{0}^x g(y) dy &#92;right)' title='&#92;displaystyle f_{&#92;pm}(x) = &#92;frac{1}{2}&#92;left(f(x)  &#92;mp &#92;int_{0}^x g(y) dy &#92;right)' class='latex' />
</p></blockquote>
<p>where the initial point of integration is fixed arbitrarily to 0. Combining this with Equation 5 we get that </p>
<blockquote><p><strong>Equation 7</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cphi%28t%2Cx%29+%3D+%5Cfrac%7B1%7D%7B2%7D%5Cleft%28+f%28x-t%29+%2B+f%28x%2Bt%29+%2B+%5Cint_%7Bx-t%7D%5E%7Bx%2Bt%7D+g%28y%29+dy+%5Cright%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;phi(t,x) = &#92;frac{1}{2}&#92;left( f(x-t) + f(x+t) + &#92;int_{x-t}^{x+t} g(y) dy &#92;right)' title='&#92;displaystyle &#92;phi(t,x) = &#92;frac{1}{2}&#92;left( f(x-t) + f(x+t) + &#92;int_{x-t}^{x+t} g(y) dy &#92;right)' class='latex' />
</p></blockquote>
<p>From this we can derive the following fact about <em>non-decay</em> of solutions to the wave equation. For simplicity we will assume our initial data <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' /> are smooth functions, and are compactly supported in the interval <img src='http://s0.wp.com/latex.php?latex=%5B-1%2C1%5D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='[-1,1]' title='[-1,1]' class='latex' />; similar statements with the usual modifications can be had if we assume <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' /> are Schwartz distributions with sufficiently fast decay. </p>
<p>First we consider the statement with fixed <img src='http://s0.wp.com/latex.php?latex=x+%3D+x_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x = x_0' title='x = x_0' class='latex' />. By assumption of compact support, for <img src='http://s0.wp.com/latex.php?latex=t+%3E+%7Cx_0%7C+%2B+1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t &gt; |x_0| + 1' title='t &gt; |x_0| + 1' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=f%28x_0+-+t%29+%3D+f%28x_0+%2B+t%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f(x_0 - t) = f(x_0 + t) = 0' title='f(x_0 - t) = f(x_0 + t) = 0' class='latex' />. And in this case the solution becomes</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cphi%28t+%3E+%7Cx_0%7C+%2B+1%2C+x_0%29+%3D+%5Cfrac%7B1%7D%7B2%7D%5Cint_%7B-1%7D%5E%7B1%7D+g%28y%29+dy&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;phi(t &gt; |x_0| + 1, x_0) = &#92;frac{1}{2}&#92;int_{-1}^{1} g(y) dy' title='&#92;displaystyle &#92;phi(t &gt; |x_0| + 1, x_0) = &#92;frac{1}{2}&#92;int_{-1}^{1} g(y) dy' class='latex' />
</p></blockquote>
<p>In fact, a modification of the same argument shows that if <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3A%5Cmathbb%7BR%7D%5Cto%5Cmathbb%7BR%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;gamma:&#92;mathbb{R}&#92;to&#92;mathbb{R}' title='&#92;gamma:&#92;mathbb{R}&#92;to&#92;mathbb{R}' class='latex' /> is a <img src='http://s0.wp.com/latex.php?latex=C%5E1&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='C^1' title='C^1' class='latex' />-curve such that there exists some <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon+%3E+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;epsilon &gt; 0' title='&#92;epsilon &gt; 0' class='latex' /> for which <img src='http://s0.wp.com/latex.php?latex=%7C%5Cdot%7B%5Cgamma%7D%7C+%5Cleq+1+-+%5Cepsilon&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|&#92;dot{&#92;gamma}| &#92;leq 1 - &#92;epsilon' title='|&#92;dot{&#92;gamma}| &#92;leq 1 - &#92;epsilon' class='latex' /> everywhere (so that the space-time curve <img src='http://s0.wp.com/latex.php?latex=%28t%2C%5Cgamma%28t%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(t,&#92;gamma(t))' title='(t,&#92;gamma(t))' class='latex' /> is uniformly time-like), then there is a maximum time <img src='http://s0.wp.com/latex.php?latex=%5Ctau_M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tau_M' title='&#92;tau_M' class='latex' /> (depending on <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%280%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;gamma(0)' title='&#92;gamma(0)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;epsilon' title='&#92;epsilon' class='latex' />) such that </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cphi%28t%2C+%5Cgamma%28t%29%29+%3D+%5Cfrac%7B1%7D%7B2%7D%5Cint_%7B-1%7D%5E%7B1%7D+g%28y%29+dy%5Cqquad+&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;phi(t, &#92;gamma(t)) = &#92;frac{1}{2}&#92;int_{-1}^{1} g(y) dy&#92;qquad ' title='&#92;displaystyle &#92;phi(t, &#92;gamma(t)) = &#92;frac{1}{2}&#92;int_{-1}^{1} g(y) dy&#92;qquad ' class='latex' /> for any <img src='http://s0.wp.com/latex.php?latex=%7Ct%7C+%3E+%5Ctau_M&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|t| &gt; &#92;tau_M' title='|t| &gt; &#92;tau_M' class='latex' />.
</p></blockquote>
<p>So for <em>generic</em> initial data where the total integral of <img src='http://s0.wp.com/latex.php?latex=g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g' title='g' class='latex' /> is non-vanishing, along every uniformly time-like trajectory, eventually the wave will settled down to a <em>non-zero constant</em> displacement. Furthermore, while for the case we have vanishing <img src='http://s0.wp.com/latex.php?latex=g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g' title='g' class='latex' /> integral that at every point on the line the wave will eventually settle down to 0, we have that the supremum over a time slice is never vanishing. To see this, notice that in the definition for <img src='http://s0.wp.com/latex.php?latex=f_%7B%5Cpm%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_{&#92;pm}' title='f_{&#92;pm}' class='latex' /> in Equation 6, we can instead set the lower bound of integration to <img src='http://s0.wp.com/latex.php?latex=-%5Cinfty&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;infty' title='-&#92;infty' class='latex' />. Then if <img src='http://s0.wp.com/latex.php?latex=g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g' title='g' class='latex' /> has compact support and vanishing total integral, we can write <img src='http://s0.wp.com/latex.php?latex=g+%3D+G%27&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g = G&#039;' title='g = G&#039;' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=G&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='G' title='G' class='latex' /> is a smooth function with compact support also, and <img src='http://s0.wp.com/latex.php?latex=f_%7B%5Cpm%7D+%3D+f+%5Cmp+G&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_{&#92;pm} = f &#92;mp G' title='f_{&#92;pm} = f &#92;mp G' class='latex' />. Now if <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29+%5Cnot%5Cequiv+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g) &#92;not&#92;equiv 0' title='(f,g) &#92;not&#92;equiv 0' class='latex' />, we also have <img src='http://s0.wp.com/latex.php?latex=%28f%2CG%29+%5Cnot%5Cequiv+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,G) &#92;not&#92;equiv 0' title='(f,G) &#92;not&#92;equiv 0' class='latex' />, and hence at least one of <img src='http://s0.wp.com/latex.php?latex=f_%7B%5Cpm%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_{&#92;pm}' title='f_{&#92;pm}' class='latex' /> is non-vanishing. Let <img src='http://s0.wp.com/latex.php?latex=x_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x_0' title='x_0' class='latex' /> be a point such that <img src='http://s0.wp.com/latex.php?latex=%5Cmax%28%7Cf_%2B%28x_0%29%7C%2C%7Cf_-%28x_0%29%7C%29+%3E+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;max(|f_+(x_0)|,|f_-(x_0)|) &gt; 0' title='&#92;max(|f_+(x_0)|,|f_-(x_0)|) &gt; 0' class='latex' />, then we have that</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Csup_%7Bx%7D+%5Cleft%7C%5Cphi%28t%2Cx%29%5Cright%7C+%5Cgeq+%5Cmax%28+%7C%5Cphi%28t%2C+x_0+%2B+t%29%7C%2C+%7C%5Cphi%28t%2Cx_0+-+t%29%7C%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;sup_{x} &#92;left|&#92;phi(t,x)&#92;right| &#92;geq &#92;max( |&#92;phi(t, x_0 + t)|, |&#92;phi(t,x_0 - t)|)' title='&#92;sup_{x} &#92;left|&#92;phi(t,x)&#92;right| &#92;geq &#92;max( |&#92;phi(t, x_0 + t)|, |&#92;phi(t,x_0 - t)|)' class='latex' /> <img src='http://s0.wp.com/latex.php?latex=%3D+%5Cmax%28+%7Cf_%2B%28x_0%29%7C%2C%7Cf_-%28x_0%29%7C%29+%3E+0%5Cqquad&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='= &#92;max( |f_+(x_0)|,|f_-(x_0)|) &gt; 0&#92;qquad' title='= &#92;max( |f_+(x_0)|,|f_-(x_0)|) &gt; 0&#92;qquad' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=%7Ct%7C+%3E+2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|t| &gt; 2' title='|t| &gt; 2' class='latex' />
</p></blockquote>
<p>so at each time there is lower bound (independent of time) to the maximum amplitude achieved by the wave at that time. In Figure 1 below, we illustrate the above. The initial data is supported on the <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> axis in the region highlighted in green. The pink region is where the wave settles down to the constant value given by the total integral of <img src='http://s0.wp.com/latex.php?latex=g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g' title='g' class='latex' />. The solutions in the cyan regions are given by translations of <img src='http://s0.wp.com/latex.php?latex=f_%7B%5Cpm%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_{&#92;pm}' title='f_{&#92;pm}' class='latex' />, with the right hand region depending only on the forward wave <img src='http://s0.wp.com/latex.php?latex=f_%2B&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_+' title='f_+' class='latex' />, and the left hand region on the backward wave. If <img src='http://s0.wp.com/latex.php?latex=f_%2B&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f_+' title='f_+' class='latex' /> is non-zero, then in the right hand cyan region <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_u%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_u&#92;phi' title='&#92;partial_u&#92;phi' class='latex' /> are non-zero, and independent of <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='v' title='v' class='latex' />; similarly in the left hand cyan region for the backward wave. The blue curve represents <img src='http://s0.wp.com/latex.php?latex=%28t%2C%5Cgamma%28t%29%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(t,&#92;gamma(t))' title='(t,&#92;gamma(t))' class='latex' />, a time-like trajectory that eventually enters the &#8220;interior&#8221; pink region.  <div id="attachment_654" class="wp-caption alignnone" style="width: 404px"><a href="http://williewong.files.wordpress.com/2011/05/illustration1.png"><img src="http://williewong.files.wordpress.com/2011/05/illustration1.png" alt="" title="Domain of dependence 1+1" width="394" height="343" class="size-full wp-image-654" /></a><p class="wp-caption-text">Figure 1</p></div></p>
<p>In this picture, the lack of dispersion can be seen in the fact that the cross sectional area at each fixed time of the cyan-colored &#8220;wave zone&#8221; (remember that outside this wave zone the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is constant) is bounded above by twice the area of the support of the initial data <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' />. </p>
<p><strong>Dirichlet boundary in one spatial dimension</strong></p>
<p>Before moving on to higher dimensions, we will have to first consider one dimensional waves on a one-sided domain with Dirichlet boundary conditions. To be more precise, we now take <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> to be a function of time and space, where the spatial parameter runs from <img src='http://s0.wp.com/latex.php?latex=%5B0%2C%5Cinfty%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='[0,&#92;infty)' title='[0,&#92;infty)' class='latex' />. When an equation is prescribed on a domain with boundary, we need to also specify how the wave must behave at the boundary. For purposes of application to higher dimensions, we will consider the case of Dirichlet boundary condition, which states that <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28t%2C0%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(t,0) = 0' title='&#92;phi(t,0) = 0' class='latex' /> for all time. Physically this represents a wave bouncing off a hard boundary (like, say, sound waves bouncing off a wall). </p>
<p>One can try to solve the equation directly and impose the Dirichlet boundary condition. But it may be more instructive to use this opportunity to illustrate the principle of using <em>symmetry</em> properties to our aid. Notice that the homogeneous linear wave equation, by virtue of its linearity, has the principle of superposition. So one way of dealing with the Dirichlet boundary condition is to <em>extend</em> the spatial domain to negative values of <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> and <em>mirror</em> the solution about the origin. To be more precise:</p>
<p>Let us take <img src='http://s0.wp.com/latex.php?latex=%28f%2Cg%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(f,g)' title='(f,g)' class='latex' /> to be initial data, compactly supported in <img src='http://s0.wp.com/latex.php?latex=%280%2C%5Cinfty%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(0,&#92;infty)' title='(0,&#92;infty)' class='latex' />, to the <em>initial boundary value problem</em> with <em>Dirichlet</em> boundary conditions at <img src='http://s0.wp.com/latex.php?latex=x+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x = 0' title='x = 0' class='latex' />. Instead of dealing with the boundary condition, we can instead consider the <em>initial value problem</em> on the whole real line (as discussed with previous section) for the wave equation, with initial data <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde%7Bf%7D%2C%5Ctilde%7Bg%7D%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(&#92;tilde{f},&#92;tilde{g})' title='(&#92;tilde{f},&#92;tilde{g})' class='latex' /> given by</p>
<blockquote><p><strong>Equation 8</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde%7Bf%7D%2C%5Ctilde%7Bg%7D%29%28x%29+%3D+%28f%2Cg%29%28x%29%5Cqquad&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(&#92;tilde{f},&#92;tilde{g})(x) = (f,g)(x)&#92;qquad' title='(&#92;tilde{f},&#92;tilde{g})(x) = (f,g)(x)&#92;qquad' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=x+%3E+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x &gt; 0' title='x &gt; 0' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde%7Bf%7D%2C%5Ctilde%7Bg%7D%29%28x%29+%3D+%28-f%2C-g%29%28-x%29%5Cqquad&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(&#92;tilde{f},&#92;tilde{g})(x) = (-f,-g)(-x)&#92;qquad' title='(&#92;tilde{f},&#92;tilde{g})(x) = (-f,-g)(-x)&#92;qquad' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=x+%3C+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x &lt; 0' title='x &lt; 0' class='latex' />
</p></blockquote>
<p>One can easily check that the solution <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7B%5Cphi%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{&#92;phi}' title='&#92;tilde{&#92;phi}' class='latex' /> to this modified problem vanishes identically at <img src='http://s0.wp.com/latex.php?latex=x+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x = 0' title='x = 0' class='latex' />. And so if we restrict <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7B%5Cphi%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{&#92;phi}' title='&#92;tilde{&#92;phi}' class='latex' /> to the positive half line, it is in fact a solution to the Dirichlet initial boundary value problem that we started with. (To show that this is the only possible solution requires a bit of care, but can be done; we&#8217;ll omit it here.)</p>
<p>(Interesting to note that if instead of Equation 8 we take <img src='http://s0.wp.com/latex.php?latex=%28%5Ctilde%7Bf%7D%2C%5Ctilde%7Bg%7D%29%28x%29+%3D+%28f%2Cg%29%28-x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(&#92;tilde{f},&#92;tilde{g})(x) = (f,g)(-x)' title='(&#92;tilde{f},&#92;tilde{g})(x) = (f,g)(-x)' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=x++%3C+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x  &lt; 0' title='x  &lt; 0' class='latex' />, we would solve the corresponding <em>Neumann</em> initial boundary value problem, where the boundary condition is <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_x%5Cphi%28t%2C0%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_x&#92;phi(t,0) = 0' title='&#92;partial_x&#92;phi(t,0) = 0' class='latex' />. This physically corresponds to the case where the medium is completely flexible at the boundary.)</p>
<p>One particularly nice aspect of this way of looking at the Dirichlet problem is that we can apply the previous results on wave equations on the whole real line. In particular, by construction the initial data <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7Bg%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tilde{g}' title='&#92;tilde{g}' class='latex' /> must have vanishing total integral. So for any fixed <img src='http://s0.wp.com/latex.php?latex=x_0+%5Cgeq+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x_0 &#92;geq 0' title='x_0 &#92;geq 0' class='latex' />, we can find some finite time <img src='http://s0.wp.com/latex.php?latex=%5Ctau&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;tau' title='&#92;tau' class='latex' /> such that we will have <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28t%2Cx_0%29+%3D+%5Ctilde%7B%5Cphi%7D%28t%2Cx_0%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(t,x_0) = &#92;tilde{&#92;phi}(t,x_0) = 0' title='&#92;phi(t,x_0) = &#92;tilde{&#92;phi}(t,x_0) = 0' class='latex' /> for any <img src='http://s0.wp.com/latex.php?latex=%7Ct%7C+%3E+%5Ctau&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|t| &gt; &#92;tau' title='|t| &gt; &#92;tau' class='latex' />. </p>
<p><strong>The homogeneous case with 3 spatial dimensions</strong></p>
<p>The more physically interesting case is when we have 3 spatial dimensions, which agrees with our intuitive understanding of the world. For convenience of the discussion, we will restrict ourselves to considering <em>spherically symmetric</em> functions; this is in general sufficient to give the intuition behind what I want to discuss. In the particular case of Minkowski space, one can also transfer, using the method of spherical means, the discussion here about spherically symmetric to statements about the <em>fundamental solution</em>, and hence also statements about general solutions of the linear homogeneous wave equation. To how see this pans out, a good reference is <a href="http://www.math.ntnu.no/~sselberg/">Sigmund Selberg&#8217;s Johns Hopkins lecture notes on wave equations</a>. </p>
<p>First let us consider the reduction of the linear wave equation. In three dimensions, we can write the <a href="http://en.wikipedia.org/wiki/Spherical_coordinate_system#Integration_and_differentiation_in_spherical_coordinates">Laplace operator in spherical coordinates</a> <img src='http://s0.wp.com/latex.php?latex=%28r%2C%5Comega%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='(r,&#92;omega)' title='(r,&#92;omega)' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=r%5Cin+%5Cmathbb%7BR%7D_%2B&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r&#92;in &#92;mathbb{R}_+' title='r&#92;in &#92;mathbb{R}_+' class='latex' /> is the radial coordinate and <img src='http://s0.wp.com/latex.php?latex=%5Comega+%5Cin+%5Cmathbb%7BS%7D%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;omega &#92;in &#92;mathbb{S}^2' title='&#92;omega &#92;in &#92;mathbb{S}^2' class='latex' /> represents some 2-dimensional coordinate system on the unit sphere (its exact form is unimportant, since we will be working in spherical symmetry). </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctriangle+%5Cphi+%3D+%5Cfrac%7B1%7D%7Br%5E2%7D+%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+r%7D+r%5E2+%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+r%7D%5Cphi+%2B+%5Cfrac%7B1%7D%7Br%5E2%7D+%5COmega%5E2%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;triangle &#92;phi = &#92;frac{1}{r^2} &#92;frac{&#92;partial}{&#92;partial r} r^2 &#92;frac{&#92;partial}{&#92;partial r}&#92;phi + &#92;frac{1}{r^2} &#92;Omega^2&#92;phi' title='&#92;displaystyle &#92;triangle &#92;phi = &#92;frac{1}{r^2} &#92;frac{&#92;partial}{&#92;partial r} r^2 &#92;frac{&#92;partial}{&#92;partial r}&#92;phi + &#92;frac{1}{r^2} &#92;Omega^2&#92;phi' class='latex' />
</p></blockquote>
<p>where we use <img src='http://s0.wp.com/latex.php?latex=%5COmega%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega^2' title='&#92;Omega^2' class='latex' /> to denote the <em>induced Laplace operator on the unit sphere</em>. In spherical symmetry, <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28r%2C%5Comega%29+%3D+%5Cphi%28r%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(r,&#92;omega) = &#92;phi(r)' title='&#92;phi(r,&#92;omega) = &#92;phi(r)' class='latex' /> is independent of the spherical coordinates, so any derivatives tangential to the sphere vanish, in particular <img src='http://s0.wp.com/latex.php?latex=%5COmega%5E2%5Cphi+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Omega^2&#92;phi = 0' title='&#92;Omega^2&#92;phi = 0' class='latex' />. We can do a further simplification, however. Consider the function <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%3D+r%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi = r&#92;phi' title='&#92;psi = r&#92;phi' class='latex' />. We have that </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r%5Cpartial_r+%5Cpsi+%3D+%5Cpartial_r+%28r+%5Cpartial_r%5Cphi+%2B+%5Cphi%29+%3D+r+%5Cpartial_r%5Cpartial_r%5Cphi+%2B+2+%5Cpartial_r+%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_r&#92;partial_r &#92;psi = &#92;partial_r (r &#92;partial_r&#92;phi + &#92;phi) = r &#92;partial_r&#92;partial_r&#92;phi + 2 &#92;partial_r &#92;phi' title='&#92;partial_r&#92;partial_r &#92;psi = &#92;partial_r (r &#92;partial_r&#92;phi + &#92;phi) = r &#92;partial_r&#92;partial_r&#92;phi + 2 &#92;partial_r &#92;phi' class='latex' />
</p></blockquote>
<p>while</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cpartial_r+r%5E2+%5Cpartial_r+%5Cphi+%3D+2+r+%5Cpartial_r+%5Cphi+%2B+r%5E2+%5Cpartial_r%5Cpartial_r+%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_r r^2 &#92;partial_r &#92;phi = 2 r &#92;partial_r &#92;phi + r^2 &#92;partial_r&#92;partial_r &#92;phi' title='&#92;partial_r r^2 &#92;partial_r &#92;phi = 2 r &#92;partial_r &#92;phi + r^2 &#92;partial_r&#92;partial_r &#92;phi' class='latex' />
</p></blockquote>
<p>so we have that, for a spherically symmetric function <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />, </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctriangle+%5Cphi+%3D+%5Cfrac%7B1%7D%7Br%7D+%5Cpartial_r%5E2+%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;triangle &#92;phi = &#92;frac{1}{r} &#92;partial_r^2 &#92;psi' title='&#92;displaystyle &#92;triangle &#92;phi = &#92;frac{1}{r} &#92;partial_r^2 &#92;psi' class='latex' />
</p></blockquote>
<p>On the other hand, we have that, since <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+r+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;partial_t r = 0' title='&#92;partial_t r = 0' class='latex' />, </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7Br%7D%5Cpartial_t%5E2+%5Cpsi+%3D+%5Cpartial_t%5E2+%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;frac{1}{r}&#92;partial_t^2 &#92;psi = &#92;partial_t^2 &#92;phi' title='&#92;displaystyle &#92;frac{1}{r}&#92;partial_t^2 &#92;psi = &#92;partial_t^2 &#92;phi' class='latex' />
</p></blockquote>
<p>and so we arrive at the <em>reduced wave equation</em></p>
<blockquote><p><strong>Equation 9</strong><br />
<img src='http://s0.wp.com/latex.php?latex=-%5Cpartial_t%5E2+%5Cpsi+%2B+%5Cpartial_r%5E2%5Cpsi+%3D+r+F+%5Cqquad&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='-&#92;partial_t^2 &#92;psi + &#92;partial_r^2&#92;psi = r F &#92;qquad' title='-&#92;partial_t^2 &#92;psi + &#92;partial_r^2&#92;psi = r F &#92;qquad' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%3D+r%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi = r&#92;phi' title='&#92;psi = r&#92;phi' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> solves Equation 1
</p></blockquote>
<p>Note that the choice of <em>weight</em> that one uses to define <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> is not coincidental: that we use <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> to the first power is a reflection of the typical behaviour expected of waves in three spatial dimensions. Imagine a radio wave spreading out from the radio tower. The energy density of the wave is proportional to square of the amplitude (which is why for computation of electrical power of alternating currents we use <a href="http://en.wikipedia.org/wiki/Root_mean_square">RMS</a>). But the wave propagates at roughly constant speed outwards radially. So after the wave has travelled a distance <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' />, the the spherical shell representing the wave front has area proportional to <img src='http://s0.wp.com/latex.php?latex=r%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r^2' title='r^2' class='latex' />, while the total energy is conserved. So this means that the energy density (and hence power density) drops as inverse squared of the distance from the tower. This means that <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r' title='r' class='latex' /> times the amplitude should roughly be constant. In spatial dimension <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='N' title='N' class='latex' />, the same argument gives that the expected weight should be <img src='http://s0.wp.com/latex.php?latex=r%5E%7B%5Cfrac%7BN-1%7D%7B2%7D%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r^{&#92;frac{N-1}{2}}' title='r^{&#92;frac{N-1}{2}}' class='latex' />, but the computation in general is not as simple and pretty as the three-dimensional case. </p>
<p>The important thing about Equation 9 is that <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> solves a 1 dimensional wave equation on the half plane <img src='http://s0.wp.com/latex.php?latex=t%5Cin+%28-%5Cinfty%2C%5Cinfty%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t&#92;in (-&#92;infty,&#92;infty)' title='t&#92;in (-&#92;infty,&#92;infty)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=r+%5Cin+%280%2C%5Cinfty%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r &#92;in (0,&#92;infty)' title='r &#92;in (0,&#92;infty)' class='latex' />. What are the boundary conditions? If the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> remains regular, it must remain bounded at the origin. Since <img src='http://s0.wp.com/latex.php?latex=%5Cpsi+%3D+r%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi = r&#92;phi' title='&#92;psi = r&#92;phi' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=r+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='r = 0' title='r = 0' class='latex' /> at the origin, we have that the boundary condition must be Dirichlet. So in particular, we can apply the result of the previous section to the case of the homogeneous equation, <img src='http://s0.wp.com/latex.php?latex=F+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F = 0' title='F = 0' class='latex' />. </p>
<blockquote><p><strong>Theorem 1 Strong Huygens&#8217; Principle</strong><br />
Let <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> solve the homogeneous wave equation on (1+3) dimensional Minkowski space. Suppose we have that the initial data for <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is supported within the ball of radius <img src='http://s0.wp.com/latex.php?latex=R&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='R' title='R' class='latex' /> around the origin. Then <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> must be identically vanishing in the following two regions:</p>
<ul>
<li>The <em>exterior region</em> <img src='http://s0.wp.com/latex.php?latex=%7Cx%7C+%3E+R+%2B+%7Ct%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|x| &gt; R + |t|' title='|x| &gt; R + |t|' class='latex' />.
<li>The <em>Interior region</em> <img src='http://s0.wp.com/latex.php?latex=%7Ct%7C+%3E+R+%2B+%7Cx%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|t| &gt; R + |x|' title='|t| &gt; R + |x|' class='latex' />.
</ul>
<p>In other words, the solution <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is only supported on the <em>wave zone</em> <img src='http://s0.wp.com/latex.php?latex=%5Cleft%7C+%7Ct%7C+-+%7Cx%7C+%5Cright%7C+%5Cleq+R&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;left| |t| - |x| &#92;right| &#92;leq R' title='&#92;left| |t| - |x| &#92;right| &#92;leq R' class='latex' />.
</p></blockquote>
<p>The exterior region corresponds roughly to the pink region in Figure 1, while the wave zone would be roughly the cyan regions. Note that the sketch of proof outlined above proceeds via spherical symmetry, and so we have only demonstrated that the theorem is true in the spherical symmetric case; as mentioned before by using the methods of spherical means the theorem can be shown to be true for general solutions. </p>
<p>What we have studied have two important consequences: using the results from the previous section, we see that on each constant time slice, for initial data that is compactly supported, the maximal amplitude of the wave <img src='http://s0.wp.com/latex.php?latex=%5Cpsi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;psi' title='&#92;psi' class='latex' /> is constant (after some initial time <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t_0' title='t_0' class='latex' /> to let the &#8220;incoming&#8221; and &#8220;outgoing&#8221; components of the wave separate). This means that the function of time </p>
<blockquote><p><strong>Equation 11</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csup_%7Bx%7D+%7C%5Cpsi%28t%2Cx%29%7C+%5Csim+C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sup_{x} |&#92;psi(t,x)| &#92;sim C' title='&#92;displaystyle &#92;sup_{x} |&#92;psi(t,x)| &#92;sim C' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cimplies+%5Csup_%7Bx%7D+%7C%5Cphi%28t%2Cx%29%7C+%5Cleq+%5Cfrac%7BC%7D%7B%7Ct%7C%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;implies &#92;sup_{x} |&#92;phi(t,x)| &#92;leq &#92;frac{C}{|t|}' title='&#92;displaystyle &#92;implies &#92;sup_{x} |&#92;phi(t,x)| &#92;leq &#92;frac{C}{|t|}' class='latex' />
</p></blockquote>
<p>where we use the fact that <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is supported only in the wave zone, where <img src='http://s0.wp.com/latex.php?latex=%7Ct%7C+%5Csim+%7Cx%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|t| &#92;sim |x|' title='|t| &#92;sim |x|' class='latex' />, so <img src='http://s0.wp.com/latex.php?latex=%7C%5Cpsi%7C+%3D+%7Cr%5Cphi%7C+%5Csim+%7Ct%5Cphi%7C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|&#92;psi| = |r&#92;phi| &#92;sim |t&#92;phi|' title='|&#92;psi| = |r&#92;phi| &#92;sim |t&#92;phi|' class='latex' />. So that &#8220;over all&#8221; the wave decays in amplitude like <img src='http://s0.wp.com/latex.php?latex=t%5E%7B-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t^{-1}' title='t^{-1}' class='latex' />. On the other hand, we also have the consequence of Theorem 1, which says that </p>
<blockquote><p><strong>Equation 12</strong><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cforall+x%2C+%5Cexists+%5Ctau+%3D+%5Ctau%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;forall x, &#92;exists &#92;tau = &#92;tau(x)' title='&#92;forall x, &#92;exists &#92;tau = &#92;tau(x)' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28t%2Cx%29+%3D+0&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(t,x) = 0' title='&#92;phi(t,x) = 0' class='latex' /> whenever <img src='http://s0.wp.com/latex.php?latex=%7Ct%7C+%3E+%5Ctau%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|t| &gt; &#92;tau(x)' title='|t| &gt; &#92;tau(x)' class='latex' />
</p></blockquote>
<p>so in particular <em>at any fixed point in space</em>, after waiting a sufficiently long period of time, you will eventually feel nothing but peace and quiet. </p>
<p>As it turns out, Equation 11 is <em>somewhat</em> stable: for nice inhomogeneity <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' /> (which allows certain types of non-linearities, if we assume the initial data is &#8220;small&#8221;) we can recover the <img src='http://s0.wp.com/latex.php?latex=t%5E%7B-1%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t^{-1}' title='t^{-1}' class='latex' /> decay rate. But Equation 12, however, is extremely unstable. Recall from the previous discussion the phenomenon of tails. Equation 12 basically says that for the linear, homogeneous wave equation on Minkowski space with compactly supported initial data, there can be no tails. As our intuition suggests from the previous post, if we add &#8220;obstacles&#8221; or &#8220;sources&#8221; (which can be captured in the function <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='F' title='F' class='latex' />) there will be backscattering from the out going waves, and this will lead to some waves persisting after long periods of time. Furthermore, Equation 12 also strongly depends on having compactly supported initial data. One way of thinking about Equation 12 is that the particularly nice features of Minkowski space allows one to convert &#8220;decay in space at a fixed moment in time&#8221; to &#8220;decay in time at a fixed point in space&#8221;. By assuming lots and lots of decay in space, we get also lots and lots of decay in time. But any reduced decay in space will automatically translate to also a reduced decay in time. </p>
<p>(If there is no decay in space, there can also be no decay in time: observe that the constant function <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28t%2Cx%29+%3D+C&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;phi(t,x) = C' title='&#92;phi(t,x) = C' class='latex' /> is a solution to the homogeneous wave equation.)</p>
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		<pubDate>Tue, 10 May 2011 12:59:30 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[Uncategorized]]></category>
		<category><![CDATA[buzz]]></category>

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		<description><![CDATA[Allegedly one can link a blog to Google Buzz. And I am pretty sure it works, since Terry&#8217;s Buzz gets also his What&#8217;s New feed. But for the life of me I cannot get Google to realise that this blog is affiliated to my google profile. And I hate to admit defeat to technology. Filed [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=660&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://email.about.com/od/gmailtips/qt/Connect_Any_Site_and_RSS_Feed_to_Google_Buzz.htm">Allegedly one can link a blog to Google Buzz</a>. And I am pretty sure it works, since Terry&#8217;s Buzz gets also his <em>What&#8217;s New</em> feed. But for the life of me I cannot get Google to realise that this blog is affiliated to <a rel="me" href="http://www.google.com/profiles/willie.w.wong">my google profile</a>. </p>
<p>And I hate to admit defeat to technology. </p>
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		<title>Decay of waves I: Introduction</title>
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		<pubDate>Thu, 05 May 2011 18:59:45 +0000</pubDate>
		<dc:creator>Willie Wong</dc:creator>
				<category><![CDATA[general relativity]]></category>
		<category><![CDATA[Maths]]></category>
		<category><![CDATA[partial differential equations]]></category>
		<category><![CDATA[Require high school maths]]></category>
		<category><![CDATA[wave and Schroedinger equations]]></category>

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		<description><![CDATA[In the next week or so, I will compose a series of posts on the heuristics for the decay of the solutions of the wave equation on curved (and flat) backgrounds. (I have my fingers crossed that this does not end up aborted like my series of posts on compactness.) In this first post I [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=williewong.wordpress.com&amp;blog=8147335&amp;post=639&amp;subd=williewong&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>In the next week or so, I will compose a series of posts on the heuristics for the decay of the solutions of the wave equation on curved (and flat) backgrounds. (I have my fingers crossed that this does not end up aborted like my series of posts on compactness.) In this first post I will give some physical intuition of <em>why</em> waves decay. In the next post I will write about the case of linear and nonlinear waves on flat space-time, which will be used to motivate the construction, in post number three, of an example space-time which gives an upper bound on the best decay that can be generally expected for linear waves on non-flat backgrounds. This last argument, due to Mihalis Dafermos, shows that why the heuristics known as <em>Price&#8217;s Law</em> is as good as one can reasonably hope for in the linear case. (In the nonlinear case, things immediately get much much worse as we will see already in the next post.)</p>
<p>This first post will not be too heavily mathematical, indeed, the only realy foray into mathematics will be in the appendix; the next ones, however, requires some basic familiarity with partial differential equations and pseudo-Riemannian geometry.<span id="more-639"></span></p>
<p><strong>Dispersion and decay</strong></p>
<p>The wave equation, as its name suggests, describes the propagation of waves. In the context of the discussion here, the precise <em>nature</em> of the wave is unimportant: we don&#8217;t care so much whether the wave is longitudinal or transversal, we don&#8217;t need to know what the medium is that facilitates the wave propagation (or <a href="http://en.wikipedia.org/wiki/Luminiferous_aether">whether such a medium is necessary at all</a>), nor do we wonder about what caused the wave in the first place. These kinds of differences manifest themselves mathematically as internal nonlinear structures, and in the limit when the amplitude of the wave is vanishingly small, these nonlinear effects can be &#8220;safely disgarded&#8221; (not strictly true, see the next section). But as a concrete example to keep in the back of the mind, we could imagine ripples on the surface of a pond, or radio (electromagnetic) waves. </p>
<p>The important thing for the present discussion is that <em>waves disperse</em>. What do we mean by dispersion? Imagine dropping a pebble into an absolutely still pond. The ripples form concentric rings that spread out. That is dispersion. Visualise a radio beacon broadcasting a signal. The signal starts with high power at the source but spreads out spherically, attenuating with distance. That is dispersion. For contrast, imagine an ideal laser beam: the beam is perfectly collimated and the cross section area is the same 1 meter, 1 kilometer, or 1 lightyear away from the source. That is the lack of dispersion. </p>
<p>Very roughly speaking, dispersion is the tendency for the wave to occupy more and more area as it propagates. In the case of ripples on the pond, the measure of &#8220;area&#8221; is the circumference of the ripple. When the pebble is first dropped in, a high amplitude disturbance is created at the spot where the pebble hit the water. As time passes by, you get concentric ripples flowing outwards whose amplitude decreases as the radius of the ripples grow. </p>
<p>This decay in amplitude, as it turns out, is characteristic of dispersive systems. The reason underpinning this connecting between dispersion and decay is the fundamental principle of &#8220;conservation of energy&#8221; (see also the appendix to this post). The wave carries with it some finite amount of total energy, which, being conserved, can be computed at the initial time. As the support of the wave (where the disturbance is non-zero) spreads out, the energy has to be distributed among larger and larger area. This means that the energy density, being roughly the average of the total energy over the area in which the wave is non-zero, would decay over time. Converting from energy density back to amplitude, we see that a wave with conserved total energy that exhibits dispersive phenomenon must decay in time. (Note that this decay is &#8220;local&#8221; and is different from the decay associated from <em>dissipation</em> associated to friction, viscosity, or damping. In particular, to &#8220;globalize&#8221; this decay far into the future, we need the area covered by the wave to keep increasing in time. If the spatial domain has limited extent, then the maximum area supporting the wave also is limited. Imagine again the pebble in the pond. If the water were not viscuous at all, and there&#8217;s no mechanical loss to friction or heat in the fluid, then the ripples will eventually reach the shore and bounce back. After a long time the ripples and their reflections will cover the surface of the entire pond and then it won&#8217;t decay further in amplitude. Another example is the phenomenon of standing waves. Absent friction effects, standing waves have more-or-less constant amplitude, reflecting the constraint of bounded spatial domain.)</p>
<p>So what causes dispersion? In general it is best described as the tendency of a wave to decompose into components traveling with different velocities. There are generally two ways for this to happen. The first is a <em>one-dimensional</em> effect, where the wave is separated into components traveling at different speeds. It is like a footrace: all racers start at the same place (the starting line) and run in the same direction; but at the end of the race the racers are spreadout, with some reaching the finishline before others. Oftentimes this decomposition is based on the frequency of the wave. A striking illustration of this is the Newtonian experiment splitting light into the rainbow of colors. In the glass prism, different frequencies of light travel at different speeds. Coupled with Snell&#8217;s law, and the relation between refractive index and light speed, this forces white light, which is a blend of electromagnetic waves of different frequencies, to split up into separate components travelling at different speeds and angles. </p>
<p>The second dispersive effect is a <em>multi-dimensional</em> effect, where the wave is separated into components traveling in different directions. This is more akin to what we imagine on the surface of a pond, or of radio waves: the spreading out is because we have a bunch of little packets of energy going all in different directions. For systems satisfying the linear wave equation, this second dispersive effect is what causes decay. And thus a solution to the wave equation in one dimension (a wave traveling along a string) does not decay in amplitude. A system that also makes use of the first dispersive effect is the linear Schroedinger equation of quantum mechanics, for which the spreading out of the wave function, even in one spatial dimension, can be seens as a manifestation of the uncertainty principle. </p>
<p><strong>Scattering and tails</strong></p>
<p>Now imagine instead of a small pond, an absolutely still ocean of infinite extent. We drop a rock into it, and a ripple travel outward. It gets further and further away, and eventually disappears from sight: all the energy has been carried away by the wave and there is no disturbance left where the rock fell in. Now, however, imagine that our ocean is dotted with stone pillars that rises out of the water. Again we drop in a rock, the ripples flow outwards and suddenly it bumps into a pillar! Instead of continuing, the wave bounces off the pillar and flows outward from the pillar as if it were the center of the disturbance. This reflection of the wave off of obstacles is the first example of scattering. </p>
<p>In general, scattering does not have to be due to &#8220;hard&#8221; obstacles like the pillars in the ocean. Reflection can also happen across transition boundaries between two media. A good example is exhibited by one-way mirrors. At the boundary between glass and air (or metal coating and air), an incoming electromagnetic wave is partially reflected and partially transmitted. When one side of the glass is much brighter than the other, the intensity of the reflected light, when viewed from the bright side, albeit weak, is still stronger than the intensity of the light transmitted from the dark side. Whereas from the dark side the light transmitted through the glass from the bright side is much brighter than the light reflected from within the dark room. This type of scattering doesn&#8217;t have to be across a discontinuous boundary either. In general one will expect some sort of back scattering of waves when the medium itself is not homogeneous. </p>
<p>As already seen in the case with the stone pillars in the ocean, the phenomenon of back scattering will cause waves which &#8220;ought of have left the area&#8221; to remain. In the extreme case, where the entire medium is encased in reflective material (a pond of finite extent, a radio wave guide), we will have non-decay of the wave, in spite of the dispersive effects. In the intermediate regime, the wave will still (mostly) escape when given long enough time, but this remnant from back scattering will cause the associated decay to be slower than one may have predicted using a purely local description coming from studying a homogeneous medium. This is what we call a <em>tail</em>. </p>
<p><strong>Appendix: two &#8220;derivations&#8221; of the wave equation</strong></p>
<p>Let <img src='http://s0.wp.com/latex.php?latex=%5CPhi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi' title='&#92;Phi' class='latex' /> be the function that describes the wave amplitude. One can think of it as, for example, the vertical displacement, as a function of position <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> and time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t' title='t' class='latex' />, of a horizontally held elastic membrane (say a drum head). </p>
<p><em>The Newtonian picture</em>. In this picture, the basic idea is the restorative force. Recall Newton&#8217;s second law, which states that the acceleration experienced by a mass is proportional to the force acting on it. Or in notation, <img src='http://s0.wp.com/latex.php?latex=%5Cddot%7BPhi%7D%28t%2Cx%29+%3D+f%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;ddot{Phi}(t,x) = f(t,x)' title='&#92;ddot{Phi}(t,x) = f(t,x)' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=f%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='f(t,x)' title='f(t,x)' class='latex' /> is the function representing the force per unit mass experienced at position <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> and time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='t' title='t' class='latex' />. For wave motion, we <em>postulate</em> that the restorative force is proportional to &#8220;how much more displaced the particle at position <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> is, when compared against its immediate neighbors&#8221;. This latter quantity can be mathematically described as the difference between <img src='http://s0.wp.com/latex.php?latex=%5CPhi%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi(x)' title='&#92;Phi(x)' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Cbar%7B%5CPhi%7D%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;bar{&#92;Phi}(x)' title='&#92;bar{&#92;Phi}(x)' class='latex' />, the average of <img src='http://s0.wp.com/latex.php?latex=%5CPhi%28x%2By%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi(x+y)' title='&#92;Phi(x+y)' class='latex' /> over a small ball <img src='http://s0.wp.com/latex.php?latex=%7Cy%7C+%5Cleq+%5Cepsilon&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='|y| &#92;leq &#92;epsilon' title='|y| &#92;leq &#92;epsilon' class='latex' />. Taking the multivariable Taylor expansion of <img src='http://s0.wp.com/latex.php?latex=%5CPhi%28x%2By%29+%3D+%5CPhi%28x%29+%2B+y%5Ccdot+%5Cnabla+%5CPhi%28x%29+%2B+%5Cfrac%7B1%7D%7B2%7Dy%5Ccdot+%5Cleft%28%5Cnabla%5E2+%5CPhi%28x%29%5Cright%29%5Ccdot+y+%2B+%5Cldots&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi(x+y) = &#92;Phi(x) + y&#92;cdot &#92;nabla &#92;Phi(x) + &#92;frac{1}{2}y&#92;cdot &#92;left(&#92;nabla^2 &#92;Phi(x)&#92;right)&#92;cdot y + &#92;ldots' title='&#92;Phi(x+y) = &#92;Phi(x) + y&#92;cdot &#92;nabla &#92;Phi(x) + &#92;frac{1}{2}y&#92;cdot &#92;left(&#92;nabla^2 &#92;Phi(x)&#92;right)&#92;cdot y + &#92;ldots' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=%5Cnabla%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;nabla^2' title='&#92;nabla^2' class='latex' /> is the Hessian operator, we compute its average on a small ball. Notice that for all <em>odd</em> terms (meaning a function <img src='http://s0.wp.com/latex.php?latex=g&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g' title='g' class='latex' /> such that there exists a hyperplane with <img src='http://s0.wp.com/latex.php?latex=g%28y%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='g(y)' title='g(y)' class='latex' /> being the negative of its reflection across the plane), the average must be zero. So up to second order, the only terms that contribute to the average is <img src='http://s0.wp.com/latex.php?latex=%5CPhi%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi(x)' title='&#92;Phi(x)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D%7Cy%7C%5E2+%5Ctriangle+%5CPhi%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{1}{2}|y|^2 &#92;triangle &#92;Phi(x)' title='&#92;frac{1}{2}|y|^2 &#92;triangle &#92;Phi(x)' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Ctriangle&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;triangle' title='&#92;triangle' class='latex' /> denotes the Laplacian operator. So taking the difference between <img src='http://s0.wp.com/latex.php?latex=%5CPhi%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi(x)' title='&#92;Phi(x)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cbar%7B%5CPhi%7D%28x%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;bar{&#92;Phi}(x)' title='&#92;bar{&#92;Phi}(x)' class='latex' />, we have that the restorative force is proportional to <img src='http://s0.wp.com/latex.php?latex=%5Ctriangle_x+%5CPhi%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;triangle_x &#92;Phi(t,x)' title='&#92;triangle_x &#92;Phi(t,x)' class='latex' />, where I put the subscript on the Laplacian operator to remind ourselves that the Laplacian is with respect to the spatial variables. Lastly, we need to know the constant of proportionality. In general this is determined by the media in question, as well as by the units of measurement. However, we can determine the <em>sign</em> of proportionality constant. If a point <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='x' title='x' class='latex' /> is <em>more</em> (positively) displaced than all its neighbors, it is a local maximum, and so its second derivative, and hence its Laplacian, must be negative. Since the force is restorative, it will need to point in the negative direction also, and so we have that tha proportionality constant has a positive sign. That is, the prototype of the wave equation is</p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cddot%7B%5CPhi%7D%28t%2Cx%29+%3D+k%5E2+%5Ctriangle_x+%5CPhi%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;ddot{&#92;Phi}(t,x) = k^2 &#92;triangle_x &#92;Phi(t,x)' title='&#92;ddot{&#92;Phi}(t,x) = k^2 &#92;triangle_x &#92;Phi(t,x)' class='latex' />
</p></blockquote>
<p><em>The Hamiltonian picture</em>. Here, we do the same derivation, but using as our guide, instead of Newton&#8217;s second law of motion, the law of conservation of energy. For a closed system, we must have that the sum of kinetic and potential energies is constant over time. But for an open system, the total energy can change by taking in or expelling a flux through the boundary of the system. Infinitesimally, this is described by the equation <img src='http://s0.wp.com/latex.php?latex=%5Cdot%7Be%7D%28t%2Cx%29+%3D+%5Cnabla%5Ccdot+j%28t%2Cx%29&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;dot{e}(t,x) = &#92;nabla&#92;cdot j(t,x)' title='&#92;dot{e}(t,x) = &#92;nabla&#92;cdot j(t,x)' class='latex' />. Here <img src='http://s0.wp.com/latex.php?latex=e&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='e' title='e' class='latex' /> is the energy density, <img src='http://s0.wp.com/latex.php?latex=j&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j' title='j' class='latex' /> is the energy flux vector, and $\nabla\cdot$ the vector divergence, and the Hamitonian picture reduces to the specification of what are the constitutive equations (or equations of state) which tell us how <img src='http://s0.wp.com/latex.php?latex=e&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='e' title='e' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=j&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j' title='j' class='latex' /> can be computed from the displacement <img src='http://s0.wp.com/latex.php?latex=%5CPhi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;Phi' title='&#92;Phi' class='latex' />. </p>
<p>To compute the energy density, we observe that the kinetic energy will take the form <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D%5Cmu+%5Cdot%7B%5CPhi%7D%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{1}{2}&#92;mu &#92;dot{&#92;Phi}^2' title='&#92;frac{1}{2}&#92;mu &#92;dot{&#92;Phi}^2' class='latex' /> as usual, coming from the velocity of each point of the medium. The potential energy we will assume is given by Hooke&#8217;s Law, which in infinitesimal form implies <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D%5Ckappa+%7C%5Cnabla%5CPhi%7C%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{1}{2}&#92;kappa |&#92;nabla&#92;Phi|^2' title='&#92;frac{1}{2}&#92;kappa |&#92;nabla&#92;Phi|^2' class='latex' />. (We can again use the Taylor expansion to arrive at this: for a spring, Hooke&#8217;s law gives potential energy <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D%5Ckappa+d%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{1}{2}&#92;kappa d^2' title='&#92;frac{1}{2}&#92;kappa d^2' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=d&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='d' title='d' class='latex' /> is the displacement from equilibrium. We can now compute the average over a small ball of <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B2%7D%5Ckappa+%28%5CPhi%28x%2By%29+-+%5CPhi%28x%29%29%5E2&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;frac{1}{2}&#92;kappa (&#92;Phi(x+y) - &#92;Phi(x))^2' title='&#92;frac{1}{2}&#92;kappa (&#92;Phi(x+y) - &#92;Phi(x))^2' class='latex' /> to give the potential energy for the wave.) <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' /> is the mass density and <img src='http://s0.wp.com/latex.php?latex=%5Ckappa&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;kappa' title='&#92;kappa' class='latex' /> is the analogue of the spring constant. For the energy flux, it is well known that the energy transfered to/from a moving particle is given by the product of the force acting on the particle and its velocity. Using Hooke&#8217;s law again, we then have <img src='http://s0.wp.com/latex.php?latex=j+%3D+%5Ckappa+%5Cdot%7B%5CPhi%7D%5Cnabla%5CPhi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='j = &#92;kappa &#92;dot{&#92;Phi}&#92;nabla&#92;Phi' title='j = &#92;kappa &#92;dot{&#92;Phi}&#92;nabla&#92;Phi' class='latex' />. Plugging everything into the conservation law, we end up with (after some cancelling of terms on the left and right hand sides), </p>
<blockquote><p>
<img src='http://s0.wp.com/latex.php?latex=%5Cmu+%5Cdot%7B%5CPhi%7D+%5Cddot%7B%5CPhi%7D+%3D+%5Ckappa+%5Cdot%7B%5CPhi%7D+%5Ctriangle_x%5CPhi&amp;bg=ffffff&amp;fg=000000&amp;s=0' alt='&#92;mu &#92;dot{&#92;Phi} &#92;ddot{&#92;Phi} = &#92;kappa &#92;dot{&#92;Phi} &#92;triangle_x&#92;Phi' title='&#92;mu &#92;dot{&#92;Phi} &#92;ddot{&#92;Phi} = &#92;kappa &#92;dot{&#92;Phi} &#92;triangle_x&#92;Phi' class='latex' />
</p></blockquote>
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